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Common Core: 5th Grade Math : Number & Operations with Fractions

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1051 : Common Core Math: Grade 5

The cafe has $349\textup { liters}$ of coffee to last days. How many liters of coffee does the cafe have per day, assuming that each day has an equal amount of coffee? Select the answer that contains the pair of numbers that the answer falls between.

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of coffee over the number of days. We get the following:

$\small \frac{349\textup{ liters of coffee}}{13\textup{ days}}$

can go into 349 only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.

Simple multiplication reveals the following:

$13\times 26=338$

In order to find out what is left over, we must subtract this number from the numerator.

349-338=11

The difference will always be less than the denominator from the original improper fraction. If it is not, then check your work in the previous step because this means that the denominator could have been divided into the numerator at least one more time.

Then, we put the difference over the denominator:

$\frac{11}{13}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{349}{13}=26\frac{11}{13}$

Last, we know that $26\frac{11}{13}$ is between the numbers and ; therefore, the correct answer is:

and

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Example Question #1052 : Common Core Math: Grade 5

The cafe has $362\textup { liters}$ of coffee to last days. How many liters of coffee does the cafe have per day, assuming that each day has an equal amount of coffee? Select the answer that contains the pair of numbers that the answer falls between.

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of coffee over the number of days. We get the following:

$\small \frac{362\textup{ liters of coffee}}{13\textup{ days}}$

can go into 362 only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.

Simple multiplication reveals the following:

$13\times 27=351$

In order to find out what is left over, we must subtract this number from the numerator.

362-351=11

Then, we put the difference over the denominator:

$\frac{11}{13}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{362}{13}=27\frac{11}{13}$

Last, we know that $27\frac{11}{13}$ is between the numbers and ; therefore, the correct answer is:

and

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Example Question #1053 : Common Core Math: Grade 5

The cafe has $375\textup { liters}$ of coffee to last days. How many liters of coffee does the cafe have per day, assuming that each day has an equal amount of coffee? Select the answer that contains the pair of numbers that the answer falls between.

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of coffee over the number of days. We get the following:

$\small \frac{375\textup{ liters of coffee}}{13\textup{ days}}$

can go into 375 only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.

Simple multiplication reveals the following:

$13\times 28=364$

In order to find out what is left over, we must subtract this number from the numerator.

375-364=11

Then, we put the difference over the denominator:

$\frac{11}{13}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{375}{13}=28\frac{11}{13}$

Last, we know that $28\frac{11}{13}$ is between the numbers and ; therefore, the correct answer is:

and

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Example Question #1054 : Common Core Math: Grade 5

Ashley has pieces of candy that she wants to divide amongst her friends. How many pieces of candy will each friend get, assuming that each friend gets the same amount? Select the answer that contains the pair of numbers that the answer falls between.

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Ashley's friends. We get the following:

$\small \frac{86\textup{ pieces of candy}}{6\textup{ friends}}$

can go into only times. In other words, we are looking for the number that when multiplied by the denominator gets us as close to the numerator as possible, without going over the value of the numerator.

Simple multiplication reveals the following:

$6\times 14=84$

In order to find out what is left over, we must subtract this number from the numerator.

86-84=2

Then, we put the difference over the denominator:

$\frac{2}{6}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{86}{6}=14\frac{2}{6}$

Last, we know that $14\frac{2}{6}$ is between the numbers and ; therefore, the correct answer is:

and

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Example Question #1055 : Common Core Math: Grade 5

Melissa has pieces of candy that she wants to divide amongst her friends. How many pieces of candy will each friend get, assuming that each friend gets the same amount? Select the answer that contains the pair of numbers that the answer falls between.

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Melissa's friends. We get the following:

$\small \frac{53\textup{ pieces of candy}}{4\textup{ friends}}$

Simple multiplication reveals the following:

$4\times 13=52$

In order to find out what is left over, we must subtract this number from the numerator.

53-52=1

Then, we put the difference over the denominator:

$\frac{1}{4}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{53}{4}=13\frac{1}{4}$

Last, we know that $13\frac{1}{4}$ is between the numbers and ; therefore, the correct answer is:

and

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Example Question #1056 : Common Core Math: Grade 5

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Melissa's friends. We get the following:

$\small \frac{50\textup{ pieces of candy}}{4\textup{ friends}}$

Simple multiplication reveals the following:

$4\times 12=48$

In order to find out what is left over, we must subtract this number from the numerator.

50-48=2

Then, we put the difference over the denominator:

$\frac{2}{4}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{50}{4}=12\frac{2}{4}$

Last, we know that $12\frac{2}{4}$ is between the numbers and ; therefore, the correct answer is:

and

Report an Error

Example Question #181 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Melissa's friends. We get the following:

$\small \frac{67\textup{ pieces of candy}}{4\textup{ friends}}$

Simple multiplication reveals the following:

$4\times 16=64$

In order to find out what is left over, we must subtract this number from the numerator.

67-64=3

Then, we put the difference over the denominator:

$\frac{3}{4}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{67}{4}=16\frac{3}{4}$

Last, we know that $16\frac{3}{4}$ is between the numbers and ; therefore, the correct answer is:

and

Report an Error

Example Question #182 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Melissa's friends. We get the following:

$\small \frac{61\textup{ pieces of candy}}{4\textup{ friends}}$

Simple multiplication reveals the following:

$4\times 15=60$

In order to find out what is left over, we must subtract this number from the numerator.

61-60=1

Then, we put the difference over the denominator:

$\frac{1}{4}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{61}{4}=15\frac{1}{4}$

and Last, we know that $15\frac{1}{4}$ is between the numbers and ; therefore, the correct answer is:

and

Report an Error

Example Question #1061 : Common Core Math: Grade 5

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Melissa's friends. We get the following:

$\small \frac{34\textup{ pieces of candy}}{3\textup{ friends}}$

Simple multiplication reveals the following:

$3\times 11=33$

In order to find out what is left over, we must subtract this number from the numerator.

34-33=1

Then, we put the difference over the denominator:

$\frac{1}{3}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{34}{3}=11\frac{1}{3}$

Last, we know that $11\frac{1}{3}$ is between the numbers and ; therefore, the correct answer is:

and

Report an Error

Example Question #1062 : Common Core Math: Grade 5

Possible Answers:

and

Correct answer:

and

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number by placing the amount of candy over the number of Melissa's friends. We get the following:

$\small \frac{31\textup{ pieces of candy}}{3\textup{ friends}}$

Simple multiplication reveals the following:

$3\times 10=30$

In order to find out what is left over, we must subtract this number from the numerator.

31-30=1

Then, we put the difference over the denominator:

$\frac{1}{3}$

Let's solve for the entire improper fraction by putting these values together and forming a mixed number:

$\small \frac{31}{3}=10\frac{1}{3}$

Last, we know that $10\frac{1}{3}$ is between the numbers and ; therefore, the correct answer is:

and

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Common Core: 5th Grade Math : Number & Operations with Fractions

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #1051 : Common Core Math: Grade 5

Example Question #1052 : Common Core Math: Grade 5

Example Question #1053 : Common Core Math: Grade 5

Example Question #1054 : Common Core Math: Grade 5

Example Question #1055 : Common Core Math: Grade 5

Example Question #1056 : Common Core Math: Grade 5

Example Question #181 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #182 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #1061 : Common Core Math: Grade 5

Example Question #1062 : Common Core Math: Grade 5

All Common Core: 5th Grade Math Resources

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