Call Now to Set Up Tutoring:

(888) 888-0446

Create an account to track your scores
and create your own practice tests:

Create an Account Create a Practice Test

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following functions $\displaystyle f$ and $\displaystyle g$, calculate g(f(2)) $\displaystyle g(f(2))$.

$\\f(x)=3x+2 \\g(x)=x^2-2x+1$ $\displaystyle \\f(x)=3x+2 \\g(x)=x^2-2x+1$

$\displaystyle g(f(2))=29$

$\displaystyle g(f(2))=36$

$\displaystyle g(f(2))=27$

$\displaystyle g(f(2))=57$

$\displaystyle g(f(2))=49$

Report an Error Copyright Notice

All Common Core: High School - Functions Resources

6 Diagnostic Tests 82 Practice Tests Question of the Day Flashcards Learn by Concept

Want to review Common Core: High School - Functions but don’t feel like sitting for a whole test at the moment? Varsity Tutors has you covered with thousands of different Common Core: High School - Functions flashcards! Our Common Core: High School - Functions flashcards allow you to practice with as few or as many questions as you like. Get some studying in now with our numerous Common Core: High School - Functions flashcards.

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following functions $\displaystyle f$ and $\displaystyle g$, calculate g(f(2)) $\displaystyle g(f(2))$.

$\\f(x)=3x+2 \\g(x)=x^2-2x+1$ $\displaystyle \\f(x)=3x+2 \\g(x)=x^2-2x+1$

$\displaystyle g(f(2))=29$

$\displaystyle g(f(2))=36$

$\displaystyle g(f(2))=27$

$\displaystyle g(f(2))=57$

$\displaystyle g(f(2))=49$

Report an Error Copyright Notice

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following functions $\displaystyle f$ and $\displaystyle g$, calculate g(f(2)) $\displaystyle g(f(2))$.

$\\f(x)=3x+2 \\g(x)=x^2-2x+1$ $\displaystyle \\f(x)=3x+2 \\g(x)=x^2-2x+1$

Your answer:

$\displaystyle g(f(2))=29$

Your answer:

$\displaystyle g(f(2))=36$

Your answer:

$\displaystyle g(f(2))=27$

Your answer:

$\displaystyle g(f(2))=57$

Correct answer:

$\displaystyle g(f(2))=49$

Explanation:

This question is testing the knowledge and skills of calculating a function value. Similar to domain and range, calculating the function value requires the application of input values into the function to find the output value. In other words, evaluating a function at a particular value results in the function value; which is another way of saying function value is the output.

For the purpose of Common Core Standards, function notation and evaluation fall within the Cluster A of the function and use of function notation concept (CCSS.MATH.CONTENT.HSF-IF.A).

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify the input value.

Since the inside function is in the form f(x) $\displaystyle f(x)$ and the question asks to calculate f(2) $\displaystyle f(2)$ we know that the input value is two.

$f(2)\rightarrow x=2$ $\displaystyle f(2)\rightarrow x=2$

After the function value of f(2) $\displaystyle f(2)$ is calculated, it will be the input value for g(x) $\displaystyle g(x)$.

Step 2: Given the function, input the desired $\displaystyle x$ value.

In step one the input value of two was found. Now substitute 2 in for every$\displaystyle x$ in the function f(x) $\displaystyle f(x)$.

$\displaystyle f(x)=3x+2$

$\\ f(2)=3(2)+2 \\f(2)=6+2 \\f(2)=8$ $\displaystyle \\ f(2)=3(2)+2 \\f(2)=6+2 \\f(2)=8$

Step 3: Substitute the function value of the inside portion into g(x) $\displaystyle g(x)$.

$\displaystyle g(f(2))=g(8)$

$\\g(x)=x^2-2x+1 \\g(8)=8^2-2(8)+1 \\g(8)=64-16+1 \\g(8)=49$ $\displaystyle \\g(x)=x^2-2x+1 \\g(8)=8^2-2(8)+1 \\g(8)=64-16+1 \\g(8)=49$

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following function $\displaystyle g$, calculate g(2) $\displaystyle g(2)$.

$g(x)=\frac{x^2-3}{x^3+1}$ $\displaystyle g(x)=\frac{x^2-3}{x^3+1}$

g(2)=1 $\displaystyle g(2)=1$

$g(2)=\frac{1}{10}$ $\displaystyle g(2)=\frac{1}{10}$

$g(2)=\frac{2}{9}$ $\displaystyle g(2)=\frac{2}{9}$

$g(2)=\frac{6}{9}$ $\displaystyle g(2)=\frac{6}{9}$

$g(2)=\frac{1}{9}$ $\displaystyle g(2)=\frac{1}{9}$

Report an Error Copyright Notice

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following function $\displaystyle g$, calculate g(2) $\displaystyle g(2)$.

$g(x)=\frac{x^2-3}{x^3+1}$ $\displaystyle g(x)=\frac{x^2-3}{x^3+1}$

Your answer:

g(2)=1 $\displaystyle g(2)=1$

Your answer:

$g(2)=\frac{1}{10}$ $\displaystyle g(2)=\frac{1}{10}$

Your answer:

$g(2)=\frac{2}{9}$ $\displaystyle g(2)=\frac{2}{9}$

Your answer:

$g(2)=\frac{6}{9}$ $\displaystyle g(2)=\frac{6}{9}$

Correct answer:

$g(2)=\frac{1}{9}$ $\displaystyle g(2)=\frac{1}{9}$

Explanation:

For the purpose of Common Core Standards, function notation and evaluation fall within the Cluster A of the function and use of function notation concept (CCSS.MATH.CONTENT.HSF-IF.A).

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify the input value.

Since the function is in the form g(x) $\displaystyle g(x)$ and the question asks to calculate g(2) $\displaystyle g(2)$ we know that the input value is two.

$g(2)\rightarrow x=2$ $\displaystyle g(2)\rightarrow x=2$

Step 2: Given the function, input the desired $\displaystyle x$ value.

In step one the input value of two was found. Now substitute 2 in for every$\displaystyle x$ in the function.

$g(x)=\frac{x^2-3}{x^3+1}$ $\displaystyle g(x)=\frac{x^2-3}{x^3+1}$

$g(2)=\frac{2^2-3}{2^3+1}$ $\displaystyle g(2)=\frac{2^2-3}{2^3+1}$

$g(2)=\frac{4-3}{8+1}$ $\displaystyle g(2)=\frac{4-3}{8+1}$

$g(2)=\frac{1}{9}$ $\displaystyle g(2)=\frac{1}{9}$

Step 3: Answer the question.

This particular function when solved algebraically results in one value.

The answer is

$g(2)=\frac{1}{9}$ $\displaystyle g(2)=\frac{1}{9}$

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

View Tutors

Abigail
Certified Tutor

Indiana University-Bloomington, Bachelor of Science, Social Work.

View Tutors

Liam
Certified Tutor

California State University-Northridge, Master of Science, Public Health.

View Tutors

Madison
Certified Tutor

D'Youville College, Doctor of Science, Pharmacology.

Popular Subjects

Calculus Tutors in Los Angeles, Statistics Tutors in San Francisco-Bay Area, MCAT Tutors in New York City, Reading Tutors in New York City, Algebra Tutors in Los Angeles, SSAT Tutors in Boston, Chemistry Tutors in Washington DC, ISEE Tutors in San Diego, SAT Tutors in Seattle, Physics Tutors in Washington DC

Popular Courses & Classes

MCAT Courses & Classes in Atlanta, SSAT Courses & Classes in Phoenix, GRE Courses & Classes in Atlanta, Spanish Courses & Classes in Los Angeles, Spanish Courses & Classes in Seattle, GRE Courses & Classes in San Diego, LSAT Courses & Classes in Philadelphia, LSAT Courses & Classes in Washington DC, GMAT Courses & Classes in Phoenix, ACT Courses & Classes in Dallas Fort Worth

Popular Test Prep

SAT Test Prep in Philadelphia, SAT Test Prep in Washington DC, GMAT Test Prep in Boston, SSAT Test Prep in Dallas Fort Worth, SAT Test Prep in San Francisco-Bay Area, GRE Test Prep in Phoenix, ACT Test Prep in Dallas Fort Worth, MCAT Test Prep in San Francisco-Bay Area, LSAT Test Prep in Seattle, SSAT Test Prep in New York City

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Create an account to track your scores
and create your own practice tests:

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

All Common Core: High School - Functions Resources

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Report an issue with this question