GED Math : GED Math

Study concepts, example questions & explanations for GED Math

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Example Questions

Example Question #3 : Central Angles And Arcs

A circle has area \(\displaystyle 81 \pi\). Give the length of a \(\displaystyle 90 ^{\circ }\) arc of the circle. 

Possible Answers:

\(\displaystyle \frac{9}{4} \pi\)

\(\displaystyle \frac{81}{4} \pi\)

\(\displaystyle \frac{9}{2} \pi\)

\(\displaystyle \frac{81}{16} \pi\)

Correct answer:

\(\displaystyle \frac{9}{2} \pi\)

Explanation:

The radius \(\displaystyle r\) of a circle, given its area \(\displaystyle A\), can be found using the formula 

\(\displaystyle A = \pi r^{2}\)

Set \(\displaystyle A= 81 \pi\):

\(\displaystyle \pi r^{2} = 81 \pi\)

Find \(\displaystyle r\) by dividing both sides by \(\displaystyle \pi\) and then taking the square root of both sides:

\(\displaystyle \pi r^{2} \div \pi = 81 \pi \div \pi\)

\(\displaystyle r^{2} = 81\)

\(\displaystyle r = \sqrt{81} = 9\)

The circumference of this circle is found using the formula

\(\displaystyle C = 2 \pi r\):

\(\displaystyle C = 2 \pi (9)\)

\(\displaystyle C= 18 \pi\)

\(\displaystyle 90 ^{\circ }\) arc of the circle is one fourth of the circle, so the length of the arc is 

\(\displaystyle L = \frac{1}{4}C\)

\(\displaystyle = \frac{1}{4} \cdot 18 \pi\)

\(\displaystyle = \frac{9}{2} \pi\)

Example Question #1 : Central Angles And Arcs

If a sector covers \(\displaystyle \frac{4}{5}\) of the area of a given circle, what is the measure of that sector's central angle?

Possible Answers:

\(\displaystyle 144^{\circ}\)

\(\displaystyle 728^{\circ}\)

\(\displaystyle 288^{\circ}\)

Not enough information given.

Correct answer:

\(\displaystyle 288^{\circ}\)

Explanation:

If a sector covers \(\displaystyle \frac{4}{5}\) of the area of a given circle, what is the measure of that sector's central angle?

 

While this problem may seem to not have enough information to solve, we actually have everything we need.

To find the measure of a central angle, we don't need to know the actual area of the sector or the circle. Instead, we just need to know what fraction of the circle we are dealing with. In this case, we are told that the sector represents four fifths of the circle. 

All circles have 360 degrees, so if our sector is four fifths of that, we can find the answer via the following.

\(\displaystyle \measuredangle =\frac{4}{5}(360^{\circ})=288^{\circ}\)

So our answer is:

\(\displaystyle 288^{\circ}\)

Example Question #2 : Central Angles And Arcs

Sector

Figure is not drawn to scale.

What percent of the  circle has not been shaded?

Possible Answers:

\(\displaystyle 75 \%\)

\(\displaystyle 72 \%\)

\(\displaystyle 66\frac{2}{3} \%\)

\(\displaystyle 60 \%\)

Correct answer:

\(\displaystyle 60 \%\)

Explanation:

The total number of degrees in a circle is \(\displaystyle 360^{\circ }\), so the shaded sector represents \(\displaystyle \frac{144^{\circ }}{360^{\circ }}\) of the circle. In terms of percent, this is 

\(\displaystyle \frac{144^{\circ }}{360^{\circ }} \times 100 \% = \frac{14,400^{\circ }}{360^{\circ }} \%= 40\%\).

The shaded sector is 40% if the circle, so the unshaded sector is \(\displaystyle 100 \% - 40\% = 60\%\) of the circle.

Example Question #1141 : Ged Math

If \(\displaystyle \Delta MNO \cong \Delta PQR\), then which segment is congruent to \(\displaystyle \overline{NO}\) ?

Possible Answers:

\(\displaystyle \overline{RQ}\)

\(\displaystyle \overline{RP}\)

\(\displaystyle \overline{MO}\)

\(\displaystyle \overline{NQ}\)

Correct answer:

\(\displaystyle \overline{RQ}\)

Explanation:

A congruency statement about two triangles implies nothing about the relationship between two sides of the same triangle, so we can eliminate \(\displaystyle \overline{MO}\). Also, the length of a segment with endpoints on two different  triangles depends on their positioning, not their congruence, so we can eliminate \(\displaystyle \overline{NQ}\).

Since \(\displaystyle N\) and \(\displaystyle O\) are in the same positions in the name of the first triangle as \(\displaystyle Q\) and \(\displaystyle R\)\(\displaystyle \overline{NO}\) and \(\displaystyle \overline{QR}\) are corresponding sides of congruent triangles, and 

\(\displaystyle \overline{NO} \cong \overline{QR}\)

Since the letters of the name of a segment are interchangeable, this statement can be rewritten as

\(\displaystyle \overline{NO} \cong \overline{RQ}\),

making \(\displaystyle \overline{RQ}\) the correct choice.

Example Question #1142 : Ged Math

A triangle has sides of length 36 inches, 3 feet, and one yard. Choose the statement that most accurately describes this triangle.

Possible Answers:

More information is needed to answer this question.

This triangle is scalene.

This triangle is isosceles but not equilateral.

This triangle is equilateral.

