All Calculus AB Resources
Example Questions
Example Question #1 : Apply Intermediate Value Theorem
Can Intermediate Value Theorem be applied to the function within the interval
?
No, because the function is not continuous
No, because
Yes, because the function crosses the axis within the interval
Yes, because the function has a root at
No, because
The required conditions for Intermediate Value Theorem include the function must be continuous and cannot equal
. While there is a root at
for this particular continuous function, this cannot be shown using Intermediate Value Theorem. The function does not cross the
axis, thus eliminating that particular answer choice. The correct answer is “No, because
.” Since one of the conditions for Intermediate Value Theorem is that
cannot equal
, by graphing
we can see that this requirement is not met.
Example Question #121 : Limits And Continuity
What can be concluded by using Intermediate Value Theorem for the function on the interval
?
There is a root for this polynomial at
There are two roots on this polynomial located between and
The requirements for Intermediate Value Theorem are not met
There is a root for this polynomial located between and
There is a root for this polynomial located between and
his function is continuous (as it is a polynomial) and ; therefore, the required conditions for Intermediate Value Theorem are met. While there is a root at
for this function (as can be seen by graphing the polynomial), Intermediate Value Theorem does not state where this root will be exactly, nor does it state how many roots there might be. Thus, the conclusion that can be made by IVT is that there is a root for this polynomial located somewhere between
and
.
Example Question #122 : Limits And Continuity
Let . Is there a number
between
and
such that
?
No, no number c such that exists
Yes, as shown by Intermediate Value Theorem
No, Intermediate Value Theorem cannot determine the exact value of
Yes, as shown by the Fundamental Theorem of Calculus
Yes, as shown by Intermediate Value Theorem
First, determine the values of the function at the bounds. This will allow the correct implementation of the Intermediate Value Theorem.
Because the problem asks to analyze the interval and
, there must be a value
, with
. Because
, by Intermediate Value Theorem there should be a number
between
and
that satisfies the required conditions. Therefore, “Yes, as shown by Intermediate Value Theorem” is the correct answer.
Example Question #123 : Limits And Continuity
Assume is continuous on the interval
and has the values listed in the table below. Which of the following values of
guarantees that
has at least two roots?
If , only one root can be guaranteed (at
).
If , then Intermediate Value Theorem can be applied twice, for
and
.
This is true because for continuous functions, Intermediate Value Theorem states that a change in sign (ex: from positive to negative) of the function within an interval suggests a root (where the function crosses the axis) at some point within that interval.
Example Question #1 : Basic Differentiation Rules
Which of the following is the correct definition of a derivative?
A derivative gives the area under the curve of a function, .
A derivative is a rate of change, if you find the derivative of a function at a certain point, it is the slope of the tangent line at that point.
A derivative of a function, , is the inverse function,
A derivative is the root of a function,
A derivative is a rate of change, if you find the derivative of a function at a certain point, it is the slope of the tangent line at that point.
When you find the derivative of a function, you are finding the rate of change of the function. By finding the derivative at a certain point you are actually finding the slope of the tangent line at that point, which tells you how much the function is changing at the given point.
Example Question #2 : Basic Differentiation Rules
In order to find the derivative of a variable such as , we use the ______ ______.
Power Rule
Quotient Rule
Product Rule
Chain Rule
Power Rule
To find the derivative of a function, you must find the derivative of each variable. The derivative of a constant is . Using our example of
, to find the derivative we use the power rule. The formula for the power rule is:
If where
is a constant and
is an integer then
So if then
. This is the power rule in action.
Example Question #3 : Basic Differentiation Rules
Find the derivative of the function .
To find the derivative we will apply the power rule to each variable. Remember that the derivative of a constant is always .
Derivative of :
We multiply
by the coefficient (
) and then subtract one from the exponent giving us
.
Derivative of :
We multiply
by the coefficient (
) and then subtract one from the exponent giving us
.
Derivative of :
is just a constant, there is no variable here. So the derivative of any constant is
.
Putting this all together we have the derivative
Example Question #4 : Basic Differentiation Rules
Find the rate of change of the function at the point
.
To find the rate of change at a given point first we must find the derivative of the function:
Now that we have found the derivative of the function, we need to plug in our given value, .
So the rate of change at is
. This also means that the slope of the tangent line at this point is
.
Example Question #1 : Basic Differentiation Rules
True or False: Derivatives give us insight into the slope of the curve of a function.
True
False
True
This is true. When finding the derivative of a function you actually find a function that, when graphed, tells you when your original function is increasing or decreasing. We can also find out if a function is increasing or decreasing at certain points by finding the derivative for specific points. The slope of the tangent line that we find by doing this, tells us if our function is increasing (slope of the tangent line is positive) or decreasing (slope of the tangent line is negative).
Example Question #2 : Basic Differentiation Rules
You are given the rate of change for a function at
. The rate of change is 2. Is your function increasing or decreasing at
?
There is not enough information to determine the answer
Increasing
Decreasing
Increasing
If we were to graph this tangent line, we would see that the tangent line is increasing (it has a positive slope). Since the tangent line at is increasing, then our function must also be increasing at
.
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