To find the area of the figure above, we need to split the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=7\times 5$            $\displaystyle A=6\times 4$

$\displaystyle A=35in^2$           $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 35in^2+24in^2=59in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=6\times 2$            $\displaystyle A=5\times 2$

$\displaystyle A=12in^2$           $\displaystyle A=10in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 12in^2+10in^2=22in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=7\times 2$            $\displaystyle A=6\times 3$

$\displaystyle A=14in^2$           $\displaystyle A=18in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 14in^2+18in^2=32in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=9\times 8$            $\displaystyle A=8\times 3$

$\displaystyle A=72in^2$           $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 72in^2+24in^2=96in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=4\times 6$            $\displaystyle A=4\times 2$

$\displaystyle A=24in^2$           $\displaystyle A=8in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 24in^2+8in^2=32in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=5\times 5$            $\displaystyle A=3\times 3$

$\displaystyle A=25in^2$           $\displaystyle A=9in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 25in^2+9in^2=34in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=4\times 2$            $\displaystyle A=9\times 4$

$\displaystyle A=8in^2$           $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 8in^2+36in^2=44in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=3\times 3$            $\displaystyle A=11\times 2$

$\displaystyle A=9in^2$           $\displaystyle A=22in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 9in^2+22in^2=31in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=8\times 5$            $\displaystyle A=6\times 4$

$\displaystyle A=40in^2$           $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 40in^2+24in^2=64in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=2\times 12$            $\displaystyle A=2\times 2$

$\displaystyle A=24in^2$           $\displaystyle A=4in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 24in^2+4in^2=28in^2$