All GRE Subject Test: Biochemistry, Cell, and Molecular Biology Resources
Example Questions
Example Question #11 : Cellular Respiration And Photosynthesis
How many molecules of pyruvate are produced from one molecule of glucose during glycolysis?
The starting molecule in glycolysis is glucose, a six-carbon molecule while the ending molecule in glycolysis is pyruvate, a three-carbon molecule. During glycolysis glucose is split and its six carbons are used to make 2 molecules of three-carbon pyruvate because. Note that no carbon dioxide is released during glycolysis, but since aerobic metabolism (starting with the Krebs cycle) uses acetyl-CoA as a substrate, which is two carbons long, one molecule of carbon dioxide is released for each molecule of pyruvate produced during glycolysis.
Example Question #11 : Cellular Respiration And Photosynthesis
Which of the following is true regarding glycolysis?
More than one of these are correct
Glycolysis produces 4 net ATP
The inputs for glycolysis include glycogen and glucose
Glycolysis occurs in every cell
Glycolysis occurs in every cell
Glycolysis is the first step in producing ATP. Glycolysis is an anaerobic process that occurs in every cell. Certain cells, such as red blood cells, only rely on glycolysis for energy. In most of the other cells, glycolysis produces ATP and few intermediates that will be used in subsequent steps to generate more ATP; therefore, glycolysis occurs in every cell.
The major input for glycolysis is glucose. Glycogen, a storage form of glucose, needs to be broken down into individual glucose units before undergoing glycolysis. The net products of glycolysis are 2 NADH, 2 pyruvate molecules, and 2 ATP. There is a total of 4 ATP produced in glycolysis; however, two of the ATP molecules are consumed, leaving behind only 2 net ATP.
Example Question #12 : Cellular Respiration And Photosynthesis
The first step of glycolysis hydrolyzes ATP to ADP and inorganic phosphate. What happens to the glucose molecule during this step?
The glucose is phosphorylated
The glucose is dephosphorylated
The glucose is cleaved into two molecules of glyceraldehyde-3-phosphate
Glucose is cleaved into two molecules of pyruvate
The glucose is converted to fructose
The glucose is phosphorylated
The first step of glycolysis consumes a molecule of ATP, removing one of the phosphate groups to make ADP. This phosphate group is added to glucose to make Glucose-6-phosphate, therefore glucose is phosphorylated.
Example Question #13 : Cellular Respiration And Photosynthesis
What enzyme converts glyceraldehyde-3-phosphate to 1, 3-bisphosphoglyceric acid during glycolysis?
Fructose-bisphosphate aldolase
Glyceraldehyde-3-phosphate dehydrogenase
Pyruvate kinase
Phosphoglycerate kinase
Enolase
Glyceraldehyde-3-phosphate dehydrogenase
The correct answer is glyceraldehyde-3-phosphate dehydrogenase. This enzyme sequesters a hydrogen from carbon 4 on glyceraldehyde 3-phosphate to reduce to , and in its place, an inorganic phosphate molecule is transferred to this position. Fructose-bisphosphate aldolase converts Fructose-1, 6-bisphosphate to glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. Pyruvate kinase converts phosphoenolpyruvate to pyruvate whereas enolase converts 2-phosphoglycerate to phosphoenolpyruvate. Phosphoglycerate kinase converts 1, 3-bisphosphoglycerate to 3-phosphoglycerate.
Example Question #14 : Cellular Respiration And Photosynthesis
Alcoholics often present with a deficiency in vitamin B1 (thiamine). What can you conclude about an alcoholic with thiamine deficiency?
I. He/she will not produce any pyruvate and NADH
II. There will be a buildup of lactic acid
III. He/she will not produce any acetyl-CoA from the breakdown of carbohydrates
III only
I and III
II and III
I only
II and III
Thiamine is an important vitamin required for the conversion of pyruvate to acetyl-CoA. It is an important cofactor for the pyruvate dehydrogenase, an enzyme important for the conversion of pyruvate to acetyl-CoA. Pyruvate and NADH from glycolysis will continue to be produced; however, they cannot go any further without thiamine. This means that cells can’t undergo Krebs cycle and oxidative phosphorylation to produce ATP.
The buildup of pyruvate and NADH will cause the pyruvate molecules to undergo fermentation and produce lactic acid. It also will oxidize NADH, the product of which is essential for several cellular processes and needs to be regenerated.
Example Question #16 : Cellular Respiration And Photosynthesis
Lactate dehydrogenase inhibitor is added to a mixture of cells. Which of the following molecules will build up inside a cell undergoing aerobic respiration?
Pyruvate
NADH
None of these molecules will build up
Both of these molecules will build up
None of these molecules will build up
The question states that the cell undergoes aerobic respiration. This means that the products from anaerobic respiration (glycolysis) will go through Krebs cycle and electron transport chain (aerobic respiration) to generate ATP. Lactate dehydrogenase is an enzyme important for converting the pyruvate molecules (from glycolysis) to lactate and oxidizing NADH. This reaction occurs in anaerobic fermentation when there is tissue hypoxia (decrease in oxygen).
If this inhibitor was placed in a cell that is deprived of oxygen, then there would be a buildup of pyruvate and NADH; however, since the inhibitor is added to cells undergoing aerobic respiration there will be no buildup. The pyruvate and NADH will undergo aerobic respiration and generate ATP. Note that red blood cells (RBCs) are unique in that they only use anaerobic respiration for ATP; therefore, adding lactate dehydrogenase inhibitor to RBCs will lead to a buildup of pyruvate and NADH.
Example Question #15 : Cellular Respiration And Photosynthesis
What is the rate-limiting enzyme for glycolysis?
Pyruvate carboxylase
Pyruvate kinase
Phosphofructokinase 1
Hexokinase
Phosphofructokinase 1
Glycolysis has three irreversible enzymatic steps that help the substrate intermediates proceed in one direction through the glycolytic pathway: the enzymes are hexokinase, phosphofructokinase 1, and pyruvate kinase. Of these three enzymes, the most important enzyme that controls the rate of glycolysis is phosphofructokinase 1, or PFK-1. Pyruvate carboxylase is not used in glycolysis, but in gluconeogenesis.
Example Question #1 : Help With The Krebs Cycle
Which of the following is not created in the Kreb's cycle?
ATP
NADH
FADH2
Acetyl CoA
Acetyl CoA
The Krebs cycle is responsible for creating three molecules of NADH, and one molecule of both ATP and NADH. Acetyl CoA is the 2-carbon molecule that enters the Krebs cycle following pyruvate decarboxylation.
Example Question #1 : Help With The Krebs Cycle
Each of the following enzymes is utilized in the citric acid cycle, except __________.
Aconitase
Phosphoglycerate kinase
Malate dehydrogenase
Fumarase
Citrate synthase
Phosphoglycerate kinase
Each of the enzymes is involved in the citric acid cycle except for phosphoglycerate kinase, which is an enzyme that is utilized in glycolysis and gluconeogenesis, and catalyzes the reversible transfer or a phosphate group from 1,3-bisphosphoglycerate to ADP, producing and/or consuming 3-phosphoglycerate and ATP.
Example Question #2 : Help With The Krebs Cycle
In what organ does gluconeogenesis primarily occur in vertebrates?
Lungs
Heart
Brain
Skin
Liver
Liver
Gluconeogenesis is the process in which glucose can be generated from carbon structures that are not the canonical carbohydrate inputs. This is required for many organisms to maintain appropriate blood glucose levels, and for vertebrates gluconeogenesis primarily occurs in the liver, although it has been found to occur in the kidneys as well.