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Common Core: 4th Grade Math : Know Relative Sizes of Measurement Units: CCSS.Math.Content.4.MD.A.1

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2994 : Ssat Elementary Level Quantitative (Math)

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 11.53.02 am

Possible Answers:

0.071

0.07

007

0.007

0.7

Correct answer:

0.007

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1g}{0.001 kg}=\frac{7g}{x}$

First we cross multiply.

1g(x)=7g(0.001kg)

Then we divide each side by to isolate the .

$\frac{1g(x)}{1g}=\frac{7g(0.001kg)}{1g}$

x=0.007kg

Report an Error

Example Question #2773 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 11.53.13 am

Possible Answers:

0.006

0.6

0006

006

0.06

Correct answer:

0.006

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1g}{0.001 kg}=\frac{6g}{x}$

First we cross multiply.

1g(x)=6g(0.001kg)

Then we divide each side by to isolate the .

$\frac{1g(x)}{1g}=\frac{6g(0.001kg)}{1g}$

x=0.006kg

Report an Error

Example Question #2771 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 11.53.22 am

Possible Answers:

005

0.005

0.05

0.5

Correct answer:

0.005

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1g}{0.001 kg}=\frac{5g}{x}$

First we cross multiply.

1g(x)=5g(0.001kg)

Then we divide each side by to isolate the .

$\frac{1g(x)}{1g}=\frac{5g(0.001kg)}{1g}$

x=0.005kg

Report an Error

Example Question #21 : Measurement & Data

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 11.53.35 am

Possible Answers:

004

0.04

0.4

0.004

Correct answer:

0.004

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1g}{0.001 kg}=\frac{4g}{x}$

First we cross multiply.

1g(x)=4g(0.001kg)

Then we divide each side by to isolate the .

$\frac{1g(x)}{1g}=\frac{4g(0.001kg)}{1g}$

x=0.004kg

Report an Error

Example Question #2771 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 11.53.45 am

Possible Answers:

0.003

0.03

0.3

003

Correct answer:

0.003

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1g}{0.001 kg}=\frac{3g}{x}$

First we cross multiply.

1g(x)=3g(0.001kg)

Then we divide each side by to isolate the .

$\frac{1g(x)}{1g}=\frac{3g(0.001kg)}{1g}$

x=0.003kg

Report an Error

Example Question #2781 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 11.53.55 am

Possible Answers:

002

0.02

0.2

0.002

Correct answer:

0.002

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1g}{0.001 kg}=\frac{2g}{x}$

First we cross multiply.

1g(x)=2g(0.001kg)

Then we divide each side by to isolate the .

$\frac{1g(x)}{1g}=\frac{2g(0.001kg)}{1g}$

x=0.002kg

Report an Error

Example Question #2782 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 3.29.15 pm

Possible Answers:

107

106

111

110

112

Correct answer:

112

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1lb}{16oz}=\frac{7lb}{x}$

First we cross multiply.

1lb(x)=7lb(16oz)

Then we divide each side by 1lb to isolate the .

$\frac{1lb(x)}{1lb}=\frac{7lb(16oz)}{1lb}$

x=112oz

Report an Error

Example Question #2783 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 3.29.49 pm

Possible Answers:

Correct answer:

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1lb}{16oz}=\frac{5lb}{x}$

First we cross multiply.

1lb(x)=5lb(16oz)

Then we divide each side by 1lb to isolate the .

$\frac{1lb(x)}{1lb}=\frac{5lb(16oz)}{1lb}$

x=80oz

Report an Error

Example Question #2784 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 3.29.39 pm

Possible Answers:

100

Correct answer:

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1lb}{16oz}=\frac{6lb}{x}$

First we cross multiply.

1lb(x)=6lb(16oz)

Then we divide each side by 1lb to isolate the .

$\frac{1lb(x)}{1lb}=\frac{6lb(16oz)}{1lb}$

x=96oz

Report an Error

Example Question #2785 : Operations

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 3.29.59 pm

Possible Answers:

Correct answer:

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1lb}{16oz}=\frac{4lb}{x}$

First we cross multiply.

1lb(x)=4lb(16oz)

Then we divide each side by 1lb to isolate the .

$\frac{1lb(x)}{1lb}=\frac{4lb(16oz)}{1lb}$

x=64oz

Report an Error

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: 4th Grade Math : Know Relative Sizes of Measurement Units: CCSS.Math.Content.4.MD.A.1

Study concepts, example questions & explanations for Common Core: 4th Grade Math

All Common Core: 4th Grade Math Resources

Example Questions

Example Question #2994 : Ssat Elementary Level Quantitative (Math)

Example Question #2773 : Operations

Example Question #2771 : Operations

Example Question #21 : Measurement & Data

Example Question #2771 : Operations

Example Question #2781 : Operations

Example Question #2782 : Operations

Example Question #2783 : Operations

Example Question #2784 : Operations

Example Question #2785 : Operations

All Common Core: 4th Grade Math Resources

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