Linear Algebra : Operations and Properties
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Example Questions
Example Question #11 : Eigenvalues And Eigenvectors Of Symmetric Matrices
Example Question #12 : Eigenvalues And Eigenvectors Of Symmetric Matrices
where 
For 
Any real value of 
Example Question #13 : Eigenvalues And Eigenvectors Of Symmetric Matrices
Give the set of eigenvalues of 
The only eigenvalue is 0.
The eigenvalues are 
The eigenvalues are 0 and 
The eigenvalues are 0 and 
The only eigenvalue is 
The eigenvalues are 0 and
An eigenvalue of 
Subtracting elementwise:
Set the determinant to 0 and solve for 
The determinant can be found by taking the upper-left-to-lower-right product and subtracting the upper-right-to-lower-left product:
so the eigenvalues of this matrix are 0 and 
Example Question #861 : Linear Algebra
That last question dealt with isomorphism. This question is meant to point out the difference between isomorphism and homomorphisms.
A homomorphism is a mapping between vector spaces that
Preserves vector addition and is injective
onto and 1-to-1
Preserves scalar multiplication and is onto
Preserves vector addition and scalar multiplication
Preserves vector addition and scalar multiplication
By definition a homomorphism is a mapping that preserves vector addition and scalar multiplication.
Compare this to the previous problem. An isomorphism is a homomorphism that is also 1-to-1 and onto. Therefore isomorphism is just a special homomorphism. In other words, every isomorphism is a homomorphism, but not all homomorphisms are an isomorphisms.
Example Question #862 : Linear Algebra
Consider the mapping 
(Hint: Think about dimension's role in isomorphism)
No
Yes
not enough information
No
No, f, cannot be an isomorphism. This is because 
Example Question #863 : Linear Algebra
Isomorphism is an important concept in linear algebra. To be able to tell if a mapping is isomorphic, it is important to be able to know what an isomorphism is.
Let f be a mapping between vector spaces V and W. Then a mapping f is an isomorphism if it is
Onto (surjective)
Preserves vector addition
1-to-1 (injective)
Preserves scalar multiplcation
All answers.
All answers.
An isomorphism is homomorphism (preserves vector addition and scalar multiplcation) that is bijective (both onto and 1-to-1). Therefore an isomorphism is a mapping that is
1) onto
2) 1-to-1
3) Preserves vector addition
4) Preserves scalar multiplcation
Example Question #4 : Linear Mapping
In the previous question, we said an isomorphism cannot be between vector spaces of different dimension. But are all homomorphisms between vector spaces of the same dimension an isomorphism?
Consider the homomorphism 
Not enough information
Yes
No
Not enough information
The answer is not enough information. The reason is that it could be an isomorphism because it is between vector spaces of the same dimension, but that doesn't mean it is.
For example:
Consider the zero mapping f(x,y)= (0,0).
This mapping is not onto or 1-to-1 because all elements go to the zero vector. Therefore it is not an isomorphism even though it is a mapping between spaces with the same dimension.
Another example:
Consider the identity mapping f(x,y) = (x,y)
This is an isomorphism. It clearly preserves structure and is both onto and 1-to-1.
Thus f could be an isomorphism (example identity map) or it could NOT be an isomorphism ( Example the zero mapping)
Example Question #5 : Linear Mapping
Let f be a mapping such that
Let f be defined such that
Is f 1-to-1 and onto?
No, it is not 1-to-1 but it is onto
No, it is 1-to-1 and not onto
No, it is not 1-to-1 and not onto
Yes
No, it is not 1-to-1 and not onto
f is not 1-to-1 and it is not onto.
f is not onto because all of 
f is not 1-to-1. For example, the vector (1,1) and (1,0) both go to the same vector.
Ie f(1,1) = f(1,0). Therefore f is not 1-to-1.
Example Question #864 : Linear Algebra
Let f be a mapping such that
Let f be defined such that
Is f an isomorphism?
(Hint: Consider the zero vector)
Yes
No, it is not a homomorphism
No, it is not 1-to-1
No, it is not onto
No, it is not a homomorphism
f is 1-to-1 and onto but it is not a homomorphism. Therefore it is not an isomorphism. To see this consider f(0,0) = (0,5)
A homomorphism always takes the zero vector to the zero vector. This particular mapping does not. Thus it does not preserve structure ie not a homomorphism.
Example Question #7 : Linear Mapping
The last question showed us isomorphisms must be between vector spaces of the same dimension. This question now asks about homomorphisms.
Consider the mapping 
No
not enough information
Yes
Yes
The answer is yes. There is no restriction on dimension for homomorphism like there is for isomorphism. Therefore f could be a homomorphism, but it is not guaranteed.
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