Correct answer:

This triangle is equilateral.

Explanation:

One yard is equal to three feet, or thirty-six inches. The three given sidelengths are equal to one another, making this an equilateral triangle.

Example Question #1141 : Ged Math

Right_triangle

Note: Figure NOT drawn to scale.

Refer to the above diagram. Evaluate \(\displaystyle X\).

Possible Answers:

\(\displaystyle x = 10 \frac{12}{13}\)

\(\displaystyle X = 11\frac{1}{13}\)

\(\displaystyle X= 10 \frac{1}{12}\)

\(\displaystyle x = 10\)

Correct answer:

\(\displaystyle X = 11\frac{1}{13}\)

Explanation:

The altitude perpendicular to the hypotenuse of a right triangle divides that triangle into two smaller triangles similar to each other and the large triangle. Therefore, the sides are in proportion. The hypotenuse of the triangle is equal to

\(\displaystyle \sqrt{5^{2}+12^{2}} = \sqrt{25+144} = \sqrt{169} =13\).

Therefore, we can set up a proportion and solve for \(\displaystyle X\):

\(\displaystyle \frac{X}{12} = \frac{12}{13}\)

\(\displaystyle \frac{X}{12}\cdot 12 = \frac{12}{13} \cdot 12\)

\(\displaystyle X = \frac{144}{13} = 11\frac{1}{13}\)

Example Question #2 : Perimeter And Sides Of Triangles

If the base of an equilateral triangle is 16cm, find the perimeter.

Possible Answers:

\(\displaystyle 56\text{cm}\)

\(\displaystyle 48\text{cm}\)

\(\displaystyle 64\text{cm}\)

\(\displaystyle \text{There is not enough information to solve the problem.}\)

\(\displaystyle 32\text{cm}\)

Correct answer:

\(\displaystyle 48\text{cm}\)

Explanation:

To find the perimeter of a triangle, we will use the following formula:

\(\displaystyle P = a+b+c\)

where a, b, and c are the lengths of the sides of the triangle.

 

Now, we know the base of the triangle is 16cm. Because it is an equilateral triangle, all sides are equal. Therefore, all sides are 16cm.  So, we get

\(\displaystyle P = 16\text{cm} +16\text{cm} +16\text{cm}\)

\(\displaystyle P = 48\text{cm}\)

Example Question #1 : Triangles

The perimeter of an equilateral triangle is 36in.  Find the length of one side.

Possible Answers:

\(\displaystyle 12\text{in}\)

\(\displaystyle 14\text{in}\)

\(\displaystyle 11\text{in}\)

\(\displaystyle 13\text{in}\)

\(\displaystyle 9\text{in}\)

Correct answer:

\(\displaystyle 12\text{in}\)

Explanation:

The formula to find the perimeter of an equilateral triangle is

\(\displaystyle P = 3a\)

where a is the length of one side of the triangle. Because it is an equilateral triangle, all sides are equal. Therefore, we can use any side in the formula. To find the length of one side, we will solve for a.

Now, we know the perimeter of the equilateral triangle is 36in. So, we will substitute and solve for a. We get

\(\displaystyle 36\text{in} = 3a\)

 

\(\displaystyle \frac{36\text{in}}{3} = \frac{3a}{3}\)

 

\(\displaystyle 12\text{in} = a\)

 

\(\displaystyle a = 12\text{in}\)

 

Therefore, the length of one side of the equilateral triangle is 12in.

Example Question #3 : Triangles

Find the perimeter of an equilateral triangle with a side having a length of 17in.

Possible Answers:

\(\displaystyle 34\text{in}\)

\(\displaystyle 51\text{in}\)

\(\displaystyle 28\text{in}\)

\(\displaystyle 42\text{in}\)

\(\displaystyle 48\text{in}\)

Correct answer:

\(\displaystyle 51\text{in}\)

Explanation:

To find the perimeter of a triangle, we will use the following formula:

\(\displaystyle P = a+b+c\)

where a, b, and c are the lengths of the sides of the triangle.

Now, we know one side of the triangle has a length of 17in. Because it is an equilateral triangle, all sides are equal. Therefore, all sides are 17in. So, we can substitute. We get

\(\displaystyle P = 17\text{in} +17\text{in} +17\text{in}\)

\(\displaystyle P = 51\text{in}\)

Example Question #1 : Perimeter And Sides Of Triangles

An equilateral triangle has a perimeter of 69in.  Find the length of one side.

Possible Answers:

\(\displaystyle 18\text{in}\)

\(\displaystyle 33\text{in}\)

\(\displaystyle 36\text{in}\)

\(\displaystyle 32\text{in}\)

\(\displaystyle 23\text{in}\)

Correct answer:

\(\displaystyle 23\text{in}\)

Explanation:

The formula to find the perimeter of an equilateral triangle is

\(\displaystyle P = 3a\)

where a is the length of one side of the triangle. Because an equilateral triangle has 3 equal sides, we can use any side in the formula. To find the length of one side, we will solve for a.

Now, we know the perimeter of the triangle is 69in. So, we can substitute and solve for a. We get

\(\displaystyle 69\text{in} = 3a\)

 

\(\displaystyle \frac{69\text{in}}{3} = \frac{3a}{3}\)

 

\(\displaystyle 23\text{in} = a\)

 

\(\displaystyle a = 23\text{in}\)

Therefore, the length of one side of the equilateral triangle is 23in.

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