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Common Core: 6th Grade Math : The Number System

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #26 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 81\\ 4{\overline{\smash{)}324}}\\ -\ 32 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 32$

$4\times 81$

$4\times 91$

$4\times 82$

$4\times 101$

Correct answer:

$4\times 81$

Explanation:

The computation shows that $324\div4=81$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 81}\\ {\color{Green} 4}{\overline{\smash{)}324}}\\ -\ 32 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times81=324+0$

Simplify.

$4\times81=324$

The correct answer is $4\times 81$

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Example Question #27 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 91\\ 4{\overline{\smash{)}364}}\\ -\ 36 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 36$

$4\times 91$

$4\times 101$

$4\times 81$

$4\times 63$

Correct answer:

$4\times 91$

Explanation:

The computation shows that $364\div4=91$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 91}\\ {\color{Green} 4}{\overline{\smash{)}364}}\\ -\ 36 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times91=364+0$

Simplify.

$4\times91=364$

The correct answer is $4\times 91$

Report an Error

Example Question #3541 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 31\\ 5{\overline{\smash{)}155}}\\ -\ 15 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 51$

$5\times 21$

$5\times 31$

$5\times 41$

$5\times 15$

Correct answer:

$5\times 31$

Explanation:

The computation shows that $155\div5=31$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 31}\\ {\color{Green} 5}{\overline{\smash{)}155}}\\ -\ 15 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times31=155+0$

Simplify.

$5\times31=155$

The correct answer is $5\times 31$

Report an Error

Example Question #3542 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 41\\ 5{\overline{\smash{)}205}}\\ -\ 20 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 31$

$5\times 62$

$5\times 41$

$5\times 61$

$5\times 20$

Correct answer:

$5\times 41$

Explanation:

The computation shows that $205\div5=41$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 41}\\ {\color{Green} 5}{\overline{\smash{)}205}}\\ -\ 20 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times41=205+0$

Simplify.

$5\times41=205$

The correct answer is $5\times 41$

Report an Error

Example Question #3543 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 5{\overline{\smash{)}255}}\\ -\ 25 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 52$

$5\times 51$

$5\times 31$

$5\times 25$

$5\times 71$

Correct answer:

$5\times 51$

Explanation:

The computation shows that $255\div5=51$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 5}{\overline{\smash{)}255}}\\ -\ 25 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times51=255+0$

Simplify.

$5\times51=255$

The correct answer is $5\times 51$

Report an Error

Example Question #3544 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 5{\overline{\smash{)}305}}\\ -\ 30 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 81$

$5\times 61$

$5\times 30$

$5\times 31$

$5\times 63$

Correct answer:

$5\times 61$

Explanation:

The computation shows that $305\div5=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 5}{\overline{\smash{)}305}}\\ -\ 30 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times61=305+0$

Simplify.

$5\times61=305$

The correct answer is $5\times 61$

Report an Error

Example Question #3552 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 71\\ 5{\overline{\smash{)}355}}\\ -\ 35 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 35$

$5\times 53$

$5\times 51$

$5\times 71$

$5\times 101$

Correct answer:

$5\times 71$

Explanation:

The computation shows that $355\div5=71$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 71}\\ {\color{Green} 5}{\overline{\smash{)}355}}\\ -\ 35 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times71=355+0$

Simplify.

$5\times71=355$

The correct answer is $5\times 71$

Report an Error

Example Question #41 : The Number System

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 81\\ 5{\overline{\smash{)}405}}\\ -\ 40 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 85$

$5\times 91$

$5\times 81$

$5\times 101$

$5\times 40$

Correct answer:

$5\times 81$

Explanation:

The computation shows that $405\div5=81$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 81}\\ {\color{Green} 5}{\overline{\smash{)}405}}\\ -\ 40 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times81=405+0$

Simplify.

$5\times81=405$

The correct answer is $5\times 81$

Report an Error

Example Question #3 : How To Add

Fill in the blank to make a true statement:

_______ $- \ 0.7 = 2.8$

Possible Answers:

19.6

3.5

2.1

1.2

Correct answer:

3.5

Explanation:

To find out what number to subtract 0.7 from to get 2.8, just do the opposite - add 0.7 to 2.8.

0.7+ 2.8 = 3.5

Report an Error

Example Question #3282 : Ssat Elementary Level Quantitative (Math)

Solve for :

0.15 h= 18

Possible Answers:

h = 120

h = 27

h= 1,200

h = 17.85

h = 2.7

Correct answer:

h = 120

Explanation:

0.15 h= 18

$0.15 h \div 0.15 = 18\div 0.15$

$h = 18\div 0.15$

To divide, move the decimal point in both numbers right two places to make the divisor whole.

$h = 1,800\div 15 = 120$

Report an Error

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: 6th Grade Math : The Number System

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #26 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #27 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #3541 : Operations

Example Question #3542 : Operations

Example Question #3543 : Operations

Example Question #3544 : Operations

Example Question #3552 : Operations

Example Question #41 : The Number System

Example Question #3 : How To Add

Example Question #3282 : Ssat Elementary Level Quantitative (Math)

All Common Core: 6th Grade Math Resources

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