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Common Core: High School - Geometry : Apply Density Concepts to Area and Volume Situations: CCSS.Math.Content.HSG-MG.A.2

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Example Questions

Example Question #1 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 58398 cubic meters of xenon with a density of 0.1629 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to 2 decimal places

Possible Answers:

$58398.16 \text{ kilograms}$

$358489.87 \text{ kilograms}$

$58397.84 \text{ kilograms}$

$4756.52 \text{ kilograms}$

$9513.03 \text{ kilograms}$

Correct answer:

$9513.03 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ ).

$0.1629 = \frac{m}{58398}$

m = 9513.03

Thus the mass of the balloon is 9513.03 kilograms.

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Example Question #2 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 53678 cubic meters of xenon with a density of 0.9606 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$55879.66 \text{ kilograms}$

$53678.96 \text{ kilograms}$

$51563.09 \text{ kilograms}$

$53677.04 \text{ kilograms}$

$25781.54 \text{ kilograms}$

Correct answer:

$51563.09 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.9606 = \frac{m}{53678} \\\\m = 51563.09$

Thus the mass of the balloon is $51563.09 \text{ kilograms}$ .

Report an Error

Example Question #3 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 58398 cubic meters of xenon with a density of 0.1629 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places

Possible Answers:

$4756.52 \text{ kilograms}$

$58398.16 \text{ kilograms}$

$9513.03 \text{ kilograms}$

$358489.87 \text{ kilograms}$

$58397.84 \text{ kilograms}$

Correct answer:

$9513.03 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ ).

$0.1629 = \frac{m}{58398}$

m = 9513.03

Thus the mass of the balloon is $9513.03 \text{ kilograms}$ .

Report an Error

Example Question #4 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 58744 cubic meters of xenon with a density of 0.1417 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$8324.02 \text{ kilograms}$

$58743.86 \text{ kilograms}$

$4162.01 \text{ kilograms}$

$414565.98 \text{ kilograms}$

$58744.14 \text{ kilograms}$

Correct answer:

$8324.02 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ ).

$\\0.1417 = \frac{m}{58744} \\\\m = 8324.02$

Thus the mass of the balloon is $8324.02 \text{ kilograms}$ .

Report an Error

Example Question #5 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 86938 cubic meters of xenon with a density of 0.5102 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$22177.88 \text{ kilograms}$

$86937.49 \text{ kilograms}$

$44355.77 \text{ kilograms}$

$86938.51 \text{ kilograms}$

$170399.84 \text{ kilograms}$

Correct answer:

$44355.77 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.5102 = \frac{m}{86938} \\\\m = 44355.77$

Thus the mass of the balloon is $44355.77 \text{ kilograms}$ .

Report an Error

Example Question #6 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 72481 cubic meters of neon with a density of 0.0364 kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$1319.15 \text{ kilograms}$

$72480.96 \text{ kilograms}$

$2638.31 \text{ kilograms}$

$1991236.26 \text{ kilograms }$

$72481.04 \text{ kilograms}$

Correct answer:

$2638.31 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.0364 = \frac{m}{72481} \\\\m = 2638.31$

Thus the mass of the balloon is $2638.31 \text{ kilograms}$ .

Report an Error

Example Question #7 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 78453 cubic meters of water with a density of 0.011 kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$7132090.91 \text{ kilograms}$

$78453.01 \text{ kilograms}$

$78452.99 \text{ kilograms}$

$862.98 \text{ kilograms }$

$431.49 \text{ kilograms}$

Correct answer:

$862.98 \text{ kilograms }$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.011 = \frac{m}{78453} \\\\m = 862.98$

Thus the mass of the balloon is $862.98 \text{ kilograms }$ .

Report an Error

Example Question #8 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 77003 cubic meters of water with a density of 0.4689 kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$18053.35 \text{ kilograms}$

$77002.53 \text{ kilograms}$

$77003.47 \text{ kilograms}$

$36106.71 \text{ kilograms}$

$164220.52 \text{ kilograms}$

Correct answer:

$36106.71 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.4689 = \frac{m}{77003} \\\\m = 36106.71$ Thus the mass of the balloon is $36106.71 \text{ kilograms}$ .

Report an Error

Example Question #9 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 97999 cubic meters of xenon with a density of 0.183 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$17933.82 \text{ kilograms}$

$97999.18 \text{ kilograms}$

$535513.66 \text{ kilograms}$

$8966.91 \text{ kilograms}$

$97998.82 \text{ kilograms}$

Correct answer:

$17933.82 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume. Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.183 = \frac{m}{97999} \\\\m = 17933.82$

Thus the mass of the balloon is $17933.82 \text{ kilograms}$ .

Report an Error

Example Question #451 : High School: Geometry

If a balloon is filled with 70672 cubic meters of neon with a density of 0.2245 kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to decimal places.

Possible Answers:

$70671.78 \text{ kilograms}$

$15865.86 \text{ kilograms}$

$7932.93 \text{ kilograms}$

$70672.22 \text{ kilograms}$

$314797.33 \text{ kilograms}$

Correct answer:

$15865.86 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ().

$\\0.2245 = \frac{m}{70672} \\\\m = 15865.86$

Thus the mass of the balloon is $15865.86 \text{ kilograms}$ .

Report an Error

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All Common Core: High School - Geometry Resources

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Common Core: High School - Geometry : Apply Density Concepts to Area and Volume Situations: CCSS.Math.Content.HSG-MG.A.2

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #1 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #2 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #3 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #4 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #5 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #6 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #7 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #8 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #9 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #451 : High School: Geometry

All Common Core: High School - Geometry Resources

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