MCAT Physical : Forces

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

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Example Question #71 : Forces

A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a radius of 0.25m. The other end of the rope is attached to a massless suspended platform, upon which 0.5kg weights may be placed. While the system is initially at equilibrium, the rope is later cut above the weight, and the platform subsequently raised by pulling on the rope.

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If, instead of using one pulley to raise the platform after it falls, we decided to use two, how would the force required to lift the platform change?

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Possible Answers:

Increase by 1/2

Decrease by 4 times

Decrease by 1/2

Increase by 4 times

Correct answer:

Decrease by 1/2

Explanation:

One-half of the force will be required to pull the platform up in the new scenario. In the diagram below, now notice that the box has two upward tension forces due to the pulley attached directly to the box. These two tension forces act against the weight of the box, meaning that each tension force is one half of the weight of the box. Because tension is transmitted unchanged over the length of the rope, the tension a person would need to pull against would be half the weight of the box. This leads us to determine that half the force would be required to lift the box if two pulleys were used.

Screen_shot_2013-10-09_at_10.40.14_pm

Example Question #72 : Forces

Two students (student X and student Y) lift a boulder vertically from point A to point B. Student X directly lifts the boulder from point A to point B, whereas student Y uses a pulley to lift the boulder. This allows student Y to apply a force () that is three times smaller than the force applied by student X (). Both students apply force upwards and take the same amount of time to complete this task.

The vertical distance between point A and point B is .

Student Z uses a frictionless inclined plane to lift the boulder and has to apply only a third of . Which of the following is true regarding the inclined plane and the pulley (used by Student Y)?

Possible Answers:

The pulley has a greater mechanical advantage than the inclined plane

The inclined plane has a greater mechanical advantage than the pulley

The pulley and the inclined plane have the same mechanical advantage

More information is required to determine the relative mechanical advantage

Correct answer:

The pulley and the inclined plane have the same mechanical advantage

Explanation:

The question states that:

Recall that the passage states that  is also one third of .

The force exerted by student Y and student Z is the same.

Mechanical advantage is defined as:

The weight of the object is the same for both students because both of them are lifting the same boulder. The force applied is also the same; therefore, mechanical advantage for both machines is the same.

Example Question #73 : Forces

Two students (student X and student Y) lift a boulder vertically from point A to point B. Student X directly lifts the boulder from point A to point B, whereas student Y uses a pulley to lift the boulder. This allows student Y to apply a force () that is three times smaller than the force applied by student X (). Both students apply force upwards and take the same amount of time to complete this task.

The vertical distance between point A and point B is .

If the pulley has a mechanical advantage of  and , what is the weight of the boulder?

Possible Answers:

Correct answer:

Explanation:

The definition of mechanical advantage is:

Rearranging this equation and solving for weight gives:

Mechanical advantage is a unitless quantity. Remember the difference between weight and mass. Weight is a measure of force and has units of Newtons, whereas mass has units of kilograms.

Example Question #71 : Forces

A 2kg object falls from a height of 3m onto a spring, which compresses 20cm. What is the spring constant?

Possible Answers:

Correct answer:

Explanation:

Conservation of energy is the key here. Initial energy is all gravitational potential energy:

 

Note that the final height change is equal to the height above the spring added to the displacement of the spring.

This is equal to the final energy, which is all spring potential energy:

Set these equations equal and solve for the spring constant.

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