Calculus 1 : Calculus

Study concepts, example questions & explanations for Calculus 1

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Example Questions

Example Question #75 : Volume

The region enclosed by the curves  and  is rotated about the line . Using discs and washers, find the volume of the resulting solid.

Possible Answers:

Correct answer:

Explanation:

The intersection points are (0,0) and (1,1). The cross-sectional area is:

 

The volume is therefore:

Example Question #72 : Regions

Finding area under a curve is extremely similar to finding the volume.  The volume of a cylinder is .  When finding the volume of a function rotated around the x-axis, we will look at summing infinitesimal cylinders (disks).  The height of each of these cylinders is , the radius of the cylinder is the function since given any x value, f(x) is the distance from the x-axis to the curve.  Thus if we want to find the volume of a function f(x) between [a,b] that is rotated about the x-axis we simply use the equation .

Find the volume of the solid obtained from rotating the function  about the x-axis and bounded by the y-axis and .

Possible Answers:

Correct answer:

Explanation:

The bounds are  since it is bounded by the y-axis and the line  and the function is .  

Therefore the equation is 

.  

This gives us the answer of 

.

Example Question #1 : How To Find Area Of A Region

What is the average value of the function f(x) = 12x3 + 15x + 5 on the interval [3, 6]?

Possible Answers:

771

895.67

1302.5

1542

1350.2

Correct answer:

1302.5

Explanation:

To find the average value, we must take the integral of f(x) between 3 and 6 and then multiply it by 1/(6 – 3) = 1/3.

The indefinite form of the integral is: 3x4 + 7.5x2 + 5x

The integral from 3 to 6 is therefore: (3(6)4 + 7.5(6)2 + 5(6)) - (3(3)4 + 7.5(3)2 + 5(3)) = (3888 + 270 + 30) – (243 + 22.5 + 15) = 3907.5

The average value is 3907.5/3 = 1302.5

Example Question #1 : Area

Find the dot product of a = <2,2,-1> and b = <5,-3,2>.

Possible Answers:
0
3
2
-3
-2
Correct answer: 2
Explanation:

To find the dot product, we multiply the individual corresponding components and add.  

Here, the dot product is found by:

2 * 5 + 2 * (-3) + (-1) * 2 = 2.

Example Question #1 : Area

Find the area of the region enclosed by the parabola  and the line 

Possible Answers:

Correct answer:

Explanation:

The limits of the integration are found by solving   and  for :





The region runs from  to . The limits of the integration are ,
The area between the curves is:



Example Question #3991 : Calculus

Find 

Possible Answers:

Correct answer:

Explanation:

Example Question #3992 : Calculus

Find 

Possible Answers:

Correct answer:

Explanation:

Example Question #4 : Area

What is the area of the space below  and above 

Possible Answers:

Correct answer:

Explanation:

 is only above  over the interval .  Areas are given by the definite integral of each function and 

 

The area between the curves is found by subtracting the area between each curve and the -axis from each other.  For  this area is  and for  the area is  giving an area between curves of 

Example Question #5 : Area

What is the area below  and above the -axis?

Possible Answers:

Correct answer:

Explanation:

To find the area below a curve, you must find the definite integral of the function.  In this case the limits of integration are where the original function intercepts the -axis at  and .  So you must find  which is  evaluated from  to .  This gives an answer of 

Example Question #6 : Area

Find the area between the curves  and .

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we first need to find the point where the two equations are equal.  Doing this we find that

 .  

From this, we see that the two graphs are equal at  and .  We also know that for is greater than .  

So to find the area between these curves we need to evaluate the integral .  

The solution to the integral is

.

Evaluating this at  and  we get

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