If 10 percent of puppies are born with spots, and of those, 50 percent have black spots, then the total percent of puppies who have spots AND the color of the spots is black can be found by multiplying the two percentages by one another:

0.05 is the equivalent of 5 percent, the correct answer. 

There are 10 total participants in the raffle.

288, 289, 290, 291, 292, 292, 294, 295, 296, 297

Only 2 participants have tickets with numbers that beging in 2 and 8.; therefore, Jenny has a 50 percent chance of holding the winning raffle ticket.

The winner is either 288 or 289, leaving Jenny a 50 percent chance. 

If each boy gets 7 raffle tickets, that means that each girl gets 14 raffle tickets. 

Therefore, Tracy will have 14 raffle tickets, and the total number of raffle tickets will be equal to . 

Thus, Tracy's chance of winning will be equal to:

Whenever an even number is added to an odd number, the result is odd. Whenever an even number is added to an even number, the result is even. 

Given that all the numbers in set  are even, there is a 100 percent chance of an even number being selected; however in set , one of the three numbers is odd, so there is a one third chance of an odd number being selected. 

Given that the sum of an even number and an odd number is odd, there is a probability of  that the sum of a number randomly selected from set  and from set  wil be an odd number. 

The only way in which a negative number would be acheived by subtracting  is if  was equal to 2, and any number was selected for . 

Therefore, the chance of  resulting in a negative number would be equal to the odds of selecting 2 from set . Given that there are four numbers in set , there is a one fourth chance. 

Thus, the correct answer is .

The only way that a product of  will be acheived is if the number  is selected from set , and the number  is selected from set . 

There is a one half chance of the number 4 being selected and a one half chance of the number 6 being selected, given that each set contains two numbers. 

Therefore, the probability of both these number being chosen is:

If Mark flips a coin, the chance that it will land on heads is . On a die, there are 2 out of 6 numbers that are a multiple of 3 (3 and 6); therefore, there is a  chance that the dice will be a multiple of 3. 

The probability that the coin will land on heads and that the dice will be a multiple of 3 is:

Given that there are six values that a die may show when rolled, there is a  chance that either dice will show a value of 1. Thus, the chance that both dice will show a value of 1 is equal to , which is equal to .

Thus,  is the correct answer. 

Since a coin toss is an independent event (no other events affect its outcomes), the probability of getting a heads on a toss will always be .

There are  cards in a deck.  

There are four suits of cards including spades.  

They make up an even amount of the deck each.  

Since there are four of the suits, each represent  of the deck and that is the probability of drawing one.