We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Calculus 2 : Finding Integrals

Study concepts, example questions & explanations for Calculus 2

Create An Account

All Calculus 2 Resources

9 Diagnostic Tests 308 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #471 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{(9sin(x + 8))}{26})dx\end{align*}$

Possible Answers:

$-\frac{(9cos(x + 8))}{26}$

$-\frac{(288cos(x + 8))}{13}+C$

$-\frac{(9cos(x + 8))}{26}+C$

$-\frac{(288cos(x + 8))}{13}$

Correct answer:

$-\frac{(9cos(x + 8))}{26}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, familiarity with derivative rules}\\&\text{can prove useful. After all, an integral is essentially the}\\&\text{opposite operation of a derivative. Consider how in a derivative}\\&\text{we’d use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside? Integrals, in}\\&\text{similar fashion, entail a division.}\\&\text{Utilizing integral rules:}\\&\int[sin(ax)]=-\frac{cos(ax)}{a}\\&\text{Note in deriving the inside, the lone constant goes to zero.}\\&\int(\frac{(9sin(x + 8))}{26})dx=-\frac{(9cos(x + 8))}{26}+C\\&\text{Now you'll note after integration we add a constant, C. This}\\&\text{is because we're working with an indefinite integral. Note how}\\&\text{if we take the derivative of this function, the constant would}\\&\text{go to zero.}\\&\end{align*}$

Report an Error

Example Question #472 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{2^{(18x)}}{4})dx\end{align*}$

Possible Answers:

$\frac{(9\cdot 2^{(18x)})}{(2ln(2))}$

$\frac{2^{(18x)}}{(72ln(2))}$

$\frac{2^{(18x)}}{(72ln(2))}+C$

$\frac{(9\cdot 2^{(18x)})}{(2ln(2))}+C$

Correct answer:

$\frac{2^{(18x)}}{(72ln(2))}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, familiarity with derivative rules}\\&\text{can prove useful. After all, an integral is essentially the}\\&\text{opposite operation of a derivative. Consider how in a derivative}\\&\text{we’d use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside? Integrals, in}\\&\text{similar fashion, entail a division.}\\&\text{Utilizing integral rules:}\\&\int[b^{ax}]=\frac{b^{ax}}{aln(b)}\\&\text{Note for this problem, the }a\text{ value is } 18\\&\int(\frac{2^{(18x)}}{4})dx=\frac{2^{(18x)}}{(72ln(2))}+C\\&\text{Now you'll note after integration we add a constant, C. This}\\&\text{is because we're working with an indefinite integral. Note how}\\&\text{if we take the derivative of this function, the constant would}\\&\text{go to zero.}\\&\end{align*}$

Report an Error

Example Question #473 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{38}{(45x)})dx\end{align*}$

Possible Answers:

$\frac{(760ln(x))}{9}+C$

$\frac{(760ln(x))}{9}$

$\frac{(38ln(x))}{45}$

$\frac{(38ln(x))}{45}+C$

Correct answer:

$\frac{(38ln(x))}{45}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, familiarity with derivative rules}\\&\text{can prove useful. After all, an integral is essentially the}\\&\text{opposite operation of a derivative. Consider how in a derivative}\\&\text{we’d use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside? Integrals, in}\\&\text{similar fashion, entail a division.}\\&\text{Utilizing integral rules:}\\&\int\frac{a}{u}=aln(u)=ln(u^{a})\\&\text{Note for this problem, the }a\text{ value is } 10\\&\int(\frac{38}{(45x)})dx=\frac{(38ln(x))}{45}+C\\&\text{Now you'll note after integration we add a constant, C. This}\\&\text{is because we're working with an indefinite integral. Note how}\\&\text{if we take the derivative of this function, the constant would}\\&\text{go to zero.}\\&\end{align*}$

Report an Error

Example Question #474 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{(5\cdot 2^{(18x)})}{37})dx\end{align*}$

Possible Answers:

$\frac{(90\cdot 2^{(18x)})}{(37ln(2))}$

$\frac{(90\cdot 2^{(18x)})}{(37ln(2))}+C$

$\frac{(5\cdot 2^{(18x)})}{(666ln(2))}+C$

$\frac{(5\cdot 2^{(18x)})}{(666ln(2))}$

Correct answer:

