The segments that represent decreases are the ones that go from upper left to lower right. There are four, and the steepest is the one between Monday and Tuesday. This is the correct response.

The dot representing Thursday is the only one of the seven that appears below 60 on the graph, so 6 is the correct response.

Only the three dots representing the peak temperatures of Sunday, Monday, and Tuesday are higher than the one representing that of Thursday, so the correct response is three.

Let's look at the line graph.

We can see the bottom axis displays the individual months. We can see the scale on the left displaying the number of enrollments.

So, to find the number of enrollments in January, we will first locate January on the bottom axis. We can see that it is the first one listed.

Now, we will see which number it corresponds with. We can see that it lines up with 10.

Therefore, the number of enrollments in January is 10.

Let's look at the graph:

If we look at the year 2013, we can see the data point is between 120 and 140.

We can also see that it is much closer to 140 than it is to 120. 

From looking at the location of the data point, we can approximate that there were 136 12th grade enrollments in 2013.

Start by finding the values for the first six months of the year.

In January, there was \(\displaystyle 1.25\) inches.

In February and March, there were \(\displaystyle 2.25\) inches per month.

In April, there was \(\displaystyle 4.75\) inches.

In May, there was \(\displaystyle 5.75\) inches.

In June, there was \(\displaystyle 6.5\) inches.

Recall how to find the average for a set of numbers:

\(\displaystyle \text{Average}=\frac{\text{Sum of all Values}}{\text{Number of Values}}\)

Plug in the values for the rainfall and divide by the number of values.

\(\displaystyle \text{Average}=\frac{1.25+2.25+2.25+4.75+5.75+6.5}{6}=3.79\)

Recall how to find the percent change for two values:

\(\displaystyle \text{Percent Change}=\frac{\text{New value-Old value}}{\text{Old value}}\times 100\%\)

The new value in this case would be the value from April, and the old value would be the value from March.

Plug in the correct values to find the percent change:

\(\displaystyle \text{Percent Change}=\frac{4.75-2.25}{2.25}\times 100\%=111.11\%\)

Start by finding the values from the last six months of the year.

Next, place these values in increasing order:

\(\displaystyle 1.5, 1.75, 2, 2.25, 3.5, 3.75\)

Since there is an even number of values, the median will be the number between the third and fourth terms. In this case, the median will be between \(\displaystyle 2\) and \(\displaystyle 2.25\).

The value in between those numbers is \(\displaystyle 2.125\).

Recall how to find the percent change:

\(\displaystyle \text{Percent Change}=\frac{\text{New value - Old value}}{\text{Old value}} \times 100\%\)

In this case, the new value is the number of attendees in May, and the old value is the number of attendees in April.

From the graph, you can see that there were \(\displaystyle 29000\) in May and \(\displaystyle 15000\) in April.

Plug these numbers into the equation to find the percent change.

\(\displaystyle \frac{29000-15000}{15000}\times 100\%=93.33\%\)

Start by looking at the graph and finding out how many attendees there were for the listed months.

There were \(\displaystyle 15000\) attendees in April, \(\displaystyle 29000\) in May, \(\displaystyle 30000\) in June, and \(\displaystyle 37000\) in July.

Now, the increase in attendees between April and May is \(\displaystyle 14000\), and the increase in attendees from June to July is \(\displaystyle 7000\).

Thus, the difference in the amount of increases is \(\displaystyle 7000\).