Common Core: 4th Grade Math : Solve problems involving measurement and conversion of measurements

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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Example Questions

Example Question #51 : Plane Geometry

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #531 : Plane Geometry

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #121 : How To Find The Area Of A Parallelogram

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #122 : How To Find The Area Of A Parallelogram

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #123 : How To Find The Area Of A Parallelogram

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #124 : How To Find The Area Of A Parallelogram

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #125 : How To Find The Area Of A Parallelogram

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

Correct answer:

Explanation:

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

Subtract  from both sides

Divide  by both sides

Example Question #531 : Plane Geometry

What is the length of a yard with a perimeter of  and a width of 

 

Possible Answers:

\displaystyle 8ft

Correct answer:

\displaystyle 4ft

Explanation:

\displaystyle P=2l+ 2w

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

\displaystyle 16=2l+2(4)

\displaystyle 16=2l+8

Subtract \displaystyle 8 from both sides

\displaystyle 16-8=2l+8-8

\displaystyle 8=2l

Divide \displaystyle 2 by both sides

\displaystyle \frac{8}{2}=\frac{2l}{2}

\displaystyle 4=l

Example Question #71 : Geometry

What is the length of a yard with a perimeter of \displaystyle 28ft and a width of \displaystyle 4ft?

 

Possible Answers:

\displaystyle 12ft

\displaystyle 13ft

\displaystyle 10ft

\displaystyle 11ft

\displaystyle 9ft

Correct answer:

\displaystyle 10ft

Explanation:

\displaystyle P=2l+ 2w

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

\displaystyle 28=2l+2(4)

\displaystyle 28=2l+8

Subtract \displaystyle 8 from both sides

\displaystyle 28-8=2l+8-8

\displaystyle 20=2l

Divide \displaystyle 2 by both sides

\displaystyle \frac{20}{2}=\frac{2l}{2}

\displaystyle 10=l

Example Question #72 : Geometry

What is the length of a yard with a perimeter of \displaystyle 20ft and a width of \displaystyle 3ft?

 

Possible Answers:

\displaystyle 6ft

\displaystyle 8ft

\displaystyle 7ft

\displaystyle 9ft

\displaystyle 5ft

Correct answer:

\displaystyle 7ft

Explanation:

\displaystyle P=2l+ 2w

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown. 

\displaystyle 20=2l+2(3)

\displaystyle 20=2l+6

Subtract \displaystyle 6 from both sides

\displaystyle 20-6=2l+6-6

\displaystyle 14=2l

Divide \displaystyle 2 by both sides

\displaystyle \frac{14}{2}=\frac{2l}{2}

\displaystyle 7=l

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