Remember the general equation of a line in vector form:

, where  is the starting point, and  is the difference between the start and ending points.

Lets apply this to our problem.

Distribute the 

Now we simply do vector addition to get

Finding the angle between two planes requires us to find the angle between their normal vectors.

To obtain normal vectors, we simply take the coefficients in front of .

The (acute) angle between any two vector is

,

Substituting, we have

.

Substituting the components of the line into those of the plane, we have

Substituting this value of  back into the components of the line gives us

.

A quick way to notice the answer is is to notice the planes are parallel (They only differ by the constant on the right side).

Typically though, to find the angle between two planes, we find the angle between their normal vectors.

A vector normal to the first plane is

A vector normal to the second plane is

Then using the formula for the angle between vectors, , we have

.

The equation of a plane is defined as

where  is the normal vector of the plane. 

To find the normal vector, we first get two vectors on the plane 

 and 

and find their cross product. 

The cross product is defined as the determinant of the matrix

Which is

Which tells us the normal vector is 

Using the point  and the normal vector to find the equation of the plane yields

Simplified gives the equation of the plane 

The equation of a plane is defined as

where  is the normal vector of the plane. 

To find the normal vector, we first get two vectors on the plane 

 and 

and find their cross product. 

The cross product is defined as the determinant of the matrix

Which is

Which tells us the normal vector is 

Using the point  and the normal vector to find the equation of the plane yields

Simplified gives the equation of the plane 

Planes that are parallel to each other only differ (if at all) by the constant on the right-hand side (when both sides are simplified). Since has the same coefficients as the given plane, they are parallel to each other.

We can begin by rewriting the expression for the cylinder as follows

.

This tells us that .  Plugging this back into the equation for the plane  to find .

This gives us the representation of the curve of intersection as

.

The equation of a plane is defined as

where 

 is the normal vector of the plane. 

To find the normal vector, we first get two vectors on the plane 

 and 

and find their cross product. 

The cross product is defined as the determinant of the matrix

Which is

Which tells us the normal vector is 

Using the point 

 and the normal vector to find the equation of the plane yields

Simplified gives the equation of the plane 

To find the angle between the planes, we find the angle between their normal vectors.

We have

, for the first plane, and

, for the second plane.

The angle between these two vectors is