All Common Core: 7th Grade Math Resources
Example Questions
Example Question #51 : Grade 7
A baker can decorate
of a wedding cake in of an hour. If the baker continues this rate, how much of the wedding cake can he decorate per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the cake decorated,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The baker can decorate
of the wedding cake per hour.Example Question #52 : Grade 7
A painter can paint
of a house in of an hour. If he continues this rate, how much of the house can he paint per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paint
of a house per hour.Example Question #53 : Grade 7
A painter can paint
of a house in of an hour. If he continues this rate, how much of the house can he paint per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paint
of a house per hour.Example Question #54 : Grade 7
A painter can paint
of a house in of an hour. If he continues this rate, how much of the house can he paint per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paint
of a house per hour.Example Question #55 : Grade 7
A painter can paint
of a house in of an hour. If he continues this rate, how much of the house can he paint per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paint
of a house per hour.Example Question #56 : Grade 7
A painter can paint
of a house in of an hour. If he continues this rate, how much of the house can he paint per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have portion of the house painted,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The painter can paint
of a house per hour.Example Question #57 : Grade 7
A landscaper can mow
of a yard in of an hour. If he continues at this rate, how many yards can the landscaper mow per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mow
yards per hour.Example Question #58 : Grade 7
A landscaper can mow
of a yard in of an hour. If he continues at this rate, how many yards can the landscaper mow per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mow
yards per hour.Example Question #59 : Grade 7
A landscaper can mow
of a yard in of an hour. If he continues at this rate, how many yards can the landscaper mow per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mow
yards per hour.Example Question #51 : Grade 7
A landscaper can mow
of a yard in of an hour. If he continues at this rate, how many yards can the landscaper mow per hour?The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards,
, divided by hours, :Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.
Therefore:
The landscaper can mow
yards per hour.All Common Core: 7th Grade Math Resources
