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Common Core: 3rd Grade Math : Common Core Math: Grade 3

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

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All Common Core: 3rd Grade Math Resources

7 Diagnostic Tests 226 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : How To Find The Area Of A Rectangle

What is the area of the figure below?

Possible Answers:

40in^2 $\displaystyle 40in^2$

8in^2 $\displaystyle 8in^2$

36in^2 $\displaystyle 36in^2$

44in^2 $\displaystyle 44in^2$

48in^2 $\displaystyle 48in^2$

Correct answer:

44in^2 $\displaystyle 44in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

6.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=4\times 2$ $\displaystyle A=4\times 2$ $A=9\times 4$ $\displaystyle A=9\times 4$

A=8in^2 $\displaystyle A=8in^2$ $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 8in^2+36in^2=44in^2$

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Example Question #1 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

What is the area of the figure below?

Possible Answers:

31in^2 $\displaystyle 31in^2$

35in^2 $\displaystyle 35in^2$

22in^2 $\displaystyle 22in^2$

40in^2 $\displaystyle 40in^2$

9in^2 $\displaystyle 9in^2$

Correct answer:

31in^2 $\displaystyle 31in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

5.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=3\times 3$ $\displaystyle A=3\times 3$ $A=11\times 2$ $\displaystyle A=11\times 2$

A=9in^2 $\displaystyle A=9in^2$ $\displaystyle A=22in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 9in^2+22in^2=31in^2$

Report an Error

Example Question #112 : Plane Geometry

What is the area of the figure below?

Possible Answers:

64in^2 $\displaystyle 64in^2$

62in^2 $\displaystyle 62in^2$

24in^2 $\displaystyle 24in^2$

68in^2 $\displaystyle 68in^2$

40in^2 $\displaystyle 40in^2$

Correct answer:

64in^2 $\displaystyle 64in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

4.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=8\times 5$ $\displaystyle A=8\times 5$ $A=6\times 4$ $\displaystyle A=6\times 4$

$\displaystyle A=40in^2$ $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 40in^2+24in^2=64in^2$

Report an Error

Example Question #121 : Geometry

What is the area of the figure below?

Possible Answers:

24in^2 $\displaystyle 24in^2$

4in^2 $\displaystyle 4in^2$

18n^2 $\displaystyle 18n^2$

28in^2 $\displaystyle 28in^2$

16in^2 $\displaystyle 16in^2$

Correct answer:

28in^2 $\displaystyle 28in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

3.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=2\times 12$ $\displaystyle A=2\times 12$ $A=2\times 2$ $\displaystyle A=2\times 2$

$\displaystyle A=24in^2$ A=4in^2 $\displaystyle A=4in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 24in^2+4in^2=28in^2$

Report an Error

Example Question #111 : Quadrilaterals

What is the area of the figure below?

Possible Answers:

8in^2 $\displaystyle 8in^2$

4in^2 $\displaystyle 4in^2$

12in^2 $\displaystyle 12in^2$

16in^2 $\displaystyle 16in^2$

20in^2 $\displaystyle 20in^2$

Correct answer:

12in^2 $\displaystyle 12in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

1.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=2\times 4$ $\displaystyle A=2\times 4$ $A=4\times 1$ $\displaystyle A=4\times 1$

A=8in^2 $\displaystyle A=8in^2$ A=4in^2 $\displaystyle A=4in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 8in^2+4in^2=12in^2$

Report an Error

Example Question #72 : Geometry

What is the area of the figure below?

Possible Answers:

9in^2 $\displaystyle 9in^2$

11in^2 $\displaystyle 11in^2$

13in^2 $\displaystyle 13in^2$

21in^2 $\displaystyle 21in^2$

18in^2 $\displaystyle 18in^2$

Correct answer:

11in^2 $\displaystyle 11in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

2.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=3\times 3$ $\displaystyle A=3\times 3$ $A=2\times 1$ $\displaystyle A=2\times 1$

A=9in^2 $\displaystyle A=9in^2$ A=2in^2 $\displaystyle A=2in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 9in^2+2in^2=11in^2$

Report an Error

Example Question #33 : Rectangles

What is the area of the figure below?

Possible Answers:

83in^2 $\displaystyle 83in^2$

48in^2 $\displaystyle 48in^2$

45in&2 $\displaystyle 45in&2$

73in^2 $\displaystyle 73in^2$

35in^2 $\displaystyle 35in^2$

Correct answer:

83in^2 $\displaystyle 83in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

12.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=6\times 8$ $\displaystyle A=6\times 8$ $A=7\times 5$ $\displaystyle A=7\times 5$

$\displaystyle A=48in^2$ $\displaystyle A=35in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 48in^2+35in^2=83in^2$

Report an Error

Example Question #251 : Geometric Measurement: Understanding Concepts Of Area And Relating Area To Multiplication And To Addition

What is the area of the figure below?

Possible Answers:

45in^2 $\displaystyle 45in^2$

18in^2 $\displaystyle 18in^2$

21in^2 $\displaystyle 21in^2$

42in^2 $\displaystyle 42in^2$

39in^2 $\displaystyle 39in^2$

Correct answer:

39in^2 $\displaystyle 39in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

11.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=7\times 3$ $\displaystyle A=7\times 3$ $A=6\times 3$ $\displaystyle A=6\times 3$

$\displaystyle A=21in^2$ $\displaystyle A=18in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 21in^2+18in^2=39in^2$

Report an Error

Example Question #252 : Geometric Measurement: Understanding Concepts Of Area And Relating Area To Multiplication And To Addition

What is the area of the figure below?

Possible Answers:

26in^2 $\displaystyle 26in^2$

58in&2 $\displaystyle 58in&2$

52in^2 $\displaystyle 52in^2$

40in^2 $\displaystyle 40in^2$

28in^2 $\displaystyle 28in^2$

Correct answer:

52in^2 $\displaystyle 52in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

10.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=8\times 3$ $\displaystyle A=8\times 3$ $A=7\times 4$ $\displaystyle A=7\times 4$

$\displaystyle A=24in^2$ $\displaystyle A=28in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 24in^2+28in^2=52in^2$

Report an Error

Example Question #231 : Problem Solving

What is the area of the figure below?

Possible Answers:

57in^2 $\displaystyle 57in^2$

126in^2 $\displaystyle 126in^2$

90in^2 $\displaystyle 90in^2$

36in^2 $\displaystyle 36in^2$

82in^2 $\displaystyle 82in^2$

Correct answer:

126in^2 $\displaystyle 126in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

9.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$ , we can solve for the area of both of our rectangles

$A=10\times 9$ $\displaystyle A=10\times 9$ $A=9\times 4$ $\displaystyle A=9\times 4$

$\displaystyle A=90in^2$ $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 90in^2+36in^2=126in^2$

Report an Error

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All Common Core: 3rd Grade Math Resources

7 Diagnostic Tests 226 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: 3rd Grade Math : Common Core Math: Grade 3

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

All Common Core: 3rd Grade Math Resources

Example Questions

Example Question #11 : How To Find The Area Of A Rectangle

Example Question #1 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

Example Question #112 : Plane Geometry

Example Question #121 : Geometry

Example Question #111 : Quadrilaterals

Example Question #72 : Geometry

Example Question #33 : Rectangles

Example Question #251 : Geometric Measurement: Understanding Concepts Of Area And Relating Area To Multiplication And To Addition

Example Question #252 : Geometric Measurement: Understanding Concepts Of Area And Relating Area To Multiplication And To Addition

Example Question #231 : Problem Solving

All Common Core: 3rd Grade Math Resources

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