All HSPT Math Resources
Example Questions
Example Question #37 : Quadrilaterals
How many meters of fence are needed to enclose a rectangular field that has a length of 1000 meters and a width of 100 meters?
The perimeter of a rectangle is simply the sum of the four sides:
Example Question #31 : Quadrilaterals
The perimeter of a rectangle with a length of and a width of is . Find .
We know that:
where:
So we can write:
Example Question #1 : How To Find The Perimeter Of A Parallelogram
13 in
36 in
18 in
26 in
26 in
To find the perimeter of a parallelogram, add the lengths of the sides. Opposite sides of a parallelogram are equivalent.
Example Question #2 : How To Find The Perimeter Of A Parallelogram
Note: Figure NOT drawn to scale.
, where and represent side lengths of the parallelogram and represents the height.
Find the perimeter of the parallelogram in the diagram.
The perimeter of the parallelogram is the sum of the four side lengths - here, that formula becomes
.
Note that the height is irrelevant to the answer.
Example Question #11 : How To Find The Perimeter Of A Rectangle
What is the perimeter of a rectangle with a width of 3 and a length of 10?
26
13
30
12
60
26
The formula for the perimeter of a rectangle is .
Plug in our given values to solve:
Example Question #1 : Isosceles Triangles
Two sides of an isosceles triangle are 20 and 30. What is the difference of the largest and the smallest possible perimeters?
10
0
30
15
The answer cannot be determined
10
The trick here is that we don't know which is the repeated side. Our possible triangles are therefore 20 + 20 + 30 = 70 or 30 + 30 + 20 = 80. The difference is therefore 80 – 70 or 10.
Example Question #1 : How To Find The Perimeter Of An Equilateral Triangle
A square rug border consists of a continuous pattern of equilateral triangles, with isosceles triangles as corners, one of which is shown above. If the length of each equilateral triangle side is 5 inches, and there are 40 triangles in total, what is the total perimeter of the rug?
The inner angles of the corner triangles is 30°.
124
188
208
180
200
188
There are 2 components to this problem. The first, and easier one, is recognizing how much of the perimeter the equilateral triangles take up—since there are 40 triangles in total, there must be 40 – 4 = 36 of these triangles. By observation, each contributes only 1 side to the overall perimeter, thus we can simply multiply 36(5) = 180" contribution.
The second component is the corner triangles—recognizing that the congruent sides are adjacent to the 5-inch equilateral triangles, and the congruent angles can be found by
180 = 30+2x → x = 75°
We can use ratios to find the unknown side:
75/5 = 30/y → 75y = 150 → y = 2''.
Since there are 4 corners to the square rug, 2(4) = 8'' contribution to the total perimeter. Adding the 2 components, we get 180+8 = 188 inch perimeter.
Example Question #1 : How To Find The Perimeter Of A Square
A circle with a radius 2 in is inscribed in a square. What is the perimeter of the square?
16 in
28 in
12 in
24 in
32 in
16 in
To inscribe means to draw inside a figure so as to touch in as many places as possible without overlapping. The circle is inside the square such that the diameter of the circle is the same as the side of the square, so the side is actually 4 in. The perimeter of the square = 4s = 4 * 4 = 16 in.
Example Question #2 : How To Find The Perimeter Of A Square
Square X has 3 times the area of Square Y. If the perimeter of Square Y is 24 ft, what is the area of Square X, in sq ft?
72
54
112
144
108
108
Find the area of Square Y, then calculate the area of Square X.
If the perimeter of Square Y is 24, then each side is 24/4, or 6.
A = 6 * 6 = 36 sq ft, for Square Y
If Square X has 3 times the area, then 3 * 36 = 108 sq ft.
Example Question #291 : Plane Geometry
A square has an area of . If the side of the square is reduced by a factor of two, what is the perimeter of the new square?
The area of the given square is given by so the side must be 6 in. The side is reduced by a factor of two, so the new side is 3 in. The perimeter of the new square is given by .
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