All Common Core: 6th Grade Math Resources
Example Questions
Example Question #731 : Grade 6
Solve the equation:
In order to solve this equation, we must divide by eight on both sides of the equation.
Divide each digit by eight.
Example Question #231 : Algebraic Equations
Solve:
In order to solve for , divide both sides by negative three.
The negative three will cancel out on the left side. Divide each digit on the numerator by three.
The answer is:
Example Question #732 : Grade 6
Solve:
Solve this equation by dividing six on both sides of the equation.
The sixes will cancel out on the left side. Leave the right side as an improper fraction.
The answer is:
Example Question #55 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c
Solve:
Solve by adding seven on both sides of the equation. This will isolate on both sides of the equation.
Add the left side of the equation.
Add the right side of the equation.
The answer is .
Example Question #241 : Algebraic Equations
Solve for :
To solve this equation, we must isolate on the left side by multiplying each side by , as follows:
Therefore, the correct answer is .
Example Question #57 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c
Solve:
To solve for , we must isolate it to one side of the equation, as follows:
Example Question #242 : Algebraic Equations
Find the solution for the variable m.
In order to find the solution we must isolate the variable m. The first step is to subtract 346 from both sides as follows:
We can check the answer by plugging in our solution of 765 into the original equation.
It works.
Example Question #1 : Apply The Properties Of Operations To Generate Equivalent Expressions: Ccss.Math.Content.6.Ee.A.3
Expand:
Distribute the by multiplying it by each term inside the parentheses.
and
Therefore, 5(2 + y) = 10 + 5y.
Example Question #31 : Identities And Properties
Simplify the expression:
To solve this question you must use the distrubitive property by multiplying x by -2 and the 2 by -2, making sure to distribute the negative as well. This gives you:
Example Question #2 : Apply The Properties Of Operations To Generate Equivalent Expressions: Ccss.Math.Content.6.Ee.A.3
Which answer correctly simplifies this expression?
To simplify this expression, use the distributive property. This means that we have to multiply the 2 times both terms inside the parentheses. , and . So, our answer is .