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ISEE Lower Level Math : Plane Geometry

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Example Questions

Example Question #53 : Geometry

Isee rect.

Find the area of the rectangle shown above.

Possible Answers:

158ft^2

200ft^2

180 ft^2

58ft^2

90ft^2

Correct answer:

180 ft^2

Explanation:

To find the area of a rectangle apply the formula:

$Area= Width\times Length$

The image provides the measurements for both the width and length of the rectangle.

Thus, the solution is:

$Area=20\times9=180$

Tip for mental math: Since you are multiplying times a multiple of ten, you can think of these factors as:

$2\times9=18$ and then tack on one zero to the product because the orginal factors have a total of one zero--which equals a product of 180 .

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Example Question #61 : Geometry

A rectangle has a length of . The width of the rectangle is $\frac{1}{5}$ that of the length measurement. Find the area of the rectangle.

Possible Answers:

490

245

250

Correct answer:

245

Explanation:

To solve this problem, first note that the width of the rectangle must equal:

$35\times \frac{1}{5}=\frac{35}{5}=7$

Now that you know the width and length of the rectangle, apply the area formula:

$Area=Width\times Length$

$Area=35\times 7= 245$

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Example Question #41 : Plane Geometry

A rectangle has a width of 26mm and a length of 23mm. Find the area of the rectangle.

Possible Answers:

598 mm^2

460mm^2

698mm^2

189mm^2

98mm^2

Correct answer:

598 mm^2

Explanation:

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Example Question #42 : Plane Geometry

Isee rect.

Find the area of the rectangle shown above.

Possible Answers:

Correct answer:

Explanation:

In this problem you are given the width and perimeter of the rectangle. However, to solve for the area of the rectangle you must first find the length of the rectangle. To do so, work backwards using the formula:

Perimeter=2(W+L)

24=2(7+L)

24=14+2L

2L=24-14=10

$L=\frac{10}{2}=5$

Now that you know the width and length of the rectangle, apply the area formula:

$Area=Width\times Length$

$Area=7\times 5= 35$

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Example Question #61 : Geometry

A rectangle has a width of and a perimeter measurement of . Find the area of the rectangle.

Possible Answers:

126

Correct answer:

Explanation:

In this problem you are given the width and perimeter of the rectangle. However, to solve for the area of the rectangle you must first find the length of the rectangle. To do so, work backwards using the formula:

Perimeter=2(W+L)

32=2(9+L)

32=18+2L

2L=32-18=14

$L=\frac{14}{2}=7$

Now that you know the width and length of the rectangle, apply the area formula:

$Area=Width\times Length$

$Area=9\times 7= 63$

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Example Question #63 : Geometry

Isee rect.

Find the area of the rectangle shown above.

Possible Answers:

19.5

Correct answer:

Explanation:

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Example Question #41 : Plane Geometry

A rectangle has a width of 8.5 and a length of . Find the area of the rectangle.

Possible Answers:

32.5

35.5

Correct answer:

Explanation:

To find the area of a rectangle apply the formula:

$Area= Width\times Length$

This problem provides the measurements for both the width and length of the rectangle.

Thus, the solution is:

$Area=8.5\times4=34$

If the arithmetic is giving you trouble note that:

$8\times 4 = 32$

$0.5=\frac{1}{2}$

$\frac{1}{2}\times4=\frac{4}{2}=2$

The sum total of the partial products is:

32+2=34

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Example Question #31 : How To Find The Area Of A Rectangle

A rectangle has a width of $\frac{3}{4}$ foot and a length of $\frac{1}{2}$ foot. Find the area of the rectangle.

Possible Answers:

4ft^2

127in^2

27in^2

54in^2

5.5ft^2

Correct answer:

54in^2

Explanation:

To find the area of a rectangle apply the formula:

$Area= Width\times Length$

This problem provides the measurements for both the width and length of the rectangle. However, to select the correct answer it's necessary to convert the width and length measurements from feet to inches.

Since an inch is equal to $\frac{1}{12}$ of foot, the width and length conversions are:

$\frac{3}{4}=\frac{3}{4}\times \frac{3}{3}=\frac{9}{12}=9 in.$

$\frac{1}{2}=\frac{1}{2}\times \frac{6}{6}=\frac{6}{12}=6in.$

Thus, the solution is:

$Area=9\times6=54in^2$

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Example Question #41 : Quadrilaterals

A rectangle has a width of and a perimeter measurement of . Find the area of the rectangle.

Possible Answers:

Correct answer:

Explanation:

In this problem you are given the width and perimeter of the rectangle. However, to solve for the area of the rectangle you must first find the length of the rectangle. To do so, work backwards using the formula:

Perimeter=2(W+L)

34=2(9+L)

34=18+2L

2L=34-18=16

$L=\frac{16}{2}=8$

Now that you know the width and length of the rectangle, apply the area formula:

$Area=Width\times Length$

$Area=9\times 8= 72$

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Example Question #31 : How To Find The Area Of A Rectangle

A rectangle has a width of and a length of . Find the area of the rectangle.

Possible Answers:

150

250

175

200

225

Correct answer:

200

Explanation:

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All ISEE Lower Level Math Resources

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ISEE Lower Level Math : Plane Geometry

Study concepts, example questions & explanations for ISEE Lower Level Math

All ISEE Lower Level Math Resources

Example Questions

Example Question #53 : Geometry

Example Question #61 : Geometry

Example Question #41 : Plane Geometry

Example Question #42 : Plane Geometry

Example Question #61 : Geometry

Example Question #63 : Geometry

Example Question #41 : Plane Geometry

Example Question #31 : How To Find The Area Of A Rectangle

Example Question #41 : Quadrilaterals

Example Question #31 : How To Find The Area Of A Rectangle

All ISEE Lower Level Math Resources

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