Biochemistry : Biochemistry

Study concepts, example questions & explanations for Biochemistry

varsity tutors app store varsity tutors android store

Example Questions

Example Question #1 : Transferases And Kinases

Which of the following is false about cyclin-dependent kinases (Cdks)?

Possible Answers:

In yeast cells, one Cdk protein regulates the cell cycle.

Cdk activity rises as mitosis starts.

Cdk binds to a single cyclin throughout the entire cell cycle.

Vertebrate cells have four types of Cdks.

Cylcin proteins control the activity of Cdks.

Correct answer:

Cdk binds to a single cyclin throughout the entire cell cycle.

Explanation:

One of the features of the beginning of mitosis, and various steps in the cell cycle, is the increase of cyclin activity. This cyclin controls the action of Cdk, causing changes in the phosphorylation of proteins, influencing cell cycle events. Yeast cells use one Cdk, which changes cyclin throughout the cycle, while vetrebrate cells use four -- -Cdk,  /S-Cdk, S-Cdk, and M-Cdk. No matter the species, however, Cdk binds to various cyclins over the course of a cell's life.

Example Question #1 : Hydrolases

Lysosomal enzymes are predominantly __________.

Possible Answers:

decarboxylases

kinases

hydrolases

isomerases

oxidases

Correct answer:

hydrolases

Explanation:

The lysosome is the "stomach" of the cell. It contains many hydrolytic enzymes to digest and recycle the monomers used to form old polymers. Remember the opposite of dehydration/condensation synthesis is hydrolysis. Hydrolysis reactions use water to break bonds in polymers, yielding monomers that can be recycled and reused in anabolic pathways.

Example Question #12 : Protein Structure And Functions

Which of the following best describes how a lysozyme works?

Possible Answers:

It cuts a polysaccharide relatively slowly, facilitating a random, spontaneous collision between water and the sugar, with little intervention.

It cuts the bond in a polysaccharide, by holding six sugars in a row in its active site, and adding a water molecule, causing hydrolysis.

It is responsible for the cleaving of amino acid chains via the ping-pong mechanism.

It cleaves the phosphodiester bond in nucleic acids, via hydrolysis.

It hydrolyzes bonds in lipids, causing a split in a fatty acid chain.

Correct answer:

It cuts the bond in a polysaccharide, by holding six sugars in a row in its active site, and adding a water molecule, causing hydrolysis.

Explanation:

Lysozymes speed up by many times the hydrolysis of polysaccharides, by adding the water molecule to sugars linked in its enzyme-substrate complex. If left alone without the lysozyme, this hydrolysis would occur relatively infrequently, because it requires a large activation energy which would be supplied only by rare random collisions. The amino acid cleavage enzyme which uses the ping-pong mechanism is chymotrypsin. The enzyme which breaks nucleic acid phosophodiester bonds is phosphodiesterase. Fats are hydrolyzed by lipases, not lysozymes.

Example Question #12 : Protein Structure And Functions

Phosphoglucomutase is an enzyme seen in glycogen breakdown. It is responsible for converting glucose-1-phosphate () to glucose-6-phosphate ().  

Based on this action, to which enzyme class does phosphoglucomutase belong?

Possible Answers:

Ligase

Oxidoreductase

Isomerase

Lyase

Correct answer:

Isomerase

Explanation:

Phosphoglucomutase is responsible for altering the position of the phosphate on the glucose from the "1" position to the "6" position. However, notice how the molecular formula for the product and the substrate are the same. Enzymes that rearrange the structure of a molecule in this manner are referred to as isomerase enzymes.

Example Question #1 : Protein Functions

Which of the following correctly mentions the function of a common eukaryotic ligase?

Possible Answers:

Convert pyruvate into acetyl-coenzyme A

Convert adenosine to adenine and ribose in the presence of water

Catalyze the conversion of glucose-6-phosphate into fructose-6-phosphate 

Transfer amino groups from an amino acid to an alpha-keto acid

Join lagging strands (Okazaki fragments) of DNA during replication 

Correct answer:

Join lagging strands (Okazaki fragments) of DNA during replication 

Explanation:

Mammalian DNA ligase I has this function, and there are other DNA ligases which perform it in other animals and eukaryotes (prokaryotes also have their own DNA ligases). All the other functions mentioned are done by other classes of enzymes, not ligases (i.e. hydrolases, aminotransferases, oxidoreductases, etc.).

Example Question #21 : Macromolecule Structures And Functions

Which of the following lists the cytoskeletal filaments in order of increasing diameter?

