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Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Screen shot 2016 01 12 at 2.32.17 pm

What is the $\displaystyle y$-intercept of the function that is depicted in the graph above?

$\textup{y-intercept}=-1$ $\displaystyle \textup{y-intercept}=-1$

$\textup{y-intercept}=3$ $\displaystyle \textup{y-intercept}=3$

$\textup{y-intercept}=1$ $\displaystyle \textup{y-intercept}=1$

$\textup{y-intercept}=1.5$ $\displaystyle \textup{y-intercept}=1.5$

$\textup{y-intercept}=2$ $\displaystyle \textup{y-intercept}=2$

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All Common Core: High School - Functions Resources

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Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Screen shot 2016 01 12 at 2.32.17 pm

What is the $\displaystyle y$-intercept of the function that is depicted in the graph above?

$\textup{y-intercept}=-1$ $\displaystyle \textup{y-intercept}=-1$

$\textup{y-intercept}=3$ $\displaystyle \textup{y-intercept}=3$

$\textup{y-intercept}=1$ $\displaystyle \textup{y-intercept}=1$

$\textup{y-intercept}=1.5$ $\displaystyle \textup{y-intercept}=1.5$

$\textup{y-intercept}=2$ $\displaystyle \textup{y-intercept}=2$

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Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Screen shot 2016 01 12 at 2.32.17 pm

What is the $\displaystyle y$-intercept of the function that is depicted in the graph above?

Your answer:

$\textup{y-intercept}=-1$ $\displaystyle \textup{y-intercept}=-1$

Your answer:

$\textup{y-intercept}=1$ $\displaystyle \textup{y-intercept}=1$

Your answer:

$\textup{y-intercept}=1.5$ $\displaystyle \textup{y-intercept}=1.5$

Your answer:

$\textup{y-intercept}=2$ $\displaystyle \textup{y-intercept}=2$

Correct answer:

$\textup{y-intercept}=3$ $\displaystyle \textup{y-intercept}=3$

Explanation:

This question tests one's ability to recognize algebraic characteristics of a graph. This particular question examines a linear function.

For the purpose of Common Core Standards, "graph linear and quadratic functions and show intercepts, maxima, and minima" falls within the Cluster C of "Analyze Functions Using Different Representations" concept (CCSS.MATH.CONTENT.HSF-IF.C.7).

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify the general algebraic function for the given graph.

Since the graph is that of a straight line, the general algebraic form of the function is,

y=mx+b $\displaystyle y=mx+b$

where

$\\m=\textup{slope} \\b=\textup{y-intercept}$ $\displaystyle \\m=\textup{slope} \\b=\textup{y-intercept}$

Step 2: Identify where the graph crosses the $\displaystyle y$-axis.

Screen shot 2016 01 12 at 2.32.17 pm

Therefore the general form of the function looks like,

y=mx+3 $\displaystyle y=mx+3$

Step 3: Answer the question.

The $\displaystyle y$-intercept is three.

Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Screen shot 2016 01 22 at 2.07.51 pm

What is the $\displaystyle y$-intercept of the function that is depicted in the graph above?

$\textup{y-intercept}=0$ $\displaystyle \textup{y-intercept}=0$

$\textup{y-intercept}=-2$ $\displaystyle \textup{y-intercept}=-2$

$\textup{y-intercept}=-1$ $\displaystyle \textup{y-intercept}=-1$

$\textup{y-intercept}=-\frac{1}{2}$ $\displaystyle \textup{y-intercept}=-\frac{1}{2}$

$\textup{y-intercept}=1$ $\displaystyle \textup{y-intercept}=1$

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Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Screen shot 2016 01 22 at 2.07.51 pm

What is the $\displaystyle y$-intercept of the function that is depicted in the graph above?

Your answer:

$\textup{y-intercept}=0$ $\displaystyle \textup{y-intercept}=0$

Your answer:

$\textup{y-intercept}=-2$ $\displaystyle \textup{y-intercept}=-2$

Your answer:

$\textup{y-intercept}=-\frac{1}{2}$ $\displaystyle \textup{y-intercept}=-\frac{1}{2}$

Your answer:

$\textup{y-intercept}=1$ $\displaystyle \textup{y-intercept}=1$

Correct answer:

$\textup{y-intercept}=-1$ $\displaystyle \textup{y-intercept}=-1$

Explanation:

This question tests one's ability to recognize algebraic characteristics of a graph. This particular question examines a linear function.

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify the general algebraic function for the given graph.

Since the graph is that of a straight line, the general algebraic form of the function is,

y=mx+b $\displaystyle y=mx+b$

where

$\\m=\textup{slope} \\b=\textup{y-intercept}$ $\displaystyle \\m=\textup{slope} \\b=\textup{y-intercept}$

Step 2: Identify where the graph crosses the $\displaystyle y$-axis.

Screen shot 2016 01 22 at 2.07.51 pm

Therefore the general form of the function looks like,

y=mx-1 $\displaystyle y=mx-1$

Step 3: Answer the question.

The $\displaystyle y$-intercept is negative one.

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Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

All Common Core: High School - Functions Resources

Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

Flashcards: Graph Linear and Quadratic Functions: CCSS.Math.Content.HSF-IF.C.7a

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