$\frac{(5\cdot 2^{(18x)})}{(666ln(2))}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, familiarity with derivative rules}\\&\text{can prove useful. After all, an integral is essentially the}\\&\text{opposite operation of a derivative. Consider how in a derivative}\\&\text{we’d use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside? Integrals, in}\\&\text{similar fashion, entail a division.}\\&\text{Utilizing integral rules:}\\&\int[b^{ax}]=\frac{b^{ax}}{aln(b)}\\&\text{Note for this problem, the }a\text{ value is } 18\\&\int(\frac{(5\cdot 2^{(18x)})}{37})dx=\frac{(5\cdot 2^{(18x)})}{(666ln(2))}+C\\&\text{Now you'll note after integration we add a constant, C. This}\\&\text{is because we're working with an indefinite integral. Note how}\\&\text{if we take the derivative of this function, the constant would}\\&\text{go to zero.}\\&\end{align*}$

Report an Error

Example Question #475 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(13\cdot 3^{(16x)})dx\end{align*}$

Possible Answers:

$\frac{(13\cdot 3^{(16x)})}{(16ln(3))}+C$

$\frac{(208\cdot 3^{(16x)})}{ln(3)}+C$

$\frac{(208\cdot 3^{(16x)})}{ln(3)}$

$\frac{(13\cdot 3^{(16x)})}{(16ln(3))}$

Correct answer:

$\frac{(13\cdot 3^{(16x)})}{(16ln(3))}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, familiarity with derivative rules}\\&\text{can prove useful. After all, an integral is essentially the}\\&\text{opposite operation of a derivative. Consider how in a derivative}\\&\text{we’d use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside? Integrals, in}\\&\text{similar fashion, entail a division.}\\&\text{Utilizing integral rules:}\\&\int[b^{ax}]=\frac{b^{ax}}{aln(b)}\\&\text{Note for this problem, the }a\text{ value is } 16\\&\int(13\cdot 3^{(16x)})dx=\frac{(13\cdot 3^{(16x)})}{(16ln(3))}+C\\&\text{Now you'll note after integration we add a constant, C. This}\\&\text{is because we're working with an indefinite integral. Note how}\\&\text{if we take the derivative of this function, the constant would}\\&\text{go to zero.}\\&\end{align*}$

Report an Error

Example Question #476 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{e^{(9x)}}{3}+\frac{ (64x^{10})}{7})dx\end{align*}$

Possible Answers:

$3e^{(9x)} +\frac{ (6400x^{11})}{77}$

$\frac{e^{(9x)}}{27}+\frac{ (64x^{11})}{77}$

$\frac{e^{(9x)}}{27}+\frac{ (64x^{11})}{77}+C$

$3e^{(9x)} +\frac{ (6400x^{11})}{77}+C$

Correct answer:

$\frac{e^{(9x)}}{27}+\frac{ (64x^{11})}{77}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, consider how in a derivative we’d}\\&\text{use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside. Integrals, in}\\&\text{similar fashion, entail a division. Now, although we have two}\\&\text{functions, since they're being added, we integrate separately}\\&\text{and combine the results. This is known as superposition.}\\&\text{Utilizing integral rules:}\\&\int[e^{ax}]=\frac{e^{ax}}{a}\\&\int x^{a}=\frac{x^{a+1}}{a+1}\\&\text{The }a\text{ value for }\frac{e^{(9x)}}{3}\text{ is }9\\&\text{The }a\text{ value for }\frac{(64x^{10})}{7}\text{ is }10\\&\int(\frac{e^{(9x)}}{3}+\frac{ (64x^{10})}{7})dx=\frac{e^{(9x)}}{27}+\frac{ (64x^{11})}{77}+C\\&\text{Now you'll note after integration we add a constant, C, because}\\&\text{we're working with an indefinite integral.}\\&\end{align*}$

Report an Error

Example Question #477 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{3^{(16x)}}{22}+\frac{ 1}{(11x^{11})})dx\end{align*}$

Possible Answers:

$\frac{(8\cdot 3^{(16x)})}{(11ln(3))}-\frac{ 11}{(10x^{10})}+C$

$\frac{(8\cdot 3^{(16x)})}{(11ln(3))}-\frac{ 11}{(10x^{10})}$

$\frac{3^{(16x)}}{(352ln(3))}-\frac{ 1}{(110x^{10})}+C$

$\frac{3^{(16x)}}{(352ln(3))}-\frac{ 1}{(110x^{10})}$

Correct answer:

