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High School Physics : High School Physics

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Example Questions

Example Question #441 : High School Physics

A 0.5kg ball is about to roll off the edge of a 1.5m tall table. What is its current potential energy?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

14.7J

9.87J

13.33J

3.72J

7.35 J

Correct answer:

7.35 J

Explanation:

The equation for potential energy is PE=mgh . We are given the mass of the ball, the height of the table, and the acceleration of gravity in the question. The distance the ball travels is in the downward direction, making it negative.

Plug in the values, and solve for the potential energy.

$PE=(0.5kg)(-9.8\frac{m}{s^2})(-1.5m)$

PE=7.35J

The units for energy are Joules.

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Example Question #442 : High School Physics

A pendulum with string length 1.2m is dropped from rest. If the mass at the end of the pendulum is 2.03kg , what is its initial potential energy?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

12.32J

23.87J

14.42J

18.87J

46.12J

Correct answer:

23.87J

Explanation:

Potential energy can be found using the equation PE=mgh . For the pendulum, the height is going to be the length of the string.

Remember, your height is your change in distance. In this case the ball will go down 1.2m , so the height will be negative since the ball travels downward.

$PE= (2.03kg)(-9.8\frac{m}{s^2})(-1.2m)$

PE=23.87J

The units for energy are Joules.

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Example Question #45 : Energy

A 0.5kg ball rolls up a hill. If the ball is initially travelling with a velocity of $3.12\frac{m}{s}$ , how high up the hill does it roll?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

0.03m

9.8m

0.52m

0.50m

0.48 m

Correct answer:

0.50m

Explanation:

Use the conservation of energy equation to solve for the potential energy at the top of the hill.

$PE_{top}=KE_{bottom}$

$mgh=\frac{1}{2}mv^2$

Plug in the values given to you and solve for the final height.

$(0.5kg)(9.8\frac{m}{s^2})(h)=\frac{1}{2}(0.5kg)(3.12\frac{m}{s})^2$

$4.9\frac{kg\cdot m}{s^2}h=2.4336\frac{kg\cdot m^2}{s^2}$

$h=\frac{2.4336\frac{kg\cdot m^2}{s^2}}{4.9\frac{kg\cdot m}{s^2}}$

$h=0.497m\approx0.5m$

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Example Question #443 : High School Physics

Rob throws a ball vertically in the air with an initial velocity of $3.5\frac{m}{s}$ . What is the maximum height of the ball?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

0.63m

1.22m

0.71m

0.87m

0.32m

Correct answer:

0.63m

Explanation:

The maximum height will be when the ball has only potential energy, and no kinetic energy. Initially, the ball has only kinetic energy and no potential energy. We can set these values equal to each other due to conservation of energy.

$PE_{top}=KE_{bottom}$

$mgh=\frac{1}{2}mv^2$

The masses will cancel out.

$gh=\frac{1}{2}v^2$

Plug in the values that were given and solve for the height.

$(9.8\frac{m}{s^2})h=\frac{1}{2}(3.5\frac{m}{s})^2$

$(9.8\frac{m}{s^2})h=\frac{1}{2}(12.25\frac{m^2}{s^2})$

$(9.8\frac{m}{s^2})h=6.125\frac{m^2}{s^2}$

$h=\frac{6.125\frac{m^2}{s^2}}{9.8\frac{m}{s^2}}$

h=0.625m

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Example Question #47 : Energy

A 1.11kg ball sits at rest on a table 1.72m above the ground. What is the potential energy of the ball?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

9.36J

18.71J

37.42J

31.2J

4.32J

Correct answer:

18.71J

Explanation:

The only potential energy this ball can have is gravitational potential energy. The formula for gravitational potential energy is PE=mgh .

We are given the height and mass of the ball. Using the given values, we can solve for the potential energy.

Keep in mind that the displacement will be negative because the ball is traveling in the downward direction.

$PE=(1.11kg)(-9.8\frac{m}{s^2})(-1.72m)$

PE=18.71J

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Example Question #48 : Energy

Two balls, one with mass 2kg and one with mass 4kg , are dropped from 30m above the ground. What is the potential energy of the 2kg ball right before it starts to fall?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

1176J

588J

98J

294J

147J

Correct answer:

588J

Explanation:

The equation for potential energy is PE=mgh .

Since we know the mass, height, and acceleration from gravity, we can simply multiply to find the potential energy.

$PE=(2kg)(-9.8\frac{m}{s^2})(-30m)$

Note that we plugged in -30m for because the ball will be moving downward; the change in height is negative as the ball drops.

PE=588J

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Example Question #49 : Energy

Two balls, one with mass 2kg and one with mass 4kg , are dropped from 30m above the ground. What is the potential energy of the 4kg ball right before it starts to fall?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

588J

1123J

1176J

294J

73.5J

Correct answer:

1176J

Explanation:

The equation for potential energy is PE=mgh .

Since we know the mass, height, and acceleration from gravity, we can simply multiply to find the potential energy.

$PE=(4kg)(-9.8\frac{m}{s^2})(-30m)$

Note that we plugged in -30m for because the ball will be moving downward; the change in height is negative as the ball drops.

PE=1176J

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Example Question #444 : High School Physics

A 2kg book falls off the top of a 2.3m bookshelf. What is its potential energy right before it falls?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

4.51J

0.47J

45.08J

2.94J

450.8J

Correct answer:

45.08J

Explanation:

The formula for potential energy is PE=mgh .

Given the values for the mass, height, and gravity, we can solve using multiplication. Note that the height is negative because the book falls in the downward direction.

$PE=2kg*-9.8\frac{m}{s^2}*-2.3m$

PE=45.08J

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Example Question #445 : High School Physics

A 1.12kg book falls off the top of a 2.03m bookshelf. What is its potential energy right before it falls?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

22.28J

8.92J

13.85J

7.99J

32.16J

Correct answer:

22.28J

Explanation:

The formula for potential energy is PE=mgh .

Given the values for the mass, height, and gravity, we can solve using multiplication. Note that the height is negative because the book falls in the downward direction.

$PE=1.12kg*-9.8\frac{m}{s^2}*-2.03m$

PE=22.28J

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Example Question #446 : High School Physics

A 3.23kg book falls off the top of a 3.01m bookshelf. What is its potential energy right before it falls?

$\small g=-9.8\frac{m}{s^2}$

Possible Answers:

31.76J

98.23J

123.38J

95.28J

16.04J

Correct answer:

95.28J

Explanation:

The formula for potential energy is PE=mgh .

Given the values for the mass, height, and gravity, we can solve using multiplication. Note that the height is negative because the book falls in the downward direction.

$PE=3.23kg*-9.8\frac{m}{s^2}*-3.01m$

PE=95.28J

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High School Physics : High School Physics

Study concepts, example questions & explanations for High School Physics

All High School Physics Resources

Example Questions

Example Question #441 : High School Physics

Example Question #442 : High School Physics

Example Question #45 : Energy

Example Question #443 : High School Physics

Example Question #47 : Energy

Example Question #48 : Energy

Example Question #49 : Energy

Example Question #444 : High School Physics

Example Question #445 : High School Physics

Example Question #446 : High School Physics

All High School Physics Resources

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