High School Physics : Understanding Distance, Velocity, and Acceleration

Study concepts, example questions & explanations for High School Physics

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Example Questions

Example Question #21 : Understanding Distance, Velocity, And Acceleration

You are given a graph of displacement vs. time. Which of the following ways can be used to determine velocity at any given point?

Possible Answers:

The velocity is the slope of the line at any given time

The velocity is the y-intercept of the graph

The velocity is the area under the curve for any time interval

The velocity cannot be determined from a graph of displacement vs time

The velocity is the total change in displacement over the total time

Correct answer:

The velocity is the slope of the line at any given time

Explanation:

The important thing to note is that the question asks for the velocity at any given point. The average velocity will be equal to the total displacement divided by the total time, but the question is asking for the instantaneous velocity.

Velocity is calculated by a change in displacement over a change in time. In a displacement versus time graph, this is equal to the slope.

This tells us that the slope at a certain time will be equal to the velocity at that time.

In calculus terms, velocity is the derivative of the function for displacement in terms of time. What this means is that at any point on the graph, the instantaneous slope is the velocity for that given time. To determine velocity, one must find the slope of the line at that particular time interval.

Example Question #111 : Linear Motion

A mass moves a constant velocity, , for a certain amount of time, . How far does it travel?

Possible Answers:

Correct answer:

Explanation:

The relationship between velocity, distance, and time is:

We can multiply both sides by  to see solve for the distance traveled, in terms of the time and velocity.

The product of time and velocity, , will give us the distance we are looking for.

Example Question #21 : Understanding Distance, Velocity, And Acceleration

Derek rolls a ball along a flat surface with an initial velocity of . If it stops after 12 seconds, what was the acceleration on the ball?

Possible Answers:

Correct answer:

Explanation:

Since the ball starts with a positive velocity and ends at rest, we can predict that the acceleration will be negative. Using the values given in the question and the equation below, we can solve for the acceleration.

Example Question #24 : Understanding Distance, Velocity, And Acceleration

An object starts sliding along a floor at a speed of . After , it is observered that the object is sliding with a speed of . What is the average acceleration of the object?

Possible Answers:

Correct answer:

Explanation:

Notice that at the beginning and at the end of the problem, the velocity of the object is . Acceleration is . Since there is no change in velocity, acceleration is calculated as , so the acceleration is .

Example Question #21 : Understanding Distance, Velocity, And Acceleration

A balls starts at rest, then begins to move with a negative acceleration. Describe the motion of the ball.

Possible Answers:

It remains at rest

It is beginning circular motion

It is moving backwards

It is slowing down

It is lifting off of the ground

Correct answer:

It is moving backwards

Explanation:

Acceleration is a vector. This means that positive and negative signs are used to help us understand the direction of motion. If something has a negative acceleration it CAN mean that it is slowing down, but not always. Negative usually means that an object is moving to the left, down, or backwards. If the ball begins from rest, and has a negative acceleration, then it is gaining a negative velocity. This simply refers to a velocity in a negative, or backwards, direction.

Example Question #26 : Understanding Distance, Velocity, And Acceleration

An object starts at rest and reaches a velocity of  after  seconds. What is the average acceleration of the object?

Possible Answers:

Correct answer:

Explanation:

The relationship between acceleration and velocity is:

Acceleration is equal to the change in velocity over the change in time. If the object starts from rest, then we can set up an equation to solve for the change in velocity.

Using the terms from the question, we can see that the acceleration will be equal to the final velocity divided by the time.

Example Question #21 : Understanding Distance, Velocity, And Acceleration

You are given a graph of velocity vs. time. Which of the following ways can be used to determine acceleration at any given point?

Possible Answers:

The acceleration is the total change in velocity over the total time

The acceleration is the y-intercept of the velocity vs time graph

The acceleration cannot be determined from the graph

The acceleration is the slope at any particular point in time

The acceleration is the area under the curve for any given time interval

Correct answer:

The acceleration is the slope at any particular point in time

Explanation:

The important thing to note is that the question asks for the acceleration at any given point. The average acceleration will be equal to the net change in velocity divided by the total time, but the question is asking for the instantaneous acceleration.

Acceleration is calculated by a change in velocity over a change in time. In a velocity versus time graph, this is equal to the slope.

This tells us that the slope at a certain time will be equal to the acceleration at that time.

In calculus terms, acceleration is the derivative of the function for velocity in terms of time. What this means is that at any point on the graph, the instantaneous slope is the acceleration for that given time. To determine acceleration, one must find the slope of the line at that particular time interval.

Example Question #21 : Understanding Distance, Velocity, And Acceleration

Sam throws a  rock off the edge of a  tall building at an angle of  from the horizontal. The rock has an initial speed of .

If Sam then threw a  rock instead, how would this affect its total horizontal distance travelled? 

Possible Answers:

The distance would be zero

The distance would not change

The distance would quadruple

The distance would be quartered

The distance would be doubled

Correct answer:

The distance would not change

Explanation:

The equation for distance travelled in the x-direction with parabolic motion is .

The mass of the object is not a variable in this calculation, and will not alter the horizontal velocity.

This can also be observed by analyzing the units for the velocity calculation.

Kilograms are not involved in the units, so mass will not be involved.

Changing the mass will not change the distance travelled; the rock will travel the same distance.

Example Question #29 : Understanding Distance, Velocity, And Acceleration

Laurence throws a  rock off the edge of a  tall building at an angle of  from the horizontal with an initial speed of .

.

A rock is thrown with the same initial velocity and angle from the top of the building. How would the horizontal distance traveled by this rock compare to the horizontal distance traveled by the lighter rock?

Possible Answers:

The heavier rock would travel twice as far

The heavier rock would not move

The heavier rock would travel half as far

They would travel the same distance

The heavier rock would travel  times as far

Correct answer:

They would travel the same distance

Explanation:

The equation for distance travelled in the horizontal direction is:

There is no acceleration in the horizontal direction, so this velocity is constant throughout flight.

There is no place for mass in this equation. Any objects thrown with the same velocity will travel the same distance. The two rocks with thus travel the same horizontal distance.

Example Question #30 : Understanding Distance, Velocity, And Acceleration

While traveling along a highway, a specific automobile is capable of an acceleration of about .  At this rate, how long does it take to accelerate from  to ?

Possible Answers:

Correct answer:

Explanation:

Knowns:

 

 

 

 

Unknowns:

 

 

Equation:

 

The most important thing to recognize here is that the initial and final velocities are not in the correct units.  The first step is to convert both of these values to .

 

 

 

Then rearrange your equation to solve for  (the missing variable).

 

 

Now plug in the variables and solve.

 

 

 

 

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