In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=1 \\ \mbox{(x in initial point)}=-6 \\ \mbox{(y in terminal point)}=1\\ \mbox{(y in initial point)}= -9$

$\displaystyle x=1-(-6)=1+6=7$

$\displaystyle y=1-(-9)=1+9=10$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < 7,10>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=-9 \\ \mbox{(x in initial point)}=2 \\ \mbox{(y in terminal point)}=1\\ \mbox{(y in initial point)}= -10$

$\displaystyle x=-9-5=-14$

$\displaystyle y=1-(-10)=1+10=11$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < -14,11>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=3 \\ \mbox{(x in initial point)}=6 \\ \mbox{(y in terminal point)}=-8\\ \mbox{(y in initial point)}= -13$

$\displaystyle x=3-6=-3$

$\displaystyle y=-8-(-13)=-8+13=5$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < -3,5>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=-1 \\ \mbox{(x in initial point)}=-4 \\ \mbox{(y in terminal point)}=-5\\ \mbox{(y in initial point)}= -9$

$\displaystyle x=-1-(-4)=-1+4=3$

$\displaystyle y=-5-(-9)=-5+9=4$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < 3,4>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=-3 \\ \mbox{(x in initial point)}=-4 \\ \mbox{(y in terminal point)}=10\\ \mbox{(y in initial point)}=12$

$\displaystyle x=-3-(-4)=-3+4=1$

$\displaystyle y=10-12=-2$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < 1,-2>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=1 \\ \mbox{(x in initial point)}=-7 \\ \mbox{(y in terminal point)}=9\\ \mbox{(y in initial point)}= 5$

$\displaystyle x=1-(-7)=1+7=8$

$\displaystyle y=9-5=4$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < 8,4>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=4 \\ \mbox{(x in initial point)}=0 \\ \mbox{(y in terminal point)}=6\\ \mbox{(y in initial point)}= -8$

$\displaystyle x=4-0=4$

$\displaystyle y=6-(-8)=6+8=14$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < 4,14>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=3 \\ \mbox{(x in initial point)}=10 \\ \mbox{(y in terminal point)}=-6\\ \mbox{(y in initial point)}=5$

$\displaystyle x=3-10=-7$

$\displaystyle y=-6-5=-11$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < -7,-11>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=-6 \\ \mbox{(x in initial point)}=-9 \\ \mbox{(y in terminal point)}=10\\ \mbox{(y in initial point)}= 11$

$\displaystyle x=-6-(-9)=-6+9=3$

$\displaystyle y=10-11=-1$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < 3,-1>$

Below is a visual representation of what we just did.

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are. 

$\displaystyle x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$\displaystyle y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\displaystyle \\ \mbox{(x in terminal point)}=1 \\ \mbox{(x in initial point)}=3 \\ \mbox{(y in terminal point)}=3\\ \mbox{(y in initial point)}= 1$

$\displaystyle x=1-3=-2$

$\displaystyle y=3-1=2$

To write this in component form, we need to put our $\displaystyle x$, and $\displaystyle y$ into $\displaystyle < >$.

So the final answer is $\displaystyle < -2,2>$

Below is a visual representation of what we just did.