$\frac{3^{(16x)}}{(352ln(3))}-\frac{ 1}{(110x^{10})}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, consider how in a derivative we’d}\\&\text{use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside. Integrals, in}\\&\text{similar fashion, entail a division. Now, although we have two}\\&\text{functions, since they're being added, we integrate separately}\\&\text{and combine the results. This is known as superposition.}\\&\text{Utilizing integral rules:}\\&\int x^{a}=\frac{x^{a+1}}{a+1}\\&\int[b^{ax}]=\frac{b^{ax}}{aln(b)}\\&\text{The }a\text{ value for }\frac{1}{(11x^{11})}\text{ is }-11\\&\text{The }a\text{ value for }\frac{3^{(16x)}}{22}\text{ is }16\\&\int(\frac{3^{(16x)}}{22}+\frac{ 1}{(11x^{11})})dx=\frac{3^{(16x)}}{(352ln(3))}-\frac{ 1}{(110x^{10})}+C\\&\text{Now you'll note after integration we add a constant, C, because}\\&\text{we're working with an indefinite integral.}\\&\end{align*}$

Report an Error

Example Question #478 : Finding Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{3^{(17x)}}{2}+\frac{ 3}{(7x)})dx\end{align*}$

Possible Answers:

$\frac{(3ln(x))}{7}+\frac{ 3^{(17x)}}{(34ln(3))}+C$

$\frac{(3ln(x))}{7}+\frac{ 3^{(17x)}}{(34ln(3))}$

$\frac{(27ln(x))}{343}+\frac{ (17\cdot 3^{(17x)})}{(2ln(3))}+C$

$\frac{(27ln(x))}{343}+\frac{ (17\cdot 3^{(17x)})}{(2ln(3))}$

Correct answer:

$\frac{(3ln(x))}{7}+\frac{ 3^{(17x)}}{(34ln(3))}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, consider how in a derivative we’d}\\&\text{use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside. Integrals, in}\\&\text{similar fashion, entail a division. Now, although we have two}\\&\text{functions, since they're being added, we integrate separately}\\&\text{and combine the results. This is known as superposition.}\\&\text{Utilizing integral rules:}\\&\int[b^{ax}]=\frac{b^{ax}}{aln(b)}\\&\int\frac{a}{u}=aln(u)=ln(u^{a})\\&\text{The }a\text{ value for }\frac{3^{(17x)}}{2}\text{ is }17\\&\text{The }a\text{ value for }\frac{3}{(7x)}\text{ is }\frac{3}{7}\\&\int(\frac{3^{(17x)}}{2}+\frac{ 3}{(7x)})dx=\frac{(3ln(x))}{7}+\frac{ 3^{(17x)}}{(34ln(3))}+C\\&\text{Now you'll note after integration we add a constant, C, because}\\&\text{we're working with an indefinite integral.}\\&\end{align*}$

Report an Error

Example Question #201 : Indefinite Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{(68cos(x + 9))}{7}+\frac{ 23}{(2x^{7})})dx\end{align*}$

Possible Answers:

$\frac{(5508sin(x + 9))}{7}-\frac{ 1127}{(12x^{6})}$

$\frac{(5508sin(x + 9))}{7}-\frac{ 1127}{(12x^{6})}+C$

$\frac{(68sin(x + 9))}{7}-\frac{ 23}{(12x^{6})}$

$\frac{(68sin(x + 9))}{7}-\frac{ 23}{(12x^{6})}+C$

Correct answer:

$\frac{(68sin(x + 9))}{7}-\frac{ 23}{(12x^{6})}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, consider how in a derivative we’d}\\&\text{use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside. Integrals, in}\\&\text{similar fashion, entail a division. Now, although we have two}\\&\text{functions, since they're being added, we integrate separately}\\&\text{and combine the results. This is known as superposition.}\\&\text{Utilizing integral rules:}\\&\int[cos(ax)]=\frac{sin(ax)}{a}\\&\int x^{a}=\frac{x^{a+1}}{a+1}\\&\text{In deriving the inside of}\frac{(68cos(x + 9))}{7}\text{, the lone constant goes to zero.}\\&\text{The }a\text{ value for }\frac{23}{(2x^{7})}\text{ is }-7\\&\int(\frac{(68cos(x + 9))}{7}+\frac{ 23}{(2x^{7})})dx=\frac{(68sin(x + 9))}{7}-\frac{ 23}{(12x^{6})}+C\\&\text{Now you'll note after integration we add a constant, C, because}\\&\text{we're working with an indefinite integral.}\\&\end{align*}$

