ISEE Lower Level Math : Operations

Study concepts, example questions & explanations for ISEE Lower Level Math

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Example Questions

Example Question #61 : Operations

Mindy bought a box of \displaystyle 5 granola bars for \displaystyle \$2.50. She sold each bar for \displaystyle \$1.00. If Mindy sold all \displaystyle 5 bars, how much of a profit would she make in dollars?

Possible Answers:

\displaystyle \$0.50

\displaystyle \$0.25

\displaystyle \$5.00

\displaystyle \$2.50

Correct answer:

\displaystyle \$2.50

Explanation:

If the box of \displaystyle 5 granola bars was \displaystyle \$2.50, this means that each granola bar cost \displaystyle \$0.50 because \displaystyle \$2.50 divided by \displaystyle 5 is \displaystyle \$0.50

If Mindy then sold each granola bar for \displaystyle \$1.00, the profit per bar would be \displaystyle \$1.00 minus the \displaystyle \$0.50 cost of the bar, which is equal to \displaystyle \$0.50

If she sold all \displaystyle 5 granola bars, then she would have made a profit of \displaystyle \$0.50\cdot5, which is \displaystyle \$2.50.

Example Question #223 : Isee Lower Level (Grades 5 6) Mathematics Achievement

Maria makes jewelry with beads. She can make a pair of earrings with \displaystyle 4 beads, a bracelet with \displaystyle 10 beads, and a necklace with \displaystyle 20 beads. If Maria has \displaystyle 120 beads, which of the following could she make?

Possible Answers:

\displaystyle 20 necklaces

\displaystyle 30 pairs of earrings

\displaystyle 13 bracelets

\displaystyle 11 bracelets and \displaystyle 3 pairs of earrings

Correct answer:

\displaystyle 30 pairs of earrings

Explanation:

Given that each pair of earrings requires \displaystyle 4 beads, the number of beads that \displaystyle 30 pairs of earrings would require is equal to:

\displaystyle 4\cdot30=120

Since Maria has \displaystyle 120 beads, she has a sufficient number of beads to make \displaystyle 30 earrings. The other jewelry arrangements will result in there being a shortage of beads: Maria would need \displaystyle 400 beads to make \displaystyle 20 necklaces (\displaystyle 20\cdot20=400), \displaystyle 130 beads to make \displaystyle 13 bracelets (\displaystyle 13\cdot10=130), and \displaystyle 122 beads to make \displaystyle 11 bracelets and \displaystyle 3 pairs of earrings (\displaystyle (11*10)+(3*4)=110+12=122).

Example Question #222 : Isee Lower Level (Grades 5 6) Mathematics Achievement

The cost for two people to be part of a tennis club is \displaystyle \$20 a month. If Jon and Marie share the annual cost of the club membership, how much does each person have to pay per year?

Possible Answers:

\displaystyle \$60

\displaystyle \$120

\displaystyle \$240

\displaystyle \$180

Correct answer:

\displaystyle \$120

Explanation:

If the cost of being part of a tennis club for two people is \displaystyle \$20 a month, that means the annual cost for two people will be \displaystyle 12\cdot\$20=\$240

If two people share this cost, that means that each person will have to pay \displaystyle \$120 because half of \displaystyle \$240 is \displaystyle \$120

Therefore, the correct answer is \displaystyle \$120.

Example Question #61 : Operations

On average, Lisa sends twelve emails a day. How many emails would she send in a week if she sent her average number of emails every day of the week?

Possible Answers:

\displaystyle 60

\displaystyle 70

\displaystyle 82

\displaystyle 84

Correct answer:

\displaystyle 84

Explanation:

If Lisa sends an average of \displaystyle 12 emails a day and sends emails over a course of \displaystyle 7 days, that means that the total number of emails that she sends will be equal to \displaystyle 12\cdot7=84. Therefore, the correct answer is \displaystyle 84.

Example Question #62 : How To Multiply

Andrew recorded a song with his band that is \displaystyle 2 minutes and \displaystyle 15 seconds long. \displaystyle \frac{3}{5} of the way into the song, he begins a drum solo. For how long does the song play before the solo begins?

Possible Answers:

\displaystyle 1 minute

\displaystyle 2 minutes and \displaystyle 21 seconds

\displaystyle 1 minute and \displaystyle 15 seconds

\displaystyle 1 minute and \displaystyle 21 seconds

Correct answer:

\displaystyle 1 minute and \displaystyle 21 seconds

Explanation:

If a song is \displaystyle 2 minutes and \displaystyle 15 seconds long, this is the equivalent of being \displaystyle 135 seconds long. (\displaystyle 2 minutes is equal to \displaystyle 120 seconds and \displaystyle 120+15=135.)

\displaystyle \frac{1}{5} of \displaystyle 135 is \displaystyle 27 because \displaystyle \frac{1}{5}\cdot \frac{135}{1}=\frac{135}{5}=27. Therefore, \displaystyle \frac{3}{5} of \displaystyle 135 is equal to \displaystyle 3*27=81. Therefore, \displaystyle 81 seconds (or \displaystyle 1 minute and \displaystyle 21 seconds) will go by before the drum solo begins. 

Example Question #231 : Isee Lower Level (Grades 5 6) Mathematics Achievement

Anita owns a store. She buys twenty sweaters for \displaystyle \$15.00 each and sells them for \displaystyle \$25.00 each. If she sells all of the twenty sweaters that she bought, how much profit will she earn in dollars?

Possible Answers:

\displaystyle \$200.00

\displaystyle \$100.00

\displaystyle \$2,000.00

\displaystyle \$220.00

Correct answer:

\displaystyle \$200.00

Explanation:

If Anita buys twenty sweaters for \displaystyle \$15.00 each and sells them for \displaystyle \$25.00 each, this means that she makes \displaystyle \$10.00 profit per sweater. If she sells \displaystyle 20 sweaters, the profit that she makes will be \displaystyle 20\cdot\$10.00, which is equal to \displaystyle \$200.00

Example Question #62 : Operations

Find the product of \displaystyle 12 and \displaystyle 5.

Possible Answers:

\displaystyle 2.4

\displaystyle 0.417

\displaystyle 17

\displaystyle 60

\displaystyle 7

Correct answer:

\displaystyle 60

Explanation:

Find the product of two numbers by multiplying them together. \displaystyle 12 \times 5 = 60, so the correct answer is \displaystyle 60.

Example Question #63 : Operations

Find the product of:

\displaystyle -9\times27

Possible Answers:

\displaystyle 234

\displaystyle 243

\displaystyle -243

\displaystyle -252

\displaystyle -234

Correct answer:

\displaystyle -243

Explanation:

When multiplying one negative factor with one positive factor the product will always be negative. 

Thus, the solution is:

\displaystyle -9\times27=-243

Example Question #64 : Operations

Find the product of:

\displaystyle -36\times-6

Possible Answers:

\displaystyle -216

\displaystyle 108

\displaystyle 216

\displaystyle 246

\displaystyle -108

Correct answer:

\displaystyle 216

Explanation:

When multiplying two negative factors the product will always be positive. 

Thus, the solution is:

\displaystyle -6\times-36=216

Example Question #65 : Operations

Find the product of:

\displaystyle -25\times15

Possible Answers:

\displaystyle -325

\displaystyle -375

\displaystyle 325

\displaystyle 375

\displaystyle -485

Correct answer:

\displaystyle -375

Explanation:

When multiplying one negative factor with one positive factor the product will always be negative. 

Thus, the solution is:

\displaystyle -25\times15=-375

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