All Common Core: High School - Geometry Resources
Example Questions
Example Question #3 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11
In a triangle where the side opposite a has length 3 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 60 for , 3 for and 51 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #181 : High School: Geometry
In a triangle where the side opposite a has length 13 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 45 for , 13 for and 65 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #182 : High School: Geometry
In a triangle where the side opposite a has length 12 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 26 for , 12 for and 41 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #1 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11
In a triangle where the side opposite a has length 6 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 36 for , 6 for and 58 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #183 : High School: Geometry
In a triangle where the side opposite a has length 11 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 26 for , 11 for and 17 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #12 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11
In a triangle where the side opposite a has length 11 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 81 for , 11 for and 66 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #11 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11
In a triangle where the side opposite a has length 5 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 70 for , 5 for and 50 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #12 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11
In a triangle where the side opposite a has length 5 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 11 for , 5 for and 64 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #11 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11
In a triangle where the side opposite a has length 6 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 78 for , 6 for and 52 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
Example Question #184 : High School: Geometry
In a triangle where the side opposite a has length 7 find the side opposite a angle. Round you answer to the nearest hundredth.
In order to solve this, we need to recall the law of sines.
Where , and are angles, and , and , are opposite side lengths.
Now let's plug in 44 for , 7 for and 53 for .
Now our equation becomes
Now we rearrange the equation to solve for b
Now we round our answer to the nearest tenth.
Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.
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