Report an Error

Example Question #202 : Indefinite Integrals

$\begin{align*}&\text{Evaluate the indefinite integral: }\\&\int(\frac{sin(6x)}{50}+\frac{ x^{8}}{29})dx\end{align*}$

Possible Answers:

$\frac{(64x^{9})}{261}-\frac{ (3cos(6x))}{25}+C$

$\frac{x^{9}}{261}-\frac{ cos(6x)}{300}+C$

$\frac{(64x^{9})}{261}-\frac{ (3cos(6x))}{25}$

$\frac{x^{9}}{261}-\frac{ cos(6x)}{300}$

Correct answer:

$\frac{x^{9}}{261}-\frac{ cos(6x)}{300}+C$

Explanation:

$\begin{align*}&\text{In performing an integral, consider how in a derivative we’d}\\&\text{use the chain rule to multiply the derivative of the “inside”}\\&\text{of a function by the derivative of the outside. Integrals, in}\\&\text{similar fashion, entail a division. Now, although we have two}\\&\text{functions, since they're being added, we integrate separately}\\&\text{and combine the results. This is known as superposition.}\\&\text{Utilizing integral rules:}\\&\int x^{a}=\frac{x^{a+1}}{a+1}\\&\int[sin(ax)]=-\frac{cos(ax)}{a}\\&\text{The }a\text{ value for }\frac{x^{8}}{29}\text{ is }8\\&\text{The }a\text{ value for }\frac{sin(6x)}{50}\text{ is }6\\&\int(\frac{sin(6x)}{50}+\frac{ x^{8}}{29})dx=\frac{x^{9}}{261}-\frac{ cos(6x)}{300}+C\\&\text{Now you'll note after integration we add a constant, C, because}\\&\text{we're working with an indefinite integral.}\\&\end{align*}$

Report an Error

View Calculus 2 Tutors

Michael
Certified Tutor

University of Richmond, Bachelor of Science, Mathematics. Central Connecticut State University, Master of Arts, Mathematics.

View Calculus 2 Tutors

Jiahao
Certified Tutor

Concordia University, Bachelor, Cell biology .

View Calculus 2 Tutors

Aaron
Certified Tutor

Tulsa Community College, Associate in Science, Mechanical Engineering.

All Calculus 2 Resources

9 Diagnostic Tests 308 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Algebra Tutors in Philadelphia, Spanish Tutors in Houston, GMAT Tutors in Boston, GMAT Tutors in Houston, GRE Tutors in Philadelphia, Chemistry Tutors in Denver, Algebra Tutors in Phoenix, GRE Tutors in Denver, Chemistry Tutors in Los Angeles, Physics Tutors in Seattle

Popular Courses & Classes

LSAT Courses & Classes in Washington DC, GMAT Courses & Classes in Houston, ACT Courses & Classes in Philadelphia, MCAT Courses & Classes in Los Angeles, ISEE Courses & Classes in Houston, GMAT Courses & Classes in San Diego, SAT Courses & Classes in Washington DC, MCAT Courses & Classes in Washington DC, GMAT Courses & Classes in Los Angeles, ISEE Courses & Classes in Seattle

Popular Test Prep

GRE Test Prep in Washington DC, MCAT Test Prep in Boston, GMAT Test Prep in San Diego, GMAT Test Prep in Houston, GMAT Test Prep in Philadelphia, ACT Test Prep in Philadelphia, SSAT Test Prep in Seattle, GRE Test Prep in Atlanta, GMAT Test Prep in Los Angeles, ISEE Test Prep in San Francisco-Bay Area

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Calculus 2 : Finding Integrals

Study concepts, example questions & explanations for Calculus 2

All Calculus 2 Resources

Example Questions

Example Question #471 : Finding Integrals

Example Question #472 : Finding Integrals

Example Question #473 : Finding Integrals

Example Question #474 : Finding Integrals

Example Question #475 : Finding Integrals

Example Question #476 : Finding Integrals

Example Question #477 : Finding Integrals

Example Question #478 : Finding Integrals

Example Question #201 : Indefinite Integrals

Example Question #202 : Indefinite Integrals

All Calculus 2 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: