Find the area of the wall - \(\displaystyle \dpi{100} 12\times 20=240\)

Divide \(\displaystyle \dpi{100} 240\div 40=6\)

6 cans of paint. 

To find the area of a rectangle, multiply the length by the width.

\(\displaystyle \small 5\times25=125\)

The area of a rectangle is found by multiping the length times the width. Given that the length is 3 feet, the width is 2 feet, the total cubic area would be found using this equation:

\(\displaystyle \text{length}\times \text{width} = \text{area}\)

Here is the equation with the appropriate numbers plugged in from the question:

\(\displaystyle 3\ \text{ft}\times2\ \text{ft}=6\ \text{ft}^2\)

6 square feet, or \(\displaystyle 6\ \text{ft}^2\) is the correct answer. 

If Jen's blanket is half as big as Leslie's blanket, and Leslie's blanket is \(\displaystyle 14\ \text{ft}^2\), then we need to divide by 2 to find the area of Jen's blanket.

\(\displaystyle 14\ \text{ft}^2\div2=7\ \text{ft}^2\)

The area of Jen's blanket is \(\displaystyle 7\ \text{ft}^2\).

The area of a rectangle is calculated by multiplying length times width.

\(\displaystyle A=l\times w\)

Given that the width is 6 feet and the height is 7, the product of 6 and 7 is 42.

\(\displaystyle A=6\ \text{ft}\times 7\ \text{ft}\)

\(\displaystyle A=42\ \text{ft}^2\)

Therefore, 42 is the correct answer. 

The area of a rectangle is equal to the width multiplied by the length, or:

\(\displaystyle A=l\times w\)

If the area of a rectangle is 28 inches and the width is 4 inches, then plugging this into the equation we would get:

\(\displaystyle 28=l\times4\)

\(\displaystyle 28=4l\)

Divide both sides by 4 to solve.

\(\displaystyle 28\div4=4l\div4\)

\(\displaystyle 7=l\)

If the area of the rectangle is 18, that means that the length and the width, when multiplied together, should equal 18.

\(\displaystyle A=l\times w=18\)

The only numbers from the answer choices that would result in the product of 18 are 9 by 2, which is therefore the correct answer. 

\(\displaystyle l=9,\ w=2\)

\(\displaystyle 9\times2=18\)

The area of a rectangle is the width times the length.

\(\displaystyle A=w\times l\)

The width is 4 feet and the length is 6 feet. Because 4 times 6 is 24, the area is 24 square feet. 

\(\displaystyle A=4\text{ft}\times6\text{ft}\)

\(\displaystyle A=24\ \text{ft}^2\)

The area of a rectangle is the width times the length.

\(\displaystyle A=w\times l\)

Given that the area is 20 square feet and the length is 5 feet, the width would have to be 4 feet because 5 times 4 is 20.

\(\displaystyle 20\text{ft}^2=w\times5\text{ft}\)

\(\displaystyle w=\frac{20\text{ft}^2}{5\text{ft}}=4\text{ft}\)

Given that the question asks for the width in inches, 4 should be multiplied by 12 (as there are 12 inches in a foot).

\(\displaystyle 4\text{ft}\times12\text{inches per foot}=48\text{in}\)

This gives us a product of 48 inches, which is the width. 

The area of a rectangle is found by multiplying the length by the width. Given that the length is 2r and that the length is 3w, the area will be the product of those numbers, which is \(\displaystyle 6rw\).