We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent 

Because we are dividing by , we need to split up our   into groups of 

As you can see, we have  groups. Thus the answer is . 

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent 

Because we are dividing  by  , we need to split up our  into groups of 

We can see that we have 2 groups of 2, thus the answer is 2. 

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent .2

Because we are dividing .2 by .2, we need to split up our .2 into groups of .2:

We can see that we have 1 group, thus our answer is 1. 

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent 

Because we are dividing  by , we need to split up our  into groups of :

As you can see, we have  groups; thus, 

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent 

Because we are dividing  by , we need to split up our  into groups of :

As you can see, we have  groups; thus, 

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent 

Because we are dividing  by , we need to split up our  into groups of 

As you can see, we have  groups; thus,  

The problem that you are challenged to solve is . 

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house". 

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best ( is too large). We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  in the ones place and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the . We will work with the numbers as if they were  when thinking of multiplication facts, but it should be noted this is actually  when you consider the decimal placement.  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining so there is no remainder. 

Our final answer is , which means that half of  is 

The problem that you are challenged to solve is .

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in thirds to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best ( is too large). We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the . We will work with the numbers as if they were  when thinking of multiplication facts, but it should be noted this is actually  when you consider the decimal placement.  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining.

Finally, we carry down the  from the hundredths place and place it next to the  giving us  (or  for the purpose of our multiplication facts.)  so we place the  above the  in the hundredths place on top of our "house" and subtract the  leaving us with a remainder of .

Our final answer is 

The problem that you are challenged to solve is . 

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in quarters to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best. We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the .  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining.

Finally, we carry down the  from the hundredths place and place it next to the .  so we place the  above the  in the hundredths place on top of our "house" and subtract the  leaving us with a remainder of .

Our final answer is 

The problem that you are challenged to solve is .

 is the dividend, this is what is being broken up into groups.  is our divisor which is the number of groups you are making. We need to split  in half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house". 

Next, we need to use or multiplication facts to determine what  can be multiplied by to make  or get close to it without going over.  is the fact that works best. We will place the numeral  directly above the  in the ones place to indicate that  groups of  fit into the . We will put the product of  which was  underneath the  and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the  in the tenths place down and put it next to the .  so we place the  above the "house" in the tenths place of our quotient and subtract the . We are left with  remaining so there is no remainder. 

Our final answer is , which means that half of  is