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HSPT Math : Algebra

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Example Questions

Example Question #501 : Algebra

Solve for : 6+p= -6

Possible Answers:

Correct answer:

Explanation:

To solve for the unknown variable, subtract the value of positive six from both sides of the equation.

6+p - (6)= -6-(6)

p=-12

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Example Question #502 : Algebra

Evaluate: $c+\frac{3}{2} = \frac{5}{2}$

Possible Answers:

$\frac{1}{2}$

Correct answer:

Explanation:

To solve for , subtract three halves from both sides of the equation.

$c+\frac{3}{2} -(\frac{3}{2})= \frac{5}{2}-(\frac{3}{2})$

$c=\frac{5}{2}-\frac{3}{2} = \frac{2}{2}=1$

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Example Question #503 : Algebra

Solve: -8=3x

Possible Answers:

$-\frac{3}{8}$

$\frac{8}{3}$

$\frac{3}{8}$

$-\frac{8}{3}$

Correct answer:

$-\frac{8}{3}$

Explanation:

Divide both sides by three.

$\frac{-8}{3}=\frac{3x}{3}$

$x=-\frac{8}{3}$

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Example Question #504 : Algebra

Solve: p+9 = -13

Possible Answers:

Correct answer:

Explanation:

To solve for the unknown variable, subtract from both sides.

p+9 -9= -13-9

p=-22

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Example Question #505 : Algebra

Solve: $b-\frac{1}{5}=0$

Possible Answers:

$\frac{1}{5}$

$-\frac{1}{5}$

Correct answer:

$\frac{1}{5}$

Explanation:

To solve for , add $\frac{1}{5}$ to both sides of the equation to isolate the unknown variable.

$b-\frac{1}{5}+\frac{1}{5}=0+\frac{1}{5}$

$b=\frac{1}{5}$

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Example Question #505 : Algebra

Solve: z-7 = 8

Possible Answers:

$-\frac{8}{7}$

Correct answer:

Explanation:

Add to both sides of the equation.

z-7 +(7)= 8+(7)

z=15

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Example Question #506 : Algebra

Solve: -32a=32

Possible Answers:

Correct answer:

Explanation:

To isolate the unknown variable, divide both sides by negative .

$\frac{-32a}{-32}=\frac{32}{-32}$

a=-1

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Example Question #508 : Algebra

Solve the equation: -2x = -10

Possible Answers:

$-\frac{1}{5}$

$\frac{1}{8}$

Correct answer:

Explanation:

In order to isolate the unknown variable, we must divide both sides by negative two.

Divide by negative two on both sides.

$\frac{-2x}{-2} =\frac{ -10}{-2}$

Simplify the left and right sides of the equation. The negative two on the left side will cancel out, and two negative signs divided by each other will turn the answer into a positive value.

The answer is: x=5

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Example Question #509 : Algebra

Solve: $\frac{9}{11}x = 2$

Possible Answers:

$\frac{22}{9}$

$\frac{9}{2}$

$\frac{11}{18}$

$\frac{22}{18}$

$\frac{9}{22}$

Correct answer:

$\frac{22}{9}$

Explanation:

In order to isolate the variable, multiply both sides by the reciprocal of the coefficient in front of the variable.

$\frac{9}{11}x \cdot \frac{11}{9}= 2\cdot \frac{11}{9}$

Simplify both sides.

The answer is : $x=\frac{22}{9}$

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Example Question #507 : Algebra

Solve the following for :

2x=30

Possible Answers:

x=15

x=28

x=32

x=60

Correct answer:

x=15

Explanation:

To solve for , simply divide both sides by 2 to isolate .

Remember, division undoes multiplication.

Thus,

$2x=30\Rightarrow \frac{2x}{2}=\frac{30}{2}\Rightarrow x=15$

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HSPT Math : Algebra

Study concepts, example questions & explanations for HSPT Math

All HSPT Math Resources

Example Questions

Example Question #501 : Algebra

Example Question #502 : Algebra

Example Question #503 : Algebra

Example Question #504 : Algebra

Example Question #505 : Algebra

Example Question #505 : Algebra

Example Question #506 : Algebra

Example Question #508 : Algebra

Example Question #509 : Algebra

Example Question #507 : Algebra

All HSPT Math Resources

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