All High School Physics Resources
Example Questions
Example Question #4 : Understanding Newton's Second Law
A ball rests on a flat table. What is the normal force exerted on the ball by the table?
Newton's second law allows us to solve for the force of gravity on the ball:
Newton's third law tells us that the force of the ball on the table, due to gravity, will be equal and opposite to the normal force of the table on the ball.
Substitute the equation for force of gravity.
Now we can use the mass of the ball and the acceleration of gravity to solve for the normal force. First, convert the mass to kilograms. Then, use the equation to find the normal force.
Example Question #311 : High School Physics
Which of these is necessary for there to be a non-zero net force?
Non-zero net acceleration
Non-zero frictional force
An equal and opposite reaction
Non-zero net torque
Non-zero net displacement
Non-zero net acceleration
Newton's second law states that force is a mass times an acceleration.
In order for a force to exist, there must be an acceleration applied to a mass. A force cannot exist on a massless object, nor can it exist without a net acceleration.
Newton's third law states that for every force on an object, there is an equal and opposite force from the object. These force frequently cancel out, however, and produce a net force of zero.
Example Question #11 : Newton's Laws
Which of these is not an example of Newtonian mechanics?
Newtonian mechanics apply to all objects of substantial mass travelling at significantly slower than the speed of light.
Newton's law of universal gravitation, Newton's second law, momentum, and the equation for mechanical energy all fall under Newtonian mechanics.
The mass-energy equivalence suggests that mass can change as the speed of an object (such as an electron) approaches the speed of light. Newtonian mechanics assume that mass is constant, and do not apply to objects approaching the speed of light.
Example Question #7 : Understanding Newton's Second Law
A pair of fuzzy dice is hanging by a cord from your rearview mirror. While you are decelerating at a constant rate from to rest in , what angle does the string make with the vertical and in what direction (toward or away from the windshield)?
45 degrees toward the windshield
61 degrees away from the windshield
61 degrees toward the windshield
29 degrees away from the windshield
29 degrees toward the windshield
29 degrees toward the windshield
When you are slowing down the car, the fuzzy dice want to keep moving forward. Therefore the angle they make will be toward the windshield. The force of tension on the fuzzy dice is what is holding them back with the car, keeping them from going through the windshield. This tension force is comprised of two components. The y-component of the tension is equal to the force of gravity acting on the fuzzy dice. The x-component of the tension is equal to the force of the car slowing down.
The angle of the fuzzy dice is related to these two components through the trigonometric function tangent.
We can then use in the inverse tan function to determine the angle acting on the fuzzy dice.
Notice how the mass of the dice falls out of the equation
We can now plug in our values and solve.
Example Question #3 : Understanding Newton's Second Law
Two dogs pull on a bone in opposite directions. If the first dog pulls with a force of to the left and the other pulls with a force of in the opposite direction, what will be the acceleration on the bone?
We need to know the masses of the dogs in order to solve
First we need to find the net force, which will be equal to the sum of the forces on the bone.
Since the forces are going in opposite directions, we know that one force will be negative (since force is a vector). Conventionally, right is assigned a positive directional value. The force to the left will be negative.
From here we can use Newton's second law to expand the force and solve for the acceleration, using the mass of the bone.
Example Question #9 : Understanding Newton's Second Law
Derek pushes a crate along a rough surface with of force. He observes that it is only accelerating at a rate of . What must the value of the force of friction be?
(Assume the only two forces acting on the object are friction and Derek).
Newton's second law states that .
If Derek is pushing with of force, then we should be able to solve for the acceleration of the crate.
Derek observes that the crate is acceleration at a rate of , rather than the expected . An outside force is acting upon it to slow the acceleration.
The equation for the net force on the object is: . We also know, from Newton's second law, that F resultant=ma resultant, where the resultant force and acceleration are the values actually observed.
Plug in the information we've been given so far to find the force of friction.
Subtract from both sides to find the force of friction.
Friction will be negative because it acts in the direction opposite to the force of Derek.
Example Question #10 : Understanding Newton's Second Law
If you push a mass with the same force that you push a mass from rest.
None of the above is true
The mass accelerates 6 times faster than the mass
Both masses accelerate at the same rate
The mass accelerates 6 times faster than the mass
The mass accelerates 6 times faster than the mass
Newton's second law states that force is a mass times an acceleration.
Since both masses have the same force acting on it, we can look at the relationship between mass and acceleration. These two things are inversely proportional to one another. As one increases, the other decreases. Therefore the larger mass will have a smaller acceleration. The smaller mass will have a larger acceleration.
Suppose that the force acting on both objects is . We can confirm this by solving for the acceleration.
The smaller mass will accelerate 6 times faster than the smaller mass.
Example Question #13 : Newton's Laws
A net force acts on a mass and produces an acceleration . What is the new acceleration if the force is doubled and the mass is quadrupled.
Newton's second law states that force is a mass times an acceleration.
Assuming that all the original values were equal to
We can substitute in new values for a doubled force and quadrupled mass to find the new acceleration.
This shows that the new acceleration will be of the original value or equal to a/2.
Example Question #11 : Understanding Newton's Second Law
Which of these is necessary for there to be a non-zero net force?
Non-zero net acceleration
Non-zero net displacement
Non-zero net torque
Non-zero frictional force
An equal and opposite reaction
Non-zero net acceleration
Newton's second law states that force is a mass times an acceleration.
In order for a force to exist, there must be an acceleration applied to a mass. A force cannot exist on a massless object, nor can it exist without a net acceleration.
Newton's third law states that for every force on an object, there is an equal and opposite force from the object. These forces frequently cancel out, however, and produce a net force of zero.
Example Question #13 : Understanding Newton's Second Law
A person jumps from the roof of a house high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of . If the mass of his torso (excluding legs) is , find the average force exerted on his torso by his legs during deceleration.
To solve this problem we need to divide up the situation into two parts. During the first part the person is jumping from the roof of a house and is therefore undergoing freefall and accelerated motion due to the force of gravity. Therefore we will need to use kinematic equations to solve for the final velocity as the person lands. In the second part of the problem, the person decelerates their torso through a specific distance and comes to a stop. We will then need to calculate the acceleration of the torso during this second part to determine the average force applied.
Let us start with kinematics to determine the speed of the torso as it hits the ground.
Knowns
We can use the kinematic equation
This is the velocity of the torso as it hits the ground. We will know use the same equation with new variables to determine the acceleration of the torso as it comes to a stop.
Knowns
Rearrange to get the acceleration by itself
We can now plug this into Newton’s 2nd Law to find the average force acting on the object.
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