Common Core: High School - Geometry : Similarity, Right Triangles, & Trigonometry

Study concepts, example questions & explanations for Common Core: High School - Geometry

varsity tutors app store varsity tutors android store

All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #3 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11

In a triangle where the side opposite a  has length 3 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 60 for , 3 for  and 51 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #181 : High School: Geometry

In a triangle where the side opposite a  has length 13 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 45 for , 13 for  and 65 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #182 : High School: Geometry


In a triangle where the side opposite a  has length 12 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 26 for , 12 for  and 41 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #1 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11

In a triangle where the side opposite a  has length 6 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 36 for , 6 for  and 58 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #183 : High School: Geometry

In a triangle where the side opposite a  has length 11 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 26 for , 11 for  and 17 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #12 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11

In a triangle where the side opposite a  has length 11 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 81 for , 11 for  and 66 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #11 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11

In a triangle where the side opposite a  has length 5 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 70 for , 5 for  and 50 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #12 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11

In a triangle where the side opposite a  has length 5 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 11 for , 5 for  and 64 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #11 : Apply Laws Of Sines And Cosines: Ccss.Math.Content.Hsg Srt.D.11

In a triangle where the side opposite a  has length 6 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 78 for , 6 for  and 52 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

Example Question #184 : High School: Geometry

In a triangle where the side opposite a  has length 7 find the side opposite a  angle. Round you answer to the nearest hundredth.

Possible Answers:

Correct answer:

Explanation:

In order to solve this, we need to recall the law of sines.

Where , and  are angles, and , and , are opposite side lengths.

Now let's plug in 44 for , 7 for  and 53 for .
Now our equation becomes

Now we rearrange the equation to solve for b

Now we round our answer to the nearest tenth.

Remember if your answer is negative, multiply it by -1, because side lengths can't be negative.

All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept
Learning Tools by Varsity Tutors