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GED Math : Single-Variable Algebra

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4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #41 : Solving For The Variable

Solve for x.

$\frac{x}{12} = 11$

Possible Answers:

x=121

x=13

x=23

x=144

x=132

Correct answer:

x=132

Explanation:

To solve for x, we want x to stand alone. So, we get

$\frac{x}{12} = 11$

$\frac{x}{12} \cdot 12 = 11 \cdot 12$

x = 132

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Example Question #42 : Solving For The Variable

Solve for : 2x-5 = 3x-2

Possible Answers:

$-\frac{3}{5}$

$\frac{7}{5}$

$-\frac{7}{5}$

Correct answer:

Explanation:

Subtract from both sides.

2x-5 -2x= 3x-2-2x

-5 = x-2

Add 2 on both sides.

-5+2 = x-2+2

-3 =x

The answer is:

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Example Question #43 : Solving For The Variable

Which of the following makes this equation true:

7y+19=75

Possible Answers:

y=19

y=7

y=8

y=9

y=12

Correct answer:

y=8

Explanation:

To answer the question, we will solve for y. We get

7y+19=75

7y+19-19=75-19

7y+0=56

7y=56

$\frac{7y}{7} = \frac{56}{7}$

y=8

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Example Question #44 : Solving For The Variable

Solve the following equation: 8x-15 = -3

Possible Answers:

$\frac{3}{2}$

$\textup{The answer is not given.}$

$-\frac{9}{4}$

$-\frac{3}{2}$

$\frac{9}{4}$

Correct answer:

$\frac{3}{2}$

Explanation:

Add 15 on both sides.

8x-15+15 = -3+15

Simplify both sides of the equation.

8x = 12

Divide by 8 on both sides.

$\frac{8x}{8} = \frac{12}{8}$

Reduce the fractions.

The answer is: $\frac{3}{2}$

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Example Question #45 : Solving For The Variable

Solve for : 2h+6=4h+3

Possible Answers:

$\frac{3}{2}$

$\frac{1}{3}$

$\frac{9}{2}$

$\frac{4}{3}$

$\frac{2}{3}$

Correct answer:

$\frac{3}{2}$

Explanation:

Subtract from both sides.

2h+6-2h=4h+3-2h

6= 2h+3

Subtract 3 from both sides.

6-3= 2h+3-3

3=2h

Divide by 2 on both sides.

$\frac{3}{2}=\frac{2h}{2}$

The answer is: $\frac{3}{2}$

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Example Question #46 : Solving For The Variable

Solve for : $\frac{1}{8}x+3=-5$

Possible Answers:

Correct answer:

Explanation:

Subtract 3 from both sides.

$\frac{1}{8}x+3-3=-5-3$

$\frac{1}{8}x = -8$

Multiply by eight on both sides to isolate the variable.

$\frac{1}{8}x \cdot 8= -8\cdot 8$

x=-64

The answer is:

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Example Question #47 : Solving For The Variable

Solve for j in the following equation:

$\frac{12j}{8} = 18$

Possible Answers:

j=2

j=9

j=4

j=8

j=12

Correct answer:

j=12

Explanation:

To solve for j, we want j to stand alone. So, we get

$\frac{12j}{8} = 18$

$\frac{12j}{8} \cdot 8 = 18 \cdot 8$

12j = 144

$\frac{12j}{12} = \frac{144}{12}$

j = 12

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Example Question #48 : Solving For The Variable

Solve for : 2(3x-5) = 11

Possible Answers:

$\frac{15}{6}$

$-\frac{1}{6}$

$\frac{1}{6}$

$\frac{7}{2}$

$\frac{1}{5}$

Correct answer:

$\frac{7}{2}$

Explanation:

Distribute the two through the both terms inside the binomial on the left.

6x-10 = 11

Add 10 on both sides.

6x-10+10 = 11+10

6x = 21

Divide by 6 on both sides.

$\frac{6x}{6} =\frac{ 21}{6}$

Reduce both fractions.

The answer is: $\frac{7}{2}$

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Example Question #49 : Solving For The Variable

Solve the equation: $\frac{4}{x} = -3$

Possible Answers:

$-\frac{1}{12}$

$-\frac{1}{3}$

$-\frac{3}{4}$

$-\frac{4}{3}$

Correct answer:

$-\frac{4}{3}$

Explanation:

Multiply by on both sides.

$\frac{4}{x}\cdot x = -3\cdot x$

4= -3x

Divide by negative three on both sides.

$\frac{4}{-3}=\frac{ -3x}{-3}$

The answer is: $-\frac{4}{3}$

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Example Question #50 : Solving For The Variable

Solve: $-8x=\frac{4}{5}$

Possible Answers:

$\frac{44}{5}$

$\frac{36}{5}$

$-\frac{1}{10}$

$-\frac{2}{5}$

$-\frac{32}{5}$

Correct answer:

$-\frac{1}{10}$

Explanation:

Divide by negative eight on both sides. This is similar to multiply negative one-eighths on both sides.

$-8x\cdot -\frac{1}{8}=\frac{4}{5}\cdot -\frac{1}{8}$

$x = -\frac{1}{10}$

The answer is: $-\frac{1}{10}$

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GED Math : Single-Variable Algebra

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #41 : Solving For The Variable

Example Question #42 : Solving For The Variable

Example Question #43 : Solving For The Variable

Example Question #44 : Solving For The Variable

Example Question #45 : Solving For The Variable

Example Question #46 : Solving For The Variable

Example Question #47 : Solving For The Variable

Example Question #48 : Solving For The Variable

Example Question #49 : Solving For The Variable

Example Question #50 : Solving For The Variable

All GED Math Resources

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