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Common Core: 2nd Grade Math : Add and Subtract Within 1000: CCSS.Math.Content.2.NBT.B.7

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

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All Common Core: 2nd Grade Math Resources

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Example Questions

Example Question #1 : Add And Subtract Within 1000: Ccss.Math.Content.2.Nbt.B.7

Solve the following:

$\frac{\begin{array}[b]{r}920\\ -\ 290\end{array}}{\space }$

Possible Answers:

630

632

631

634

Correct answer:

630

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}0\\ -\ 0\end{array}}{\ \ \ 0 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}2\\ -\ 9\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take away from since is the smaller number. In this case, we are going to look to the . We only ever need to take away from the number to the left. For this problem, that will leave us with a to replace the . So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{8} \not920\\ -\ 290\end{array}}{\space }$

Remember, we've borrowed from the hundreds place, so we can put a in front of the number in the tens place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{8} \not9\ ^{12}\not2\ \ \ \ \ 0\\ -\ 2 \ \ \ \ \ 9\ \ \ \ \ 0\end{array}}{\space }$

Now, we can subtract the numbers in the tens place:

$\frac{\begin{array}[b]{r}12\\ -\ 9\end{array}}{\ \ \ 3}$

Next, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{\ \ \ 6}$

Your final answer should be 630

$\frac{\begin{array}[b]{r}^{8} \not9\ ^{12}\not2\ \ \ \ \ 0\\ -\ 2 \ \ \ \ \ 9\ \ \ \ \ 0\end{array}}{\ \ \ 6 \ \ \ \ \ 3\ \ \ \ \ 0}$

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Example Question #1 : Add And Subtract Within 1000: Ccss.Math.Content.2.Nbt.B.7

Solve the following:

$\frac{\begin{array}[b]{r}169\\ +\ 323\end{array}}{\space }$

Possible Answers:

494

493

492

495

Correct answer:

492

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

9+3=12

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}1^{{\color{Red} 1}}6\ 9\\ +\ 3\ 2\ 3\end{array}}{\ \ \ \ \ \ \ \ 2 }$

Add the numbers in the tens place, including the that was carried over:

1+6+2=9

Add the numbers in the hundreds place:

1+3=4

Your final answer should be 492:

$\frac{\begin{array}[b]{r}169\\ +\ 323\end{array}}{\ \ \ 492 }$

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Common Core: 2nd Grade Math : Add and Subtract Within 1000: CCSS.Math.Content.2.NBT.B.7

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

All Common Core: 2nd Grade Math Resources

Example Questions

Example Question #1 : Add And Subtract Within 1000: Ccss.Math.Content.2.Nbt.B.7

Example Question #1 : Add And Subtract Within 1000: Ccss.Math.Content.2.Nbt.B.7

All Common Core: 2nd Grade Math Resources

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