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GED Math : GED Math

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4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Geometry And Graphs

Find the radius of a circle with an area of $8\pi$ .

Possible Answers:

$4\sqrt2$

$2\sqrt2$

$8\sqrt2$

$\sqrt2$

Correct answer:

$2\sqrt2$

Explanation:

Write the formula for the area of a circle.

$A = \pi r^2$

Substitute the area.

$8\pi = \pi r^2$

Divide by pi on both sides.

$\frac{8\pi }{\pi}=\frac{ \pi r^2}{\pi}$

Square root both sides.

$\sqrt{r^2 }= \sqrt{8}$

$r= \sqrt8 = 2\sqrt2$

The answer is: $2\sqrt2$

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Example Question #14 : Radius And Diameter

Find the value of the diameter if the radius is $5\pi-2$ .

Possible Answers:

$10\pi -4$

$10\pi -2$

$5\pi -4$

$5\pi +4$

$10\pi +4$

Correct answer:

$10\pi -4$

Explanation:

The diameter is double the radius.

Multiply the quantity by two.

$2(5\pi-2) = 10\pi -4$

The answer is: $10\pi -4$

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Example Question #15 : Radius And Diameter

Determine the radius if the diameter is $\frac{\sqrt{2}}{3}$ .

Possible Answers:

$\frac{1}{3}$

$\frac{\sqrt2}{2}$

$\frac{2}{3}$

$2\sqrt2$

$\frac{\sqrt2}{6}$

Correct answer:

$\frac{\sqrt2}{6}$

Explanation:

The radius is half the diameter.

Multiply the diameter by half.

$\frac{\sqrt{2}}{3} \cdot\frac{1}{2}$

The answer is: $\frac{\sqrt2}{6}$

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Example Question #16 : Geometry And Graphs

Determine the radius of the circle if the diameter is $\frac{3\sqrt5}{7}$ .

Possible Answers:

$\frac{3\sqrt{10}}{14}$

$\frac{3\sqrt{10}}{7}$

$\frac{3\sqrt5}{14}$

$\frac{6\sqrt5}{7}$

$\textup{The answer is not given.}$

Correct answer:

$\frac{3\sqrt5}{14}$

Explanation:

The radius is half the diameter. To find the radius, multiply the diameter by half.

$\frac{3\sqrt5}{7} \cdot \frac{1}{2} = \frac{3\sqrt5}{14}$

The answer is: $\frac{3\sqrt5}{14}$

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Example Question #11 : Radius And Diameter

Determine the radius of the circle if the diameter of a circle is $\frac{3}{50}$ .

Possible Answers:

$\frac{3}{100}$

$\frac{9}{100}$

$\frac{9}{50}$

$\frac{3}{50}$

$\frac{3}{25}$

Correct answer:

$\frac{3}{100}$

Explanation:

The radius is half the diameter.

Multiply the diameter by one-half.

$\frac{3}{50} \cdot \frac{1}{2} = \frac{3}{100}$

The answer is: $\frac{3}{100}$

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Example Question #21 : Radius And Diameter

Find the diameter if the radius is $\sqrt5$ .

Possible Answers:

$5\sqrt2$

$\sqrt{10}$

$2\sqrt5$

Correct answer:

$2\sqrt5$

Explanation:

The diameter is double the radius.

d=2r

Multiply the radical by two.

$d=2r = 2\cdot \sqrt5$

Do not multiply the coefficient into the radical.

The answer is: $2\sqrt5$

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Example Question #984 : Ged Math

Determine the diameter if the radius is 6x-9 .

Possible Answers:

12x-9

12x-81

12x-18

36x-81

36x-9

Correct answer:

12x-18

Explanation:

The diameter is double the radius.

D=2r

Substitute the radius into the formula.

D=2(6x-9) = 12x-18

The answer is: 12x-18

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Example Question #22 : 2 Dimensional Geometry

A circle is circumscribed in a square as shown by the figure below.

If the area of the square is 144in^2 , what is the area of the circle in square inches? Use $\pi=3.14$ .

Possible Answers:

106.34

128.28

128.97

113.04

Correct answer:

113.04

Explanation:

Start by finding the length of a side of the square from the area.

$\text{Area}=\text{side}^2$

$\text{side}=\sqrt{\text{Area}}$

Plug in the area to find the length of the side.

$\text{side}=\sqrt{144}=12$

Now, notice that the diameter of the circle is the same as the length of a side of the square.

Thus, the diameter of the circle is , which means the radius is . Recall how to find the area of a circle:

$\text{Area}=\pi r^2$

$\text{Area}=\pi(6)^2=36\pi=113.04$

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Example Question #985 : Ged Math

Determine the diameter with a radius of $8\sqrt2$ .

Possible Answers:

$16\sqrt2$

$64\sqrt{2}$

$4\sqrt2$

Correct answer:

$16\sqrt2$

Explanation:

The diameter is double the radius.

d=2r

Substitute the radius.

$d=2(8\sqrt2) = 16\sqrt2$

The answer is: $16\sqrt2$

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Example Question #21 : Circles

Determine the radius if the diameter of a circle is: $\frac{3+\sqrt2}{3}$

Possible Answers:

$1+\sqrt2$

$1+\frac{\sqrt2}{4}$

$\frac{1}{2}+\frac{\sqrt2}{2}$

$\frac{3+\sqrt2}{6}$

$1+\frac{\sqrt2}{2}$

Correct answer:

$\frac{3+\sqrt2}{6}$

Explanation:

The radius is half the diameter.

Multiply the diameter by one-half.

$(\frac{3+\sqrt2}{3} )\cdot \frac{1}{2} = \frac{3+\sqrt2}{6}$

The answer is: $\frac{3+\sqrt2}{6}$

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All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

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GED Math : GED Math

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #11 : Geometry And Graphs

Example Question #14 : Radius And Diameter

Example Question #15 : Radius And Diameter

Example Question #16 : Geometry And Graphs

Example Question #11 : Radius And Diameter

Example Question #21 : Radius And Diameter

Example Question #984 : Ged Math

Example Question #22 : 2 Dimensional Geometry

Example Question #985 : Ged Math

Example Question #21 : Circles

All GED Math Resources

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