Common Core: High School - Number and Quantity : High School: Number and Quantity

Study concepts, example questions & explanations for Common Core: High School - Number and Quantity

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All Common Core: High School - Number and Quantity Resources

6 Diagnostic Tests 49 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #3 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (1,1)\) , and an initial point of \(\displaystyle (-6,-9)\)?

Possible Answers:

\(\displaystyle < 7,10>\)

\(\displaystyle < -10,-7>\)

\(\displaystyle < -7,-10>\)

\(\displaystyle < 10,7>\)

\(\displaystyle < 0,0>\)

Correct answer:

\(\displaystyle < 7,10>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=1 \\ \mbox{(x in initial point)}=-6 \\ \mbox{(y in terminal point)}=1\\ \mbox{(y in initial point)}= -9\)

\(\displaystyle x=1-(-6)=1+6=7\)

\(\displaystyle y=1-(-9)=1+9=10\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < 7,10>\)

 

Below is a visual representation of what we just did.

Screen shot 2016 03 15 at 10.39.47 am

Example Question #4 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (-9,1)\), and an initial point of \(\displaystyle (5,-10)\)?

Possible Answers:

\(\displaystyle < -14,-11>\)

\(\displaystyle < 11,-14>\)

\(\displaystyle < 14,-11>\)

\(\displaystyle < 11,14>\)

\(\displaystyle < -14,11>\)

Correct answer:

\(\displaystyle < -14,11>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=-9 \\ \mbox{(x in initial point)}=2 \\ \mbox{(y in terminal point)}=1\\ \mbox{(y in initial point)}= -10\)

\(\displaystyle x=-9-5=-14\)

\(\displaystyle y=1-(-10)=1+10=11\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < -14,11>\)

 

Below is a visual representation of what we just did.

Screen shot 2016 03 15 at 10.52.08 am

Example Question #5 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (3,-8)\), and an initial point of \(\displaystyle (6,-13)\)?

Possible Answers:

\(\displaystyle < -3,5>\)

\(\displaystyle < 5,-3>\)

\(\displaystyle < 9,-21>\)

\(\displaystyle < -21,9>\)

\(\displaystyle < -5,-7>\)

Correct answer:

\(\displaystyle < -3,5>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=3 \\ \mbox{(x in initial point)}=6 \\ \mbox{(y in terminal point)}=-8\\ \mbox{(y in initial point)}= -13\)

\(\displaystyle x=3-6=-3\)

\(\displaystyle y=-8-(-13)=-8+13=5\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < -3,5>\)

 

Below is a visual representation of what we just did.

Screen shot 2016 03 15 at 12.32.48 pm

Example Question #6 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (-1,-5)\), and an initial point of \(\displaystyle (-4,-9)\)?

Possible Answers:

\(\displaystyle < 3,4>\)

\(\displaystyle < 4,5>\)

\(\displaystyle < 8,-1>\)

\(\displaystyle < -4,3>\)

\(\displaystyle < 4,3>\)

Correct answer:

\(\displaystyle < 3,4>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=-1 \\ \mbox{(x in initial point)}=-4 \\ \mbox{(y in terminal point)}=-5\\ \mbox{(y in initial point)}= -9\)

\(\displaystyle x=-1-(-4)=-1+4=3\)

\(\displaystyle y=-5-(-9)=-5+9=4\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < 3,4>\)

 

Below is a visual representation of what we just did.

Screen shot 2016 03 16 at 12.09.51 pm

Example Question #1 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (-3,10)\), and an initial point of \(\displaystyle (-4,12)\)?

Possible Answers:

\(\displaystyle < 14,-15>\)

\(\displaystyle < -15,14>\)

\(\displaystyle < 1,-2>\)

\(\displaystyle < -2,1>\)

\(\displaystyle < 1,2>\)

Correct answer:

\(\displaystyle < 1,-2>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=-3 \\ \mbox{(x in initial point)}=-4 \\ \mbox{(y in terminal point)}=10\\ \mbox{(y in initial point)}=12\)

\(\displaystyle x=-3-(-4)=-3+4=1\)

\(\displaystyle y=10-12=-2\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < 1,-2>\)

 

Below is a visual representation of what we just did.


Screen shot 2016 03 16 at 12.32.22 pm

Example Question #2 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (1,9)\), and an initial point of \(\displaystyle (-7,5)\)?

