Calculus 1 : Differential Functions

Study concepts, example questions & explanations for Calculus 1

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Example Questions

Example Question #201 : Other Differential Functions

Find the point on the graph of  where the slope of the tangent line is equal to .

Possible Answers:

The slope of the tangent line never equals .

Correct answer:

Explanation:

To solve this problem, we first need to take the derivative of the function. Then, we will set the derivative equal to  to find the  value where the slope of the tangent line is equal to . Finally, we will plug this  back into the original function to find the corresponding  value. 

We will need the power rule and the derivative of a constant to solve this problem:

Now we set the derivative equal to :

Now that we have the  value where the slope of the tangent line is equal to , we plug that value back into the function to find the  value:

Therefore, the point where the slope of the tangent line is equal to  is 

Example Question #201 : Other Differential Functions

Find the derivative of .

Possible Answers:

Correct answer:

Explanation:

To find this derivative, we need power rule, the derivative of a constant, and the chain rule.

The first thing that we should do is to change the form of the function so that it is written as a power:

Now that it is written as a power, we can use the power rule and chain rule:

Recall these derivative formulas:

In this problem,  and 

 and

Now, combining these two derivatives with multiplication as demonstrated by the chain rule yields:

Example Question #1422 : Calculus

Use implicit differentiation to find  for .

Possible Answers:

Correct answer:

Explanation:

In using implicit differentiation, we need the power rule, the product rule, the chain rule, and the derivative of a constant, and the derivative of the trigonometric function cosine. 

To find the derivative of , we first need the product rule:

In this problem,  and 

To find , we need the power rule, which states:

To find the derivative of , we need the chain rule and the derivative of the trigonometric function cosine which state:

Where  and 

 and  

Combining these results with multiplication as demonstrated by the chain rule yields:

Now that we have  and , we can use the product rule:

 

Now, some algebraic simplification:

Example Question #391 : Functions

Use implicit differentiation to find  for .

Possible Answers:

Correct answer:

Explanation:

To find , we must use the power rule, the derivative of a consant, and the derivative of y.

Then using some algebraic techniques to solve for   :

Example Question #1424 : Calculus

Find the derivative of .

Possible Answers:

Correct answer:

Explanation:

To find this derivative, we need the derivative of a constant, the power rule, the product rule, and the chain rule.

First, let's apply the product rule which states:

 In this problem,  and 

To find the derivative of , we need the power rule and the derivative of a constant which state:

To find the derivative of , we need the chain rule and the power rule which states:

First, let's write  as a power:

Using the chain rule with  and  we obtain:

Using the chain rule, 

 

Now that we have found  and , we can plug these values into the product rule, to obtain:

Example Question #1423 : Calculus

Find the derivative of .

Possible Answers:

Correct answer:

Explanation:

To find this derivative, we need the power rule and the quotient rule.

Using the quotient rule, which states:

In this problem,  and 

To find, we need the power rule which states:

And to find , we also need the power rule.

 

 Now, applying the quotient rule, we obtain:

Then we use algebraic methods to simplify the derivative:

Example Question #1426 : Calculus

Find the derivative of 

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we need the product rule, and the derivatives of the trigonometric functions sine and cotangent.

First, we apply the product rule, which states:

In this problem.  and .

To find , we need the formula for the derivative of sine:

To find the  , we need the derivative of cotangent:

Now, plugging these values into the product rule, we obtain:

And after some simplification:

Example Question #395 : Functions

Find the derivative of 

Possible Answers:

 

Correct answer:

Explanation:

To solve this problem, we need the power rule, the derivative formulas for sine and cosine, and the chain rule.

The chain rule states that:

In this problem, we will have to apply the chain rule twice. This is because the  is inside the sine function which is inside the cosine function.

In this problem, , and we have another function 

For this problem, we are using the chain rule in this form:

To evaluate these derivatives, we need the power rule and the derivatives of sine and cosine which state:

Now, plugging these equations into the chain rule, we obtain:

 

Example Question #396 : Functions

Find the derivative of 

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we need the derivative of a constant, the derivative of the trigonometric function cosine, and the chain rule.

First, let's rewrite the function in terms of a power:

 Now we should apply the chain rule which states that:

In this problem,  and .

To find  we need to use the power rule, which states:

To find  , we again need to use the chain rule, the derivative of a constant, and the derivative of the rtigonometric function cosine to evaluate  , which state that:

 

Plugging all of these equations back into the chain rule, we obtain:

Example Question #1429 : Calculus

Find the derivative of 

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we need the derivative of the trigonometric function cotangent, derivative of a constant, and the quotient rule.

First, let's use the quotient rule, which states:

In this problem,   and  .

To find , we need the formula for the derivative of cotangent which states:

 

To find  we also need the derivative of a constant formula which states:

Now combining these into the quotient rule formula, we obtain:

And after some simplification:

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