Common Core: 7th Grade Math : Ratios & Proportional Relationships

Study concepts, example questions & explanations for Common Core: 7th Grade Math

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Example Questions

Example Question #51 : Grade 7

A baker can decorate \displaystyle \frac{1}{13} of a wedding cake in \displaystyle \frac{1}{4} of an hour. If the baker continues this rate, how much of the wedding cake can he decorate per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the cake decorated, \displaystyle \frac{1}{13}, divided by hours, \displaystyle \frac{1}{4}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{4}\rightarrow \frac{4}{1}

Therefore:

\displaystyle \frac{1}{13}\times\frac{4}{1}=\frac{4}{13}

The baker can decorate \displaystyle \frac{4}{13} of the wedding cake per hour. 

Example Question #52 : Grade 7

A painter can paint \displaystyle \frac{1}{8} of a house in \displaystyle \frac{1}{5} of an hour. If he continues this rate, how much of the house can he paint per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted, \displaystyle \frac{1}{8}, divided by hours, \displaystyle \frac{1}{5}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{5}\rightarrow \frac{5}{1}

Therefore:

\displaystyle \frac{1}{8}\times\frac{5}{1}=\frac{5}{8}

The painter can paint \displaystyle \frac{5}{8} of a house per hour. 

Example Question #53 : Grade 7

A painter can paint \displaystyle \frac{1}{7} of a house in \displaystyle \frac{1}{5} of an hour. If he continues this rate, how much of the house can he paint per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted, \displaystyle \frac{1}{7}, divided by hours, \displaystyle \frac{1}{5}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{5}\rightarrow \frac{5}{1}

Therefore:

\displaystyle \frac{1}{7}\times\frac{5}{1}=\frac{5}{7}

The painter can paint \displaystyle \frac{5}{7} of a house per hour. 

Example Question #54 : Grade 7

A painter can paint \displaystyle \frac{1}{6} of a house in \displaystyle \frac{1}{5} of an hour. If he continues this rate, how much of the house can he paint per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted, \displaystyle \frac{1}{6}, divided by hours, \displaystyle \frac{1}{5}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{5}\rightarrow \frac{5}{1}

Therefore:

\displaystyle \frac{1}{6}\times\frac{5}{1}=\frac{5}{6}

The painter can paint \displaystyle \frac{5}{6} of a house per hour. 

Example Question #55 : Grade 7

A painter can paint \displaystyle \frac{1}{5} of a house in \displaystyle \frac{1}{5} of an hour. If he continues this rate, how much of the house can he paint per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted, \displaystyle \frac{1}{5}, divided by hours, \displaystyle \frac{1}{5}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{5}\rightarrow \frac{5}{1}

Therefore:

\displaystyle \frac{1}{5}\times\frac{5}{1}=\frac{5}{5}=1

The painter can paint \displaystyle 1 of a house per hour. 

Example Question #56 : Grade 7

A painter can paint \displaystyle \frac{1}{4} of a house in \displaystyle \frac{1}{5} of an hour. If he continues this rate, how much of the house can he paint per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted, \displaystyle \frac{1}{4}, divided by hours, \displaystyle \frac{1}{5}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{5}\rightarrow \frac{5}{1}

Therefore:

\displaystyle \frac{1}{4}\times\frac{5}{4}=1\frac{1}{5}

The painter can paint \displaystyle 1\frac{1}{5} of a house per hour. 

Example Question #57 : Grade 7

A landscaper can mow \displaystyle \frac{1}{4} of a yard in \displaystyle \frac{1}{8} of an hour. If he continues at this rate, how many yards can the landscaper mow per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards, \displaystyle \frac{1}{4}, divided by hours, \displaystyle \frac{1}{8}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{8}\rightarrow \frac{8}{1}

Therefore:

\displaystyle \frac{1}{4}\times\frac{8}{1}=\frac{8}{4}=2

The landscaper can mow \displaystyle 2 yards per hour. 

Example Question #58 : Grade 7

A landscaper can mow \displaystyle \frac{1}{5} of a yard in \displaystyle \frac{1}{8} of an hour. If he continues at this rate, how many yards can the landscaper mow per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards, \displaystyle \frac{1}{5}, divided by hours, \displaystyle \frac{1}{8}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{8}\rightarrow \frac{8}{1}

Therefore:

\displaystyle \frac{1}{5}\times\frac{8}{1}=\frac{8}{5}=1\frac{3}{5}

The landscaper can mow \displaystyle 1\frac{3}{5} yards per hour. 

Example Question #59 : Grade 7

A landscaper can mow \displaystyle \frac{1}{6} of a yard in \displaystyle \frac{1}{8} of an hour. If he continues at this rate, how many yards can the landscaper mow per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards, \displaystyle \frac{1}{6}, divided by hours, \displaystyle \frac{1}{8}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{8}\rightarrow \frac{8}{1}

Therefore:

\displaystyle \frac{1}{6}\times\frac{8}{6}=\frac{8}{6}=1\frac{2}{6}=1\frac{1}{3}

The landscaper can mow \displaystyle 1\frac{1}{3} yards per hour. 

Example Question #51 : Grade 7

A landscaper can mow \displaystyle \frac{1}{7} of a yard in \displaystyle \frac{1}{8} of an hour. If he continues at this rate, how many yards can the landscaper mow per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards, \displaystyle \frac{1}{7}, divided by hours, \displaystyle \frac{1}{8}:

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

\displaystyle \frac{1}{8}\rightarrow \frac{8}{1}

Therefore:

\displaystyle \frac{1}{7}\times\frac{8}{1}=\frac{8}{7}=1\frac{1}{7}

The landscaper can mow \displaystyle 1\frac{1}{7} yards per hour. 

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