Possible Answers:

Intermediate filaments < actin filaments < microtubules

Microtubules < intermediate filaments < actin filaments

Actin filaments < microtubules < intermediate filaments

Actin filaments < intermediate filaments < microtubules

Microtubules < actin filaments < intermediate filaments

Correct answer:

Actin filaments < intermediate filaments < microtubules

Explanation:

Actin filaments, also known as microfilaments, are flexible and bundle up, and are 5-9nm in diameter. Intermediate filaments, which can strengthen cells, are about 10nm. Microtubules, rigid and attached on one end to a centrosome, are 25nm.

Example Question #1 : Transport Proteins

How does an increase in carbon dioxide affect oxygen transport in hemoglobin?

Possible Answers:

Hemoglobin will have a lower oxygen affinity, which means that subunit cooperation will be lost

Hemoglobin will have a lower oxygen affinity, which allows for a greater release of oxygen into tissue

Hemoglobin will have greater oxygen affinity, which allows more oxygen to be carried

Hemoglobin will have a greater oxygen affinity, which allows for a greater release of oxygen into tissue

Correct answer:

Hemoglobin will have a lower oxygen affinity, which allows for a greater release of oxygen into tissue

Explanation:

A high carbon dioxide concentration will decrease the pH and produce the Bohr effect. These conditions will cause a slight conformational change in hemoglobin that results in a lower oxygen binding affinity. However, since the partial pressure of oxygen in the lungs in so high, most of the available oxygen will be loaded on to the hemoglobin anyway. Since the oxygen affinity is lowered, the hemoglobin will release the oxygen more freely, resulting in a greater oxygen to load in tissue. Functioning hemoglobin always has four cooperative subunits.

Example Question #2 : Transport Proteins

Which of the following steps list in chronological order, the creation of a transport vesicle from a membrane via clathrin coating?

Possible Answers:

The clathrin coat is assembled, the membrane buds out, the vesicle forms, the clathrin coat is disassembled, dynamin pinches the vesicle

The clathrin coat is assembled, the membrane buds out, the vesicle forms, dynamin pinches the vesicle, the clathrin coat is disassembled

The vesicle forms, dynamin pinches the vesicle, the clathrin coat is assembled, the clathrin coat is disassembled, the membrane buds out

The membrane buds out, the clathrin coat is assembled, the vesicle forms, dynamin pinches the vesicle, the clathrin coat is disassembled

The membrane buds out, the vesicle forms, dynamin pinches the vesicle, the clathrin coat is assembled, the clathrin coat is disassembled

Correct answer:

The clathrin coat is assembled, the membrane buds out, the vesicle forms, dynamin pinches the vesicle, the clathrin coat is disassembled

Explanation:

The process of creating transport vesicles via clathrin coats proceeds in distinct steps. Before any budding occurs of the membrane, clathrin attaches to it, bound to adaptin which is attached to a transmembranal cargo receptor. (Cargo molecules are what trigger the creation of the vesicle in the first place.) The clathrin coating is believed to cause the membrane to bud. After the vesicle forms, dynamin uses GTP to pinch the vesicle off, and it is only then that the clathrin coat disassembles and we have a transport vesicle.

Example Question #2 : Transport Proteins

Which of the following lists these molecules in order of increasing permeability to a lipid bilayer?

Possible Answers:

Carbon dioxide, water, glucose, sodium ion

Glucose, carbon dioxide, water, sodium ion

Glucose, carbon dioxide, sodium ion, water

Sodium ion, glucose, carbon dioxide, water

Sodium ion, glucose, water, carbon dioxide

Correct answer:

Sodium ion, glucose, water, carbon dioxide

Explanation:

Charged molecules do not permeate the lipid bilayer easily at all. So despite its small size, among our choices, a sodium ion passes least easily through. Polar molecules also have a hard (but less difficult) time passing through, and the larger the molecule, the harder that becomes, so after the sodium ion comes glucose, followed by water, which is polar but much smaller. Small, hydrophobic molecules -- such as carbon dioxide -- diffuse through most easily, because they can pass through the longest (hydrophobic) part of the membrane.

Example Question #1 : Transport Proteins

Which type of transport does not require a protein?

Possible Answers:

Passive transport

Osmosis

Facilitated diffusion

Active transport

Correct answer:

Osmosis

Explanation:

There are two types of transport: passive transport and active transport. Active transport requires an expenditure of energy and a protein pump. Passive transport includes simple diffusion and facilitated diffusion. Diffusion is the movement of a substance from an area of high concentration to one of low concentration. Simple diffusion is the name for the diffusion process which does not require a protein; facilitated diffusion is the name for the diffusion process which requires a carrier protein for transport. Osmosis is the simple diffusion of water and thus does not require protein.

Learning Tools by Varsity Tutors