All GED Math Resources
Example Questions
Example Question #33 : Slope Intercept Form
Find the slope of the line perpendicular to the line:
Remember that the slopes of perpendicular lines are each other's negative reciprocal.
To find the negative reciprocal of a number, we put it into fraction form, invert the numerator and the denominator, and negate the result.
For example:
(invert the numerator and denominator)
(negate the result)
In our example, the slope of our equation is
(invert the numerator and denominator)
(negate the result)
Therefore, the slope of a line perpendicular to the line is
Example Question #34 : Slope Intercept Form
Which line is parallel to the line ?
Parallel lines have identical slopes. The y-intercept, in this case, is irrelevant.
The line which has the same slope as is:
Example Question #35 : Slope Intercept Form
Given two points of a line with the y-intercept , write the equation of the line in slope-intercept form.
In our equation , we need to find the slope, , and the y-intercept, .
To find the slope of a line given two points, , we have our slope formula:
So, given , we can find the slope by substituting those values into our slope formula:
Our y-intercept was given as , so,
We have our and our , so the answer is
Example Question #36 : Slope Intercept Form
Put the following equation, which is in slope-intercept form, into standard form:
A linear equation in standard form is represented by:
In our equation, , we can arrange these values to get it into its standard form:
(add to both sides)
Or, , which is in the form
Example Question #37 : Slope Intercept Form
In the equation , find the slope and y-intercept.
First, get the equation into slope-intercept form
(divide both sides by 6)
We can clearly see the y-intercept as
For the slope, notice that there is an invisible coefficient of in front of the . That is our slope.
Example Question #38 : Slope Intercept Form
Arrange this linear equation so it is in slope-intercept form:
The slope-intercept form of a line is represented as:
To rearrange into form, we must get by itself.
1) (add to and subtract from both sides)
2)
3) (divide both sides by )
4)
Example Question #39 : Slope Intercept Form
Rearrange the following equation, which is in its standard form, into slope-intercept form:
Recall that our slope-intercept form is
First, we get the term by itself:
(subtract from both sides)
Then:
(multiply both sides by the reciprocal of the coefficient)
Our answer is
Example Question #40 : Slope Intercept Form
Which line is parallel to ?
You may know that parallel lines have the same slope. With that in mind, it may be tempting to see that there and find an equation with and a different y-intercept.
Be careful of that trap! Notice that equation is written in STANDARD form, and to find the slope of a line we must get it into slope-intercept form,
Arranging the equation into slope-intercept form, we see that we get
Our slope is , so a line parallel could be , one of our choices.
Example Question #41 : Slope Intercept Form
What identification mistake(s), if any, did this student make?
The slope, , is and the y-intercept, , is
The slope, , is correct..
The y-intercept, , is correct.
After dividing both sides by , the student neglected to divide the -value by , as well. So the slope was incorrect. It should be
The y-intercept, , is correct.
The slope, , is correct.
After dividing both sides by , the student should not have divided the y-intercept, , by . The y-intercept is incorrect.
The student should have put it in standard form to find the slope and y-intercept.
After dividing both sides by , the student neglected to divide the -value by , as well. So the slope was incorrect. It should be
The y-intercept, , is correct.
The student was correct in the attempt to get the equation into slope-intercept form, by dividing by on both sides.
The slope should have been:
The y-intercept was correct in being:
Example Question #41 : Linear Algebra
What is the equation of the line that goes through the points and ?
Start by finding the slope of the line.
Recall how to find the slope:
Using the given points,
Now, we can write the equation for the line as the following:
, where is the y-intercept that we still need to find.
Take one of the points and plug it into the equation for and , then solve for .
Using the point ,
Thus, the equation of the line must be