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Common Core: 6th Grade Math : Solve Unit Rate Problems: CCSS.Math.Content.6.RP.A.3b

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #61 : Algebraic Concepts

At a local market, farmers trade produce to obtain a more diverse crop. A farmer will trade turnips for ears of corn. If a man has ears of corn, then how many turnips can he get?

Possible Answers:

$351\ \text{turnips}$

$153\ \text{turnips}$

$533\ \text{turnips}$

$531\ \text{turnips}$

$353\ \text{turnips}$

Correct answer:

$351\ \text{turnips}$

Explanation:

Ratios can be written in the following format:

$A:B\rightarrow \frac{A}{B}$

Using this format, substitute the given information to create a ratio.

$3\ \text{corn}: 13\ \text{turnips}$

Rewrite the ratio as a fraction.

$3\ \text{corn}: 13\ \text{turnips}\rightarrow \frac{3\ \text{corn}}{13\ \text{turnips}}$

We know that the farmer has ears of corn. Create a ratio with the variable that represents how many turnips he can get.

$\frac{81\ \text{corn}}{T}$

Create a proportion using the two ratios.

$\frac{3\ \text{corn}}{13\ \text{turnips}}=\frac{81\ \text{corn}}{T}$

Cross multiply and solve for .

$81\ \text{corn}\times 13\ \text{turnips}=3\ \text{corn}\times T$

Simplify.

3T=1053

Divide both sides of the equation by .

$\frac{3T}{3}=\frac{1053}{3}$

Solve.

T=351

The farmer can get $351\ \text{turnips}$ .

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Example Question #735 : Ssat Middle Level Quantitative (Math)

At a local market, farmers trade produce to obtain a more diverse crop. A farmer will trade turnips for ears of corn. If a man has 126 ears of corn, then how many turnips can he get?

Possible Answers:

$546\ \text{turnips}$

$456\ \text{turnips}$

$564\ \text{turnips}$

$654\ \text{turnips}$

$645\ \text{turnips}$

Correct answer:

$546\ \text{turnips}$

Explanation:

Ratios can be written in the following format:

$A:B\rightarrow \frac{A}{B}$

Using this format, substitute the given information to create a ratio.

$3\ \text{corn}: 13\ \text{turnips}$

Rewrite the ratio as a fraction.

$3\ \text{corn}: 13\ \text{turnips}\rightarrow \frac{3\ \text{corn}}{13\ \text{turnips}}$

We know that the farmer has 126 ears of corn. Create a ratio with the variable that represents how many turnips he can get.

$\frac{126\ \text{corn}}{T}$

Create a proportion using the two ratios.

$\frac{3\ \text{corn}}{13\ \text{turnips}}=\frac{126\ \text{corn}}{T}$

Cross multiply and solve for .

$126\ \text{corn}\times 13\ \text{turnips}=3\ \text{corn}\times T$

Simplify.

3T=1638

Divide both sides of the equation by .

$\frac{3T}{3}=\frac{1638}{3}$

Solve.

T=546

The farmer can get $546\ \text{turnips}$ .

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All Common Core: 6th Grade Math Resources

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Common Core: 6th Grade Math : Solve Unit Rate Problems: CCSS.Math.Content.6.RP.A.3b

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #61 : Algebraic Concepts

Example Question #735 : Ssat Middle Level Quantitative (Math)

All Common Core: 6th Grade Math Resources

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