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Flashcards: Area

Find the area of a square with the following side length:

s=5 $\displaystyle s=5$

$\displaystyle 5$

$\displaystyle 10$

$\displaystyle 20$

$\displaystyle 15$

$\displaystyle 25$

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Flashcards: Area

Find the area of a square with the following side length:

s=5 $\displaystyle s=5$

$\displaystyle 5$

$\displaystyle 10$

$\displaystyle 20$

$\displaystyle 15$

$\displaystyle 25$

Report an Error Copyright Notice

Flashcards: Area

Find the area of a square with the following side length:

s=5 $\displaystyle s=5$

Your answer:

$\displaystyle 5$

Your answer:

$\displaystyle 10$

Your answer:

$\displaystyle 20$

Your answer:

$\displaystyle 15$

Correct answer:

$\displaystyle 25$

Explanation:

We can find the area of a circle using the following formula:

A=s^2 $\displaystyle A=s^2$

In this equation the variable, $\displaystyle s$ , represents the length of a single side.

Substitute and solve.

A=5^2 $\displaystyle A=5^2$

A=25 $\displaystyle A=25$

Flashcards: Area

The perimeter of a square is $\displaystyle P$ . In terms of $\displaystyle P$ , give the area of the square.

$\frac{1}{4}P^{2}$ $\displaystyle \frac{1}{4}P^{2}$

$\frac{1}{16} \sqrt{P}$ $\displaystyle \frac{1}{16} \sqrt{P}$

$\frac{1}{4} \sqrt{P}$ $\displaystyle \frac{1}{4} \sqrt{P}$

$\frac{1}{16}P^{2}$ $\displaystyle \frac{1}{16}P^{2}$

$\displaystyle 4P$

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Flashcards: Area

The perimeter of a square is $\displaystyle P$ . In terms of $\displaystyle P$ , give the area of the square.

Your answer:

$\frac{1}{4}P^{2}$ $\displaystyle \frac{1}{4}P^{2}$

Your answer:

$\frac{1}{16} \sqrt{P}$ $\displaystyle \frac{1}{16} \sqrt{P}$

Your answer:

$\frac{1}{4} \sqrt{P}$ $\displaystyle \frac{1}{4} \sqrt{P}$

Your answer:

$\displaystyle 4P$

Correct answer:

$\frac{1}{16}P^{2}$ $\displaystyle \frac{1}{16}P^{2}$

Explanation:

Since a square comprises four segments of the same length, the length of one side is equal to one fourth of the perimeter of the square, which is $\frac{1}{4}P$ $\displaystyle \frac{1}{4}P$ . The area of the square is equal to the square of this sidelength, or

$\left (\frac{1}{4}P \right )^{2} = \left (\frac{1}{4} \right )^{2} P^{2} = \frac{1}{16}P^{2}$ $\displaystyle \left (\frac{1}{4}P \right )^{2} = \left (\frac{1}{4} \right )^{2} P^{2} = \frac{1}{16}P^{2}$ .

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Flashcards: Area

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Flashcards: Area

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Flashcards: Area

Flashcards: Area

Flashcards: Area

Flashcards: Area

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