HSPT Math : Algebra
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Example Questions
Example Question #51 : Operations
Simplify:
We can first apply the power of a product rule and then apply the power of a power rule. So we can write:
Example Question #694 : Concepts
Simplify:
None of these
We can solve it using the pattern for the square of a binominal or by using FOIL:
Example Question #695 : Concepts
Simplify:
None of these
We can solve it using the pattern for the square of a binominal or by using FOIL:
Example Question #53 : Operations
At Bess's candy warehouse, she charges M for the first 5 pounds of candy that customers buy and P for each additional pound of candy. What is the cost of buying 128 ounces of candy from Bess's warehouse? (*Note: there are 16 ounces in a pound.)
The first step is the convert ounces into pounds. Given that there are 16 ounces in a pound, there are 8 pounds in 128 ounces because 128 divided by 16 eequals 8.
Since the first 5 pounds cost M, and each additional pound costs P, there are 3 additional pounds that will have to be paid for at the P price per pound. Thus, the appropriate formula to express the value of the cost of 128 ounces of candy (8 pounds) is:
Example Question #1 : Expressions & Equations
Simplify:
Example Question #5 : Apply Properties Of Operations To Expand Linear Expressions With Rational Coefficients: Ccss.Math.Content.7.Ee.A.1
Simplify:
Example Question #1 : Expressions & Equations
Simplify:
This problem is just a matter of grouping together like terms. Remember that terms like 
The only part that might be a little hard is:
If you are confused, think of your number line. This is like "going back" (more negative) from 15. Therefore, you ranswer will be:
Example Question #1 : How To Subtract Variables
Simplify:
This problem really is a trick question. There are no common terms among any of the parts of the expression to be simplified. In each case, you have an independent variable or set of variables: 
Example Question #141 : Algebra
Simplify:
Remember, when there is a subtraction outside of a group, you should add the opposite of each member. That is:
That is a bit confusing, so let's simplify. When you add a negative, you subtract:
Now, group your like variables:
Finally, perform the subtractions and get:
Example Question #3 : How To Subtract Variables
Simplify:
Begin by rewriting the subtracted group as a set of added negative numbers:
Now, simplify that a little by rewriting the additions of negatives as being mere subtractions:
Next, move the like terms next to each other:
Finally, combine like terms:
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