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Common Core: High School - Functions : Restricting Domain of Trigonometric Functions to Allow for Construction of Inverse: CCSS.Math.Content.HSF-TF.B.6

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Example Questions

Example Question #71 : Trigonometric Functions

Find the exact value of the following statement.

$f(x)=\sin^{-1}(0)$

Possible Answers:

$\sin^{-1}(0)=\frac{\pi}{4}$

$\sin^{-1}(0)=\frac{2\pi}{5}$

$\sin^{-1}(0)=\frac{\pi}{2}$

$\sin^{-1}(0)=\pi \text{ or }2\pi$

$\sin^{-1}(0)=\frac{3\pi}{2}$

Correct answer:

$\sin^{-1}(0)=\pi \text{ or }2\pi$

Explanation:

This question is testing ones ability to understand and identify inverses of trigonometric functions as they relate to the unit circle.

For the purpose of Common Core Standards, " Understand that restricting a trigonometric function to a domain on which it is always increasing or always decreasing allows its inverse to be constructed." concept (CCSS.MATH.CONTENT.HSF-TF.B.6). It is important to note that this standard is not directly tested on but is used for building a deeper understanding on trigonometric functions.

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify what the question is asking for.

Since there is a trigonometric function raised to the negative one power, this question is talking about the inverse of the function. In other words, which angle on the unit circle results in a sine equalling zero?

$y=\sin^{-1}(a)\Rightarrow \sin(\theta)=a$

Therefore, theta needs to be solved for.

Step 2: Draw and label the unit circle.

Screen shot 2016 01 14 at 10.52.42 am

Step 3: Locate the angle that results in the given sine value.

Recall that

$(x,y)=(\cos(\theta),\sin(\theta))$

therefore look for the (x,y) that has y=0 . Looking at the unit circle from step 2, it is seen that at angle $\pi$ and $2\pi$ the sine equals the given value.

Thus,

$f(x)=\sin^{-1}(0)\Rightarrow f(x)=\pi \text{ or }2\pi$

To verify the solution simply find the sine of the angle theta.

$\\\sin\left({\pi}\right)=0\rightarrow\sin^{-1}(0)=\pi\\ \sin(2\pi)=0\rightarrow \sin^{-1}(0)=2\pi$

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Example Question #71 : Trigonometric Functions

Find the exact value of the following statement.

$f(x)=\sin^{-1}\left(\frac{1}{2} \right )$

Possible Answers:

$\sin^{-1}\left( \frac{1}{2}\right )=\frac{\pi}{6}\text{ or }\frac{11\pi}{6}$

$\sin^{-1}\left( \frac{1}{2}\right )=\frac{\pi}{6}\text{ or }\frac{5\pi}{6}$

$\sin^{-1}\left( \frac{1}{2}\right )=\frac{\pi}{6}\text{ or }\frac{7\pi}{6}$

$\sin^{-1}\left( \frac{1}{2}\right )=\frac{11\pi}{6}\text{ or }\frac{5\pi}{6}$

$\sin^{-1}\left( \frac{1}{2}\right )=\frac{7\pi}{6}\text{ or }\frac{5\pi}{6}$

Correct answer:

$\sin^{-1}\left( \frac{1}{2}\right )=\frac{\pi}{6}\text{ or }\frac{5\pi}{6}$

Explanation:

This question is testing ones ability to understand and identify inverses of trigonometric functions as they relate to the unit circle.

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify what the question is asking for.

$y=\sin^{-1}(a)\Rightarrow \sin(\theta)=a$

Therefore, theta needs to be solved for.

Step 2: Draw and label the unit circle.

Screen shot 2016 01 14 at 10.52.42 am

Step 3: Locate the angle that results in the given sine value.

Recall that

$(x,y)=(\cos(\theta),\sin(\theta))$

therefore look for the (x,y) that has $y=\frac{1}{2}$ . Looking at the unit circle from step 2, it is seen that at angle $\frac{\pi}{6}$ and $\frac{5\pi}{6}$ the sine equals the given value.

Thus,

$f(x)=\sin^{-1}\left(\frac{1}{2} \right )\Rightarrow f(x)=\frac{\pi}{6}, \frac{5\pi}{6}$

To verify the solution simply find the sine of the angle theta.

$\\ \sin\left(\frac{\pi}{6} \right )=\frac{1}{2}\rightarrow \sin^{-1}\left(\frac{1}{2} \right )=\frac{\pi}{6} \\ \sin\left(\frac{5\pi}{6} \right )=\frac{1}{2}\rightarrow \sin^{-1}\left(\frac{1}{2} \right )=\frac{5\pi}{6}$

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Common Core: High School - Functions : Restricting Domain of Trigonometric Functions to Allow for Construction of Inverse: CCSS.Math.Content.HSF-TF.B.6

Study concepts, example questions & explanations for Common Core: High School - Functions

All Common Core: High School - Functions Resources

Example Questions

Example Question #71 : Trigonometric Functions

Example Question #71 : Trigonometric Functions

All Common Core: High School - Functions Resources

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