GRE Subject Test: Chemistry : Freezing Point
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Example Questions
Example Question #5 : Physical Chemistry
What is the freezing point of a 2M solution of 
First, we need to calculate the molality because that is what we use in our equation for freezing point depression. We can get that from the molarity without knowing exactly how many liters or grams we have. We just have to know what we have one mole per liter. The weight of water is one kilogram per liter, so this allows us to make this conversion.
The molality is 2m. The van't Hoff factor is 3, as we get one calcium ion and two chloride ions per molecule during dissociation.
We can now plug the values into the equation for freezing point depression.
This gives us our depression of 
Example Question #1 : Colligative Properties
How much sodium chloride has been added to four liters of water if the freezing point of the solution is 
Sodium chloride has a molar mass of 
We can determine how much sodium chloride was added to the water using the freezing point depression equation.
The normal freezing point of wtaer is 0 degrees Celsius, so we know that the temperature of the solution has changed by 2.5 degrees. Since sodium chloride will generate two ions per molecule in solution, the van't Hoff factor will be 2. Based on the density of water, we can determine that 4 liters of water weighs 4 kilograms.
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