The perimeter of a parallelogram is two times the two side lengths and add them together.  

\(\displaystyle \\P=s_1+s_2+s_3+s_4 \\s_1=s_3 \\s_2=s_4 \\P=s_a+s_a+s_b+s_b \\P=2s_a+2s_b\)

Therefore, this particular problem becomes as follows.

\(\displaystyle 2*7=14\) 

and 

\(\displaystyle 2*3=6\) 

so 

\(\displaystyle 14+6=20\).

The perimeter of the parallelogram is the sum of the four side lengths - here, that formula becomes

\(\displaystyle P = a + b + a + b = 18 + 26 + 18 + 26 = 88\).

Note that the height \(\displaystyle h\) is irrelevant to the answer.

The base of the parallelogram is 10, while the height is 5.

\(\displaystyle A=b\times h\)

\(\displaystyle A=10\times5=50\: in^2\)

The area of a parallelogram can be determined using the following equation:

\(\displaystyle \small A=bh\)

Therefore,

\(\displaystyle \small A=8\times3=24\)

The area of a parallelogram is found by computing \(\displaystyle base * height\).  In this situation, you would have the base which is the bottom side but you would not have the height measurement.  Since you would not be able to solve for the area with just the side lengths, the statement is \(\displaystyle FALSE\).

To find the area of a parallelogram, you use the formula,

 \(\displaystyle A=base*height\).  

Since the height in this problem is not known, you cannot solve for area.

To find the area of a parallelogram, we will use the following formula:

\(\displaystyle \text{area of a parallelogram} = b \cdot h\)

where b is the base and h is the height of the parallelogram.

Now, we know the base has a length of 6 inches. We also know it has a height of 9 inches.  Knowing this, we can substitute into the formula.  We get

\(\displaystyle \text{area of a parallelogram} = 6\text{in} \cdot 9\text{in}\)

\(\displaystyle \text{area of a parallelogram} = 54\text{in}^2\)

Write the area formula of a parallelogram.

\(\displaystyle A=bh\)

Substitute the dimensions into the formula.

\(\displaystyle A=6(15) = 90\)

The answer is:  \(\displaystyle 90\)

The coordinates of a point are determined by the distance from the origin. The first point in the ordered pair is the number of units to the left or right of the origin. Negative numbers indicate the number of units to the left while positive numbers indicate the number of units to the right. The second number indicates the number of units above or below the origin. Positive numbers indicate the number of units above while negative numbrs indicate the number of units below the origin. The vertices of the square are:
\(\displaystyle \small (-1,2); (-1,4); (1,2); (-1,4)\)

A point is located on the \(\displaystyle y\)-axis if and only if it has \(\displaystyle x\)-coordinate (first coordinate) 0. Of the five choices, only \(\displaystyle (0,-30)\) fits that description.