We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

GED Math : Squares, Rectangles, and Parallelograms

Study concepts, example questions & explanations for GED Math

Create An Account

All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 7 8 9 10 11 Next →

Example Question #301 : Geometry And Graphs

Garden

Note: Figure NOT drawn to scale

Refer to the above figure, which shows a rectangular garden (in green) surrounded by a dirt path (in brown). The dirt path is six feet wide throughout. Which of the following polynomials gives the perimeter of the garden, in feet?

Possible Answers:

3x-24

6x-48

6x-24

3x-48

Correct answer:

6x-48

Explanation:

The length of the garden, in feet, is $2 \times 6 = 12$ feet less than that of the entire lot, or

L = 2x-12 .

The width of the garden, in feet, is $2 \times 6 = 12$ less than that of the entire lot, or

W = x-12 .

The perimeter, in feet, is twice the sum of the two:

P = 2 (L + W)

= 2 (2x-12 + x - 12 )= 2 (3x-24) = 6x - 48

Report an Error

Example Question #302 : Geometry And Graphs

Given Square ABCD , the distance from to is one mile. Which of the following gives the perimeter of the square, to the nearest foot?

Possible Answers:

$7,467\textrm{ ft}$

$29,868\textrm{ ft}$

$10,560\textup{ ft}$

$14,934\textrm{ ft}$

Correct answer:

$14,934\textrm{ ft}$

Explanation:

The segment $\overline{AC}$ is a diagonal of the square. It is also the hypotenuse of a right triangle whose legs both measure the same length, which we will call ; this is also the length of one side of the square.

The right triangle formed is an isosceles triangle - and, subsequently, a $45^{\circ }-45^{\circ }-90^{\circ }$ triangle - and therefore,

$s \sqrt{2} = AC$

$\overline{AC}$ is one mile, or 5,280 feet, long, so we substitute AC = 5,280 and solve for :

$s \sqrt{2} = 5,280$

$s = 5,280 \div \sqrt{2} \approx 5,280 \div 1.414 \approx 3,733.5$

The perimeter, in feet, is four times this, or

$P = 4s \approx 4 \times 3,733.5 \approx 14,934$ feet.

Report an Error

Example Question #303 : Geometry And Graphs

The length of each side of a square is increased by 12%. By what percent has its perimeter increased?

Possible Answers:

$44 \%$

$48 \%$

$12 \%$

$24 \%$

Correct answer:

$12 \%$

Explanation:

Let be the original sidelength of the square. Increasing this by 12% is the same as adding 0.12 times that sidelength to the original sidelength. The new sidelength is therefore

s + 0.12s = 1.12s .

The perimeter of a square is four times its sidelength. Its original perimeter was ; after the increase, it is $4 \cdot 1.12s = 4.48 s$ . The percent of increase is therefore

$\frac{4.48s - 4s }{4s} \times 100 \% = \frac{0.48 s}{4s} \times 100 \% = 0.12 \times 100 \% = 12 \%$ .

Report an Error

Example Question #304 : Geometry And Graphs

The perimeter of a square is 24cm. Find the length of one side of the square.

Possible Answers:

$7\text{cm}$

$3\text{cm}$

$\text{There is not enough information to answer the question.}$

$4\text{cm}$

$6\text{cm}$

Correct answer:

$6\text{cm}$

Explanation:

The formula to find the perimeter of a square is

P = 4a

where a is the length of any side of the square. Because a square has 4 equal sides, we can use any side in the formula. To find the length of one side of the square, we will solve for a.

Now, we know the perimeter of the square is 24cm. So, we will substitute and solve for a. We get

$24\text{cm} = 4a$

$\frac{24\text{cm}}{4} = \frac{4a}{4}$

$6\text{cm} = a$

$a = 6\text{cm}$

Therefore, the length of one side of the square is 6cm.

Report an Error

Example Question #305 : Geometry And Graphs

Find the perimeter of a rectangle with a width of 8in and a length that is two times the width.

Possible Answers:

$16\text{in}$

$64\text{in}$

$36\text{in}$

$48\text{in}$

$24\text{in}$

Correct answer:

$48\text{in}$

Explanation:

To find the perimeter of a rectangle, we will use the following formula:

P = 2l + 2w

Where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 8in. We also know the length is two times the width. Therefore, the length is 16in. So, we can substitute. We get

$P = 2(16\text{in}) + 2(8\text{in})$

$P = 32\text{in} + 16\text{in}$

$P = 48\text{in}$

Report an Error

Example Question #306 : Geometry And Graphs

Find the perimeter of a square with a length of 8cm.

Possible Answers:

$48\text{cm}$

$64\text{cm}$

$16\text{cm}$

$24\text{cm}$

$32\text{cm}$

Correct answer:

$32\text{cm}$

Explanation:

To find the perimeter of a square, we will use the following formula:

P = 4a

where a is the length of one side of the square. Because a square has 4 equal sides, we can use any side in the formula.

Now, we know the length of the square is 8cm. So, we can substitute. We get

$P = 4 \cdot 8\text{cm}$

$P = 32\text{cm}$

Report an Error

Example Question #307 : Geometry And Graphs

The perimeter of a square is 72in. Find the length of one side.

