We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased by 42 percent between January and April, we can solve for this constant of proportionality. Treat the months as their number in the calendar:

$\displaystyle (1+0.42)y_0=y_0e^{k(4-1)}$

$\displaystyle 1.42=e^{3k}$

$\displaystyle 3k=ln(1.42)$

$\displaystyle k=\frac{ln(1.42)}{3}=0.117$

We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased by 100 percent between 4:10 and 4:30, we can solve for this constant of proportionality. Note that units we're asked to use:

$\displaystyle (1+1)y_0=y_0e^{k(20*60)}$

$\displaystyle 2=e^{1200k}$

$\displaystyle 1200k=ln(2)$

$\displaystyle k=\frac{ln(2)}{1200}=0.0006$

We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased by 48 percent between 2014 and 2015, we can solve for this constant of proportionality:

$\displaystyle (1+0.48)y_0=y_0e^{k(2015-2014)}$

$\displaystyle 1.48=e^{k}$

$\displaystyle k=ln(1.48)=0.392$

We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased by 113 percent between 2011 and 2015, we can solve for this constant of proportionality:

$\displaystyle (1+1.13)y_0=y_0e^{k(2015-2011)}$

$\displaystyle 2.13=e^{4k}$

$\displaystyle 4k=ln(2.13)$

$\displaystyle k=\frac{ln(2.13)}{4}=0.189$

We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased by 8 percent between 2013 and 2015, we can solve for this constant of proportionality:

$\displaystyle (1+0.08)y_0=y_0e^{k(2015-2013)}$

$\displaystyle 1.08=e^{2k}$

$\displaystyle 2k=ln(1.08)$

$\displaystyle k=\frac{ln(1.08)}{2}=0.038$

We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased by 148 percent between 2010 and 2015, we can solve for this constant of proportionality:

$\displaystyle (1+1.48)y_0=y_0e^{k(2015-2010)}$

$\displaystyle 2.48=e^{5k}$

$\displaystyle 5k=ln(2.48)$

$\displaystyle k=\frac{ln(2.48)}{5}=0.182$

We're told that the rate of decrease of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population decreased by 33 percent between 2008 and 2015, we can solve for this constant of proportionality:

$\displaystyle (1-0.33)y_0=y_0e^{k(2015-2008)}$

$\displaystyle 0.67=e^{7k}$

$\displaystyle 7k=ln(0.67)$

$\displaystyle k=\frac{ln(0.67)}{7}=-0.057$

We're told that the rate of decrease of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population decreased by 18 percent between 2009 and 2015, we can solve for this constant of proportionality:

$\displaystyle (1-0.18)y_0=y_0e^{k(2015-2009)}$

$\displaystyle 0.82=e^{6k}$

$\displaystyle 6k=ln(0.82)$

$\displaystyle k=\frac{ln(0.82)}{6}=-0.033$

We're told that the rate of decrease of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population decreased by 27 percent between 2003 and 2007, we can solve for this constant of proportionality:

$\displaystyle (1-0.27)y_0=y_0e^{k(2007-2003)}$

$\displaystyle 0.73=e^{4k}$

$\displaystyle 4k=ln(0.73)$

$\displaystyle k=\frac{ln(0.73)}{4}=-0.079$

We're told that the rate of growth of the population is proportional to the population itself, meaning that this problem deals with exponential growth/decay. The population can be modeled thusly:

$\displaystyle p(t)=p_0e^{kt}$

Where $\displaystyle p_0$ is an initial population value, and $\displaystyle k$ is the constant of proportionality.

Since the population increased from 11000  to 17000 between 2012 and 2015, we can solve for this constant of proportionality:

$\displaystyle 17000=11000e^{k(2015-2012)}$

$\displaystyle \frac{17}{11}=e^{3k}$

$\displaystyle 3k=ln(\frac{17}{11})$

$\displaystyle k=\frac{ln(\frac{17}{11})}{3}=0.145$