Possible Answers:

\(\displaystyle < 8,14>\)

\(\displaystyle < -6,4>\)

\(\displaystyle < 4,6>\)

\(\displaystyle < 4,-6>\)

\(\displaystyle < 8,4>\)

Correct answer:

\(\displaystyle < 8,4>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=1 \\ \mbox{(x in initial point)}=-7 \\ \mbox{(y in terminal point)}=9\\ \mbox{(y in initial point)}= 5\)

\(\displaystyle x=1-(-7)=1+7=8\)

\(\displaystyle y=9-5=4\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < 8,4>\)

 

Below is a visual representation of what we just did.

Screen shot 2016 03 16 at 12.41.19 pm

Example Question #3 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (4,6)\), and an initial point of \(\displaystyle (0,-8)\)?

Possible Answers:

\(\displaystyle < 6,12>\)

\(\displaystyle < -2,8>\)

\(\displaystyle < 4,14>\)

\(\displaystyle < 14,4>\)

\(\displaystyle < 12,6>\)

Correct answer:

\(\displaystyle < 4,14>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=4 \\ \mbox{(x in initial point)}=0 \\ \mbox{(y in terminal point)}=6\\ \mbox{(y in initial point)}= -8\)

\(\displaystyle x=4-0=4\)

\(\displaystyle y=6-(-8)=6+8=14\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < 4,14>\)

 

Below is a visual representation of what we just did.


Screen shot 2016 03 16 at 1.16.38 pm

Example Question #4 : Vector Components: Ccss.Math.Content.Hsn Vm.A.2

What are the components of a vector that has a terminal point of \(\displaystyle (3,-6)\), and an initial point of \(\displaystyle (10,5)\)?

Possible Answers:

\(\displaystyle < 8,-4>\)

\(\displaystyle < -11,-7>\)

\(\displaystyle < 8,4>\)

\(\displaystyle < -8,4>\)

\(\displaystyle < -7,-11>\)

Correct answer:

\(\displaystyle < -7,-11>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=3 \\ \mbox{(x in initial point)}=10 \\ \mbox{(y in terminal point)}=-6\\ \mbox{(y in initial point)}=5\)

\(\displaystyle x=3-10=-7\)

\(\displaystyle y=-6-5=-11\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < -7,-11>\)

 

Below is a visual representation of what we just did.

 


Screen shot 2016 03 16 at 1.27.32 pm

Example Question #113 : High School: Number And Quantity

What are the components of a vector that has a terminal point of \(\displaystyle (-6,10)\), and an initial point of \(\displaystyle (-9,11)\)?

Possible Answers:

\(\displaystyle < 1,-5>\)

\(\displaystyle < -1,3>\)

\(\displaystyle < 3,-1>\)

\(\displaystyle < -16,-20>\)

\(\displaystyle < -17,19>\)

Correct answer:

\(\displaystyle < 3,-1>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=-6 \\ \mbox{(x in initial point)}=-9 \\ \mbox{(y in terminal point)}=10\\ \mbox{(y in initial point)}= 11\)

\(\displaystyle x=-6-(-9)=-6+9=3\)

\(\displaystyle y=10-11=-1\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < 3,-1>\)

 

Below is a visual representation of what we just did.

Screen shot 2016 03 16 at 1.33.55 pm

Example Question #114 : High School: Number And Quantity

What are the components of a vector that has a terminal point of \(\displaystyle (1,3)\), and an initial point of \(\displaystyle (3,1)\)?

Possible Answers:

\(\displaystyle < 2,2>\)

\(\displaystyle < -2,-2>\)

\(\displaystyle < 2,-2>\)

\(\displaystyle < -2,2>\)

\(\displaystyle < -2,0>\)

Correct answer:

\(\displaystyle < -2,2>\)

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

\(\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }\)

\(\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }\)

Now lets identify what these values are.

\(\displaystyle \\ \mbox{(x in terminal point)}=1 \\ \mbox{(x in initial point)}=3 \\ \mbox{(y in terminal point)}=3\\ \mbox{(y in initial point)}= 1\)

\(\displaystyle x=1-3=-2\)

\(\displaystyle y=3-1=2\)

To write this in component form, we need to put our \(\displaystyle x\), and \(\displaystyle y\) into \(\displaystyle < >\).

So the final answer is \(\displaystyle < -2,2>\)

 

Below is a visual representation of what we just did.


Comp3

All Common Core: High School - Number and Quantity Resources

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