All Calculus 3 Resources
Example Questions
Example Question #51 : Integration
To integrate, we simply expand the function and integrate:
Example Question #52 : Integration
To solve this problem, we would have to apply u-substitution:
Substituting for u and dx, get us:
The terms cross out and simplifying we get:
We can then 'isolate' the constant:
To integrate , we have to convert it to :
Since the derivative of cos(x) is -sin(x), we would have to apply u-substitution again, but using a different variable to prevent confusion:
Replacing for v and du gets us:
Simplifying get us:
Integrating gets us:
Now substitute v = cos(u) from earlier:
Now substitute u = 2/x from earlier as well and now we get:
Example Question #151 : Calculus Review
We notice that this problem can be solved with a simple u -substitution:
Substituting for u and dx get us:
The terms cross out, and simplifying we get:
Isolating the -1 outside the integral we get:
This is now simply:
Substituting , from earlier gets us our final answer:
Example Question #54 : Integration
This problem can be solved using u-substitution:
Substituting for u and dx in the original integral gets us:
However the factors x+1 and 2x+2 don't cross out, but we can factor 2x+2 to cross out x+1:
Simplifying gets us:
Isolating the 1/2 from the integral gets us:
Substituting from earlier, we now get:
Example Question #55 : Integration
This question can be solved with a simple u- substitution;
Plugging in u and dx in our original integral gets us:
Isolating on the outside, as it is a constant, gets us:
The integration of cos(u) is sin(u)+C:
Substitute back gets us:
Example Question #56 : Integration
This problem can be solved using a u-substitution:
Plugging in u and dx gets us:
The cos(x) factors cross out and simplifying get us:
The integration of is :
Plugging in u = sin(x) from earlier get us our final answer:
Example Question #57 : Integration
This problem can be solved using u-substitution, but instead of crossing out terms, we are manipulating the terms:
Plugging in u and du into the original integral gets us:
Since we cant cross out any terms, we will substitute in terms of u by solving for x:
Now that we found our term in terms of u, we can substitute it in our equation above:
We can now expand and simplify from there:
Then we can integrate from there:
Substituting u = x-1 from earlier gets us:
Example Question #58 : Integration
We notice that the powers of the functions within the numerator and denominator are the same, which means we need to rewrite the function:
We first isolate the any constants to make the problem easier:
We then rewrite the function into though long division or any other method:
Now we integrate each term:
To find, , we apply u-substitution:
Plugging in u and du, we get:
The integral of is , and we get:
Substituting u = x-4 from earlier, we get our final answer:
Example Question #59 : Integration
At first glance, we notice that the tangent power is odd and positive. Since it is odd, we then save a secant-tangent factor and convert the remaining factors to secants:
Ignoring the secant- tangent factor, convert the remaining factors to secant functions:
Using the trig identity, , convert
Now, we are free to use u- substitution at this point:
Substituting u and dx for the above equation, we now get:
We can then cross out the sec(x)tan(x) factor to now get:
Expand and simplify factors:
Using the basic formula , we can now integrate the function:
Now substitute the remaining u's with u = sec(x):
Simplifying, we get:
Example Question #51 : Integration
This question looks extremely difficult without thinking at first, but it is simple problem by breaking it into separate integrals:
We then apply u substitution to each of the two separate integrals. starting with :
Plugging in for u and dx get us:
Isolate constants:
The integration of is :
Plugging in , we now get:
For the second integral, , we also apply u substitution, but using a different variable to avoid confusion:
Plugging y and dy into the integral gets us:
,
which equals:
Plugging in y = x+1, we now get:
Combining two results together gets us our final result: