All Calculus AB Resources
Example Questions
Example Question #19 : Connect Infinite Limits And Vertical/Horizontal Asymptotes
Decide which of the following functions, most likely represents the sample data above.
Notice that as x increases, the points of data graphed appears to level out, flattening towards a certain value. This value is what is known as a horizontal asymptote. An asymptote is a value that a function approaches, but never actually reaches. Think of a horizontal asymptote as a limit of a function as x approaches infinity. In such a case, as x approaches infinity, any constants added or subtracted in the numerator and denominator become irrelevant. What matters is the power of x in the denominator and the numerator; if those are the same, then to coefficients define the asymptote. We see that the function flattens towards:
This matches the ratio of coefficients for the function:
Example Question #20 : Connect Infinite Limits And Vertical/Horizontal Asymptotes
Which of the four following functions is most likely depicted in the sample data above?
Observation of the data points shows that there is a sharp increase and decrease on either side of a particular x-value. This type of behavior is observed when there is a vertical asymptote. An asymptote is a value that a function may approach, but will never actually attain. In the case of vertical asymptotes, this behavior occurs if the function approaches infinity for a given x-value, often when a zero value appears in a denominator. Noting this rule, the above function has a zero in the denominator at a definite point centered approximately around:
We find a zero denominator for the function:
Example Question #81 : Calculus Ab
Which of the four following functions is probably depicted in the sample data above?
Notice that as x increases, the points of data graphed appears to level out, flattening towards a certain value. This value is what is known as a horizontal asymptote. An asymptote is a value that a function approaches, but never actually reaches. Think of a horizontal asymptote as a limit of a function as x approaches infinity. In such a case, as x approaches infinity, any constants added or subtracted in the numerator and denominator become irrelevant. What matters is the power of x in the denominator and the numerator; if those are the same, then to coefficients define the asymptote. We see that the function flattens towards:
This matches the ratio of coefficients for the function:
Example Question #82 : Calculus Ab
Decide which of the following functions, most likely represents the sample data above.
Observation of the data points shows that there is a sharp increase and decrease on either side of a particular x-value. This type of behavior is observed when there is a vertical asymptote. An asymptote is a value that a function may approach, but will never actually attain. In the case of vertical asymptotes, this behavior occurs if the function approaches infinity for a given x-value, often when a zero value appears in a denominator. Noting this rule, the above function has a zero in the denominator at a definite point centered approximately around:
We find a zero denominator for the function:
Example Question #1 : Apply Intermediate Value Theorem
Which of the following does NOT satisfy the conditions required to apply the Intermediate Value Theorem to a function on the interval ?
The function f must be continuous along to apply Intermediate Value Theorem
Intermediate Value Theorem considers points within the interval
Intermediate Value Theorem cannot be applied outside of the interval
Intermediate Value Theorem can be used when
Intermediate Value Theorem can be used when
Intermediate Value Theorem states that if the function is continuous and has a domain containing the interval , then at some number within the interval the function will take on a value that is between the values of and .
The conditions that must be satisfied in order to use Intermediate Value Theorem include that the function must be continuous and the number must be within the interval . However, cannot equal .
Therefore, the answer choice “Intermediate Value Theorem can be used when ” does not satisfy the necessary conditions and is the correct answer for this question.
Example Question #1 : Apply Intermediate Value Theorem
Using Intermediate Value Theorem to analyze a continuous function, what can be deduced if a polynomial changes signs within an interval?
The function is not differentiable within that interval
The function is not continuous within that interval
There is a local maximum between the endpoints of that interval
There is a zero between the endpoints of that interval
There is a zero between the endpoints of that interval
Intermediate Value Theorem is only true with continuous, differentiable functions, thus eliminating the answer choices “The function is not continuous within that interval” and “The function is not differentiable within that interval.” There is not necessarily a local maximum or minimum contained in the interval either. That leaves the correct answer choice, “There is a zero between the endpoints of that interval.” If the polynomial is changing signs and meets the requirements for Intermediate Value Theorem, it must cross the axis at some point within the interval.
Example Question #1 : Apply Intermediate Value Theorem
What theorem could you use to show that a polynomial has a root on a given interval?
Mean Value Theorem for Derivatives
Fundamental Theorem of Calculus
Extreme Value Theorem
Intermediate Value Theorem
Intermediate Value Theorem
A polynomial has a zero or root when it crosses the axis. For a given interval , if a and b have different signs (for instance, if is negative and is positive), then by Intermediate Value Theorem there must be a value of zero between and . Therefore, Intermediate Value Theorem is the correct answer.
Example Question #1 : Apply Intermediate Value Theorem
Using the continuous function and the interval , which of the following correctly identifies why the Intermediate Value Theorem is useful?
The Intermediate Value Theorem tells you how many times the function repeats a value as it progresses from to
The Intermediate Value Theorem states that somewhere between and there exists a value , with
The Intermediate Value Theorem can identify the value of that the function takes on as it passes from to
The Intermediate Value Theorem is not useful
The Intermediate Value Theorem states that somewhere between and there exists a value , with
The Intermediate Value Theorem tells us that a value between and exists, but it does not provide any information on what that value is. This eliminates two of the four answer choices - “The Intermediate Value Theorem can identify the value of that the function takes on as it passes from to ” and “The Intermediate Value Theorem tells you how many times the function repeats a value as it progresses from to .”
The Intermediate Value Theorem is useful because it can help identify when there are roots or zeros; an example of this is if a polynomial switches signs, Intermediate Value Theorem tells us there is a zero between those values.
From this, we can conclude that the correct answer is “The Intermediate Value Theorem states that somewhere between and there exists a value , with .”
Example Question #1 : Apply Intermediate Value Theorem
In which interval does have a root?
Graphing on cartesian coordinates reveals that the function is continuous and crosses the axis at a value within the interval .
Furthermore, setting produces a negative value for the function, while setting produces a positive value, as seen below:
Because the function is a polynomial, the function is continuous. By Intermediate Value Theorem, if the function changes signs within this interval, there must be a root present within the interval.
Example Question #3 : Apply Intermediate Value Theorem
In which interval does the function NOT necessarily have a root?
Because the function is a polynomial, the function is continuous. By Intermediate Value Theorem, if the function changes signs within this interval, there must be a root present within the interval.
To apply Intermediate Value Theorem to the function , the function can be evaluated at each of the given bounds.
For instance, if the function is evaluated at and , the following is obtained:
For the intervals , , and , there is a change in sign within the interval.
Because the function does not change in sign within the interval , we cannot conclude by Intermediate Value Theorem whether there is a root contained in the interval or not. Thus, is the correct answer.
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