All Common Core: High School - Geometry Resources
Example Questions
Example Question #1 : Sine And Cosine Relationship Of Complementary Angles: Ccss.Math.Content.Hsg Srt.C.7
You have two complementary angles, and . You know that and . Using your sine and cosine relationships, what is ?
We will use the definition of complementary to solve for . and must sum up to be 90 by the definition of complementary angles. We are able to set up the following equation:
(combine like terms)
Example Question #1 : Sine And Cosine Relationship Of Complementary Angles: Ccss.Math.Content.Hsg Srt.C.7
and are complementary angles. If what is ? Use the sine cosine relationship of complementary angles to solve this problem.
Using our relationship we know that . We can set up the following equation to solve for
We can double check our work using the definition of complementary angles. That means that . We know that our answer must be correct because .
Example Question #1 : Sine And Cosine Relationship Of Complementary Angles: Ccss.Math.Content.Hsg Srt.C.7
Use the sine and cosine relationship of complementary angles to find the diagonal of the square. (DO NOT use Pythagorean Theorem).
First, we need to think about what it means to be a square. Squares have 4 congruent sides and 4 congruent angles that must add up to 360. So each angle must be 90-degree angles. The diagonal of the square cut two of these 90-degree angles in symmetrical halves to form two right triangles within the square. Now we have two identical right triangles with legs of length 5 and angles of 90, 45, 45.
Recall what we know about our sine and cosine relationships:
So we can use either sine or cosine to solve for the hypotenuse. We will first use cosine:
We can also use sine since their relationship makes them equivalent
And now we can confirm using the Pythagorean Theorem to check our work:
Example Question #3 : Sine And Cosine Relationship Of Complementary Angles: Ccss.Math.Content.Hsg Srt.C.7
Use the sine and cosine relationship of complementary angles to solve for .
Recall our sine and cosine relationship of complementary angles. The sine of any acute angle is equal to the cosine of its complement:
We know that and .
We can use this information to set up the following equation to solve for .
()
(multiply both sides by )
Example Question #2 : Sine And Cosine Relationship Of Complementary Angles: Ccss.Math.Content.Hsg Srt.C.7
Consider the equilateral triangle below. Find the height of the triangle using the sine cosine relationship of complementary angles.
We begin by noting that this triangle is an equilateral triangle as stated in the problem. This means that all sides are congruent and all angles are congruent. Since a triangle’s angles must add up to 180 degrees, we can deduce that each of the three angles is 60 degrees. By drawing a vertical auxiliary line down from vertex A perpendicular to the base of the triangle we are evenly dividing the equilateral triangle into two right triangles. We can update the triangle as such:
We also know that each of the three angles of the equilateral triangle are equal to 60 degrees. Since the auxiliary line splits the equilateral evenly into two right triangles, we know that and that . Again, we can update our triangle:
Now we can begin to use our sine and cosine relationships of complementary angles to solve for . Recall the following:
Since we can use either one to solve for this problem.
or
Example Question #3 : Sine And Cosine Relationship Of Complementary Angles: Ccss.Math.Content.Hsg Srt.C.7
Consider the following figure. and are parallel to each other. and are parallel to each other. Is there enough information to solve for using sine and cosine relationship of complementary angles? If so, what is the value of ?
There is not enough information
Yes,
Yes,
Yes,
Yes,
We can deduce that and are complementary angles because triangle is a right triangle. We have enough information from this figure to find . Once we have this measurement we will be able to use the sine cosine relationship of complementary angles to solve for .
Since is a straight line segment, . Plugging in our values we can find
We could just use our knowledge that a triangle must add up to 180 degrees to solve for but that is not what the question is asking. We must now use the fact that ). We can set up the following equation to solve for .
Example Question #1 : Use Trigonometric Ratios And Pythagorean Theorem To Solve Right Triangles: Ccss.Math.Content.Hsg Srt.C.8
Determine whether a triangle with side lengths , , and is a right triangle.
Yes
No
No
To figure this problem out, we need to recall the Pythagorean Theorem.
Now we simply plug in for , for , and for .
If both sides are equal, then the side lengths result in a right triangle.
Since both sides are not equal, we can conclude that the side lengths are not a right triangle.
Example Question #2 : Use Trigonometric Ratios And Pythagorean Theorem To Solve Right Triangles: Ccss.Math.Content.Hsg Srt.C.8
Determine whether a triangle with side lengths , , and is a right triangle.
No
Yes
No
To figure this problem out, we need to recall the Pythagorean Theorem.
Now we simply plug in for , for , and for .
If both sides are equal, then the side lengths result in a right triangle.
Since both sides are not equal, we can conclude that the side lengths are not a right triangle.
Example Question #1 : Use Trigonometric Ratios And Pythagorean Theorem To Solve Right Triangles: Ccss.Math.Content.Hsg Srt.C.8
Determine whether a triangle with side lengths , , and is a right triangle.
No
Yes
No
To figure this problem out, we need to recall the Pythagorean Theorem.
Now we simply plug in for , for , and for .
If both sides are equal, then the side lengths result in a right triangle.
Since both sides are not equal, we can conclude that the side lengths are not a right triangle.
Example Question #1 : Use Trigonometric Ratios And Pythagorean Theorem To Solve Right Triangles: Ccss.Math.Content.Hsg Srt.C.8
Determine whether a triangle with side lengths , , and is a right triangle.
No
Yes
No
To figure this problem out, we need to recall the Pythagorean Theorem.
Now we simply plug in for , for , and for .
If both sides are equal, then the side lengths result in a right triangle.
Since both sides are not equal, we can conclude that the side lengths are not a right triangle.