Possible Answers:

$9\text{in}$

$36\text{in}$

$18\text{in}$

$54\text{in}$

$16\text{in}$

Correct answer:

$18\text{in}$

Explanation:

To answer this, we will look at the formula for perimeter of a square. We get

P = 4a

where a is the length of one side of the square. Because a square has 4 equal sides, we can use any side in the formula. To find the length of one side, we will solve for a. Now, we know the perimeter of the square is 72\text{in}. So, we will substitute and solve for a. We get

$72\text{in} = 4a$

$\frac{72\text{in}}{4} = \frac{4a}{4}$

$18\text{in} = a$

$a = 18\text{in}$

Therefore, the length of one side of the square is 18in.

Report an Error

Example Question #308 : Geometry And Graphs

The area of a square is $25\text{cm}^2$ . Find the perimeter.

Possible Answers:

$5\text{cm}$

$\text{There is not enough information to solve the problem.}$

$25\text{cm}$

$30\text{cm}$

$20\text{cm}$

Correct answer:

$20\text{cm}$

Explanation:

A square has 4 equal sides. To find the perimeter of the square, we first have to find the length of one side of the square.

Now, we know the area of the square. The formula for area of a square is

A = b^2

where b is the length of one side of the square. To find the length of one side, we will solve for b. Now, we know the area is $25\text{cm}^2$ . So, we will substitute and solve for b.

$25\text{cm}^2 = b^2$

$\sqrt{25\text{cm}^2} = \sqrt{b^2}$

$5\text{cm} = b$

$b = 5\text{cm}$

Therefore, the length of one side of the square is 5cm.

Now, to find the perimeter of a square, we will use the following formula:

P = 4b

where b is the length of one side of the square. Now, we know the length of one side of the square is 5cm. So, we can substitute. We get

$P = 4 \cdot 5\text{cm}$

$P = 20\text{cm}$

Therefore, the perimeter of the square is 20cm.

Report an Error

Example Question #309 : Geometry And Graphs

Find the perimeter of a rectangle with a length of 9in and a width that is a third of the length.

Possible Answers:

$15\text{in}$

$18\text{in}$

$12\text{in}$

$24\text{in}$

$27\text{in}$

Correct answer:

$24\text{in}$

Explanation:

To find the perimeter of a rectangle, we will use the following formula:

P = 2l + 2w

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 9in. We also know the width is a third of the length. Therefore, the width is 3in. So, we can substitute. We get

$P = 2(9\text{in}) + 2(3\text{in})$

$P = 18\text{in} + 6\text{in}$

$P = 24\text{in}$

Report an Error

Example Question #311 : Geometry And Graphs

The perimeter of a square is 68in. Find the length of one side.

Possible Answers:

$17\text{in}$

$13\text{in}$

$14\text{in}$

$16\text{in}$

$\text{There is not enough information to solve the problem.}$

Correct answer:

$17\text{in}$

Explanation:

A square has 4 equal sides. To find the perimeter of a square, we will use the following formula:

P = 4a

where a is the length of one side of the square. Because a square has 4 equal sides, we can use any side in the formula. To find the length of one side, we will solve for a.

Now, we know the perimeter of the square is 68in. So, we can substitute and solve for a.

$68\text{in} = 4a$

$\frac{68\text{in}}{4} = \frac{4a}{4}$

$17\text{in} = a$

$a = 17\text{in}$

Therefore, the length of one side of the square is 17in.

Report an Error

← Previous 1 2 3 4 5 6 7 8 9 10 11 Next →

View Tutors

Dawn
Certified Tutor

University of Oregon, Bachelor in Arts, Biochemistry and Molecular Biology. Johns Hopkins University, Doctor of Philosophy, E...

View Tutors

Alison
Certified Tutor

University of Illinois at Urbana-Champaign, Bachelor of Science, Accounting.

View Tutors

edward
Certified Tutor

University of South Florida-Main Campus, Bachelor in Business Administration, Business Administration and Management.

All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

French Tutors in Philadelphia, Physics Tutors in San Francisco-Bay Area, Reading Tutors in Philadelphia, MCAT Tutors in Atlanta, Computer Science Tutors in San Francisco-Bay Area, MCAT Tutors in Dallas Fort Worth, ACT Tutors in Washington DC, SSAT Tutors in Los Angeles, Reading Tutors in Houston, Calculus Tutors in San Francisco-Bay Area

Popular Courses & Classes

ISEE Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Phoenix, SAT Courses & Classes in San Diego, LSAT Courses & Classes in Chicago, GMAT Courses & Classes in Boston, Spanish Courses & Classes in Miami, ISEE Courses & Classes in San Diego, MCAT Courses & Classes in Philadelphia, MCAT Courses & Classes in Miami, GMAT Courses & Classes in Phoenix

Popular Test Prep

GMAT Test Prep in Phoenix, ISEE Test Prep in New York City, ISEE Test Prep in Boston, MCAT Test Prep in Chicago, GMAT Test Prep in Boston, SSAT Test Prep in Houston, ACT Test Prep in New York City, SAT Test Prep in Denver, SSAT Test Prep in Los Angeles, ACT Test Prep in Atlanta

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

GED Math : Squares, Rectangles, and Parallelograms

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #301 : Geometry And Graphs

Example Question #302 : Geometry And Graphs

Example Question #303 : Geometry And Graphs

Example Question #304 : Geometry And Graphs

Example Question #305 : Geometry And Graphs

Example Question #306 : Geometry And Graphs

Example Question #307 : Geometry And Graphs

Example Question #308 : Geometry And Graphs

Example Question #309 : Geometry And Graphs

Example Question #311 : Geometry And Graphs

All GED Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: