All HSPT Math Resources
Example Questions
Example Question #1326 : Concepts
The perimeter of the above square is 40% of what number?
The perimeter of a square with sides of length 12 is 4 times this, or
.
The number of which 48 is 40% can be found by dividing 48 by 40%, or :
..
Example Question #1327 : Concepts
What is the volume of a cube with a side of 9m?
Since volume is length times width times height, and every side on a cube is equal, multiply
The volume of this cube is .
Example Question #1328 : Concepts
A cube has six square faces, each with area 64 square inches. Using the conversion factor 1 inch = 2.5 centimeters, give the volume of this cube in cubic centimeters, rounding to the nearest whole number.
800 cubic centimeters
8,000 cubic centimeters
400 cubic centimeters
4,000 cubic centimeters
2,000 cubic centimeters
8,000 cubic centimeters
The volume of a cube is the cube of its sidelength, which is also the sidelength of each square face. This sidelength is the square root of the area 64:
inches.
Multiply this by 2.5 to get the sidelength in centimeters:
centimeters.
The cube of this is
cubic centimeters
Example Question #1329 : Concepts
A cube has a side length of 5 inches. Give the volume and surface area of the cube.
A cube has all edges the same length. The volume of a cube is found by multiplying the length of any edge by itself twice. As a formula:
where is the length of any edge of the cube.
The Surface Area of a cube can be calculated as .
So we get:
Volume
Surface area
Example Question #1921 : Hspt Mathematics
The height of a cylinder is 3 inches and the radius of the circular end of the cylinder is 3 inches. Give the volume and surface area of the cylinder.
The volume of a cylinder is found by multiplying the area of one end of the cylinder (base) by its height or:
where is the radius of the circular end of the cylinder and is the height of the cylinder. So we can write:
The surface area of the cylinder is given by:
where is the surface area of the cylinder, is the radius of the cylinder and is the height of the cylinder. So we can write:
Example Question #1922 : Hspt Mathematics
The end (base) of a cylinder has an area of square inches. If the height of the cylinder is half of the radius of the base of the cylinder, give the volume of the cylinder.
The area of the end (base) of a cylinder is , so we can write:
The height of the cylinder is half of the radius of the base of the cylinder, that means:
The volume of a cylinder is found by multiplying the area of one end of the cylinder (base) by its height:
or
Example Question #1923 : Hspt Mathematics
We have two right cylinders. The radius of the base Cylinder 1 is times more than that of Cylinder 2, and the height of Cylinder 2 is 4 times more than the height of Cylinder 1. The volume of Cylinder 1 is what fraction of the volume of Cylinder 2?
The volume of a cylinder is:
where is the volume of the cylinder, is the radius of the circular end of the cylinder, and is the height of the cylinder.
So we can write:
and
Now we can summarize the given information:
Now substitute them in the formula:
Example Question #1924 : Hspt Mathematics
Two right cylinders have the same height. The radius of the base of the first cylinder is two times more than that of the second cylinder. Compare the volume of the two cylinders.
The volume of a cylinder is:
where is the radius of the circular end of the cylinder and is the height of the cylinder. So we can write:
We know that
and
.
So we can write:
Example Question #491 : Grade 8
A car dealership wants to fill a large spherical advertising ballon with helium. It can afford to buy 1,000 cubic yards of helium to fill this balloon. What is the greatest possible diameter of that balloon (nearest tenth of a yard)?
The volume of a sphere, given its radius, is
Set , solve for , and double that to get the diameter.
The diameter is twice this, or 12.4 yards.
Example Question #492 : Grade 8
The diameter of a sphere is . Give the volume of the sphere in terms of .
The diameter of a sphere is so the radius of the sphere would be
The volume enclosed by a sphere is given